Problem 6
Question
Determine whether each function is a one-to-one function. If it is one-to-one, list the inverse function by switching coordinates, or inputs and outputs. \(f=\\{(-1,-1),(1,1),(0,2),(2,0)\\}\)
Step-by-Step Solution
Verified Answer
The function is one-to-one, and its inverse is \(f^{-1} = \{(-1, -1), (1, 1), (2, 0), (0, 2)\}\).
1Step 1: Understanding One-to-One Functions
A one-to-one function, also known as an injective function, is a function for which every element in the domain corresponds to a unique element in the range. In other words, no two different elements in the domain of the function should map to the same element in the co-domain. Thus, we need to check that each input (the first number in each pair) maps to a unique output (the second number in each pair).
2Step 2: Check for Unique Outputs
Examine the given function: \( f = \{(-1,-1),(1,1),(0,2),(2,0)\}\)- For \(-1\), the output is \(-1\).- For \(1\), the output is \(1\).- For \(0\), the output is \(2\).- For \(2\), the output is \(0\).Since no two different inputs produce the same output, the function is one-to-one.
3Step 3: Switch Inputs and Outputs
To find the inverse function, switch each pair’s coordinates (input and output). For the set \(f\):- \((-1, -1)\) becomes \((-1, -1)\).- \((1, 1)\) becomes \((1, 1)\).- \((0, 2)\) becomes \((2, 0)\).- \((2, 0)\) becomes \((0, 2)\).Thus, the inverse function is given by the set \(f^{-1} = \{(-1, -1), (1, 1), (2, 0), (0, 2)\}\).
4Step 4: Validate the Inverse Function
To ensure correctness, check that after swapping, each new input still maps to a unique new output. Each coordinate pair in the set \(f^{-1}\) does not repeat any output for different inputs, confirming it remains a function.
Key Concepts
Inverse FunctionUnique OutputInjective Function
Inverse Function
An inverse function is like a reverse gear for mathematical functions. It allows you to go backward from the output back to the input. Imagine walking down a path using a map, and then retracing your steps exactly using the same path every time.
In mathematical terms, if you have a function \( f(x) \), its inverse is denoted as \( f^{-1}(x) \).
They have this special relationship: when you apply \( f \) and then \( f^{-1} \), you should end up where you started. Mathematically, this is written as:
This gives us new sets of pairs, forming what we call the inverse function. Each input now becomes an output, forming a sort of mirror image of the original function.
In mathematical terms, if you have a function \( f(x) \), its inverse is denoted as \( f^{-1}(x) \).
They have this special relationship: when you apply \( f \) and then \( f^{-1} \), you should end up where you started. Mathematically, this is written as:
- \( f(f^{-1}(x)) = x \)
- \( f^{-1}(f(x)) = x \)
This gives us new sets of pairs, forming what we call the inverse function. Each input now becomes an output, forming a sort of mirror image of the original function.
Unique Output
The concept of unique output is a cornerstone of understanding one-to-one or injective functions.
In any function, you should think of it as a matching activity. Each input from the domain must correspond to just one output in the range. If you feed in a specific input, you should always get back the same output.
This is what it means for an output to be unique:
In any function, you should think of it as a matching activity. Each input from the domain must correspond to just one output in the range. If you feed in a specific input, you should always get back the same output.
This is what it means for an output to be unique:
- Different inputs should never lead to the same output
- Each pair of input-output is distinct and doesn't repeat the output for different inputs
- For input \(-1\), the output is \(-1\)
- For input \(1\), the output is \(1\)
- For input \(0\), the output is \(2\)
- For input \(2\), the output is \(0\)
Injective Function
Injective functions are a major category of functions, and are sometimes referred to as one-to-one functions.
These functions have the property that no two different inputs in their domain produce the same output in their codomain. Thus, injective functions are all about ensuring every input has an individual and unique output.
Thinking about injectivity is quite like thinking about putting keys into locks. Each key (input) opens exactly one lock (output), and each lock is only opened by one key.
These functions have the property that no two different inputs in their domain produce the same output in their codomain. Thus, injective functions are all about ensuring every input has an individual and unique output.
Thinking about injectivity is quite like thinking about putting keys into locks. Each key (input) opens exactly one lock (output), and each lock is only opened by one key.
- An injective function will never "recycle" its output for different inputs.
- This ensures the possibility of finding a valid inverse function.
- \(-1\) maps uniquely to \(-1\)
- \(1\) maps uniquely to \(1\)
- \(0\) maps uniquely to \(2\)
- \(2\) maps uniquely to \(0\)
Other exercises in this chapter
Problem 6
Use a calculator to approximate each logarithm to four decimal places. $$ \ln 3 $$
View solution Problem 6
For the functions \(f\) and \(g\), find a. \((f+g)(x)\), b. \((f-g)(x), c .(f \cdot g)(x)\), and d. \(\left(\frac{f}{g}\right)(x)\). $$ f(x)=\sqrt[3]{x} ; g(x)=
View solution Problem 6
Graph each exponential function. $$ y=\left(\frac{1}{5}\right)^{x} $$
View solution Problem 6
Write each sum as a single logarithm. Assume that variables represent positive numbers. $$ \log _{5} y^{3}+\log _{5}(y-7) $$
View solution