Problem 6
Question
Determine the radius of convergence of the given power series. $$\sum_{n=0}^{\infty} \frac{5^{n} x^{n}}{n !}$$
Step-by-Step Solution
Verified Answer
The radius of convergence for the given power series \(\sum_{n=0}^{\infty} \frac{5^{n} x^{n}}{n !}\) is infinity, as the power series converges for any value of x.
1Step 1: Apply the Ratio Test
The Ratio Test is defined as \(\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|\), where a_n represents the terms in the series. We can write the given power series as a_n = \(\frac{5^n x^n}{n!}\) and a_{n+1} = \(\frac{5^{n+1} x^{n+1}}{(n+1)!}\).
Step 2: Compute the limit
2Step 2: Compute the limit
Next, we need to compute the limit of the Ratio Test as n approaches infinity: \(\limits_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|\). We have \(\frac{a_{n+1}}{a_n} = \frac{ \frac{5^{n+1} x^{n+1}}{(n+1)!} }{ \frac{5^n x^n}{n!} } \).
Step 3: Simplify the expression
3Step 3: Simplify the expression
We now simplify the expression: \(\frac{ \frac{5^{n+1} x^{n+1}}{(n+1)!} }{ \frac{5^n x^n}{n!} } = \frac{5^{n+1}x^{n+1}}{(n+1)!} \cdot \frac{n!}{5^n x^n} = \frac{5x(n!)}{(n+1)!}\).
Step 4: Compute the limit
4Step 4: Compute the limit
Compute the limit as n approaches infinity: \(\lim_{n \to \infty} \left| \frac{5x(n!)}{(n+1)!} \right|\).
Observe that (n+1)! is equivalent to (n+1)n!. The expression becomes: \(\lim_{n \to \infty} \left| \frac{5x}{n+1} \right|\).
Step 5: Determine the criterion for convergence
5Step 5: Determine the criterion for convergence
According to the Ratio Test, if the absolute value of the limit is less than 1, the series converges. In this case, we need to determine when \(\left| \frac{5x}{n+1} \right| < 1\). Since n tends to infinity, the limit is clearly 0, and 0 is less than 1. Therefore, the condition for convergence is met for all x.
Step 6: State the radius of convergence
6Step 6: State the radius of convergence
Since the series converges for all x, the radius of convergence is infinity. This means that the power series converges for any value of x.
Key Concepts
Understanding Power SeriesExploring the Ratio TestDiving into Infinite Series
Understanding Power Series
A power series is a type of infinite series where each term is a power of a variable (often denoted as \(x\)). The general form of a power series is:
The range of \(x\) values for which a power series converges is determined by its radius of convergence. This radius specifies the interval around a central point where the series behaves nicely and sums up to a finite value. Beyond this interval, the series may diverge, making it ineffective for calculations involving those \(x\) values.
- \(\sum_{n=0}^{\infty} a_n x^n\), where \(a_n\) represents the coefficients of each term.
The range of \(x\) values for which a power series converges is determined by its radius of convergence. This radius specifies the interval around a central point where the series behaves nicely and sums up to a finite value. Beyond this interval, the series may diverge, making it ineffective for calculations involving those \(x\) values.
Exploring the Ratio Test
The Ratio Test is a pivotal method in determining the convergence of series, particularly power series. To apply the Ratio Test, we consider the terms of the series denoted as \(a_n\). For a series to pass the Ratio Test:
- Calculate \(\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|\).
- If the limit is less than 1, the series converges.
- If the limit is greater than 1, the series diverges.
- If the limit equals 1, the test is inconclusive.
Diving into Infinite Series
Infinite series extend the concept of a series into a sum with an endless number of terms. They are written in the form \(\sum_{n=0}^{\infty} a_n\), which indicates that terms keep adding infinitely.
Infinite series can either converge to a finite value or diverge depending on their terms’ nature.
Convergence is crucial as it implies that the series approaches a particular value as more terms are added. For power series, convergence may occur across certain intervals, defined by the radius of convergence.
Understanding infinite series can be enhanced by testing methods like the Ratio Test, which specifically help in ascertaining convergence properties. Finite sums are straightforward, but as we deal with infinitely many terms, these tests become essential to determine the behaviour of the series and ensure the series is useful for practical calculations.
Infinite series can either converge to a finite value or diverge depending on their terms’ nature.
Convergence is crucial as it implies that the series approaches a particular value as more terms are added. For power series, convergence may occur across certain intervals, defined by the radius of convergence.
Understanding infinite series can be enhanced by testing methods like the Ratio Test, which specifically help in ascertaining convergence properties. Finite sums are straightforward, but as we deal with infinitely many terms, these tests become essential to determine the behaviour of the series and ensure the series is useful for practical calculations.
Other exercises in this chapter
Problem 6
Determine the roots of the indicial equation of the given differential equation. $$x^{2} y^{\prime \prime}+x(1-x) y^{\prime}-7 y=0$$
View solution Problem 6
(a) By making the change of variables \(t=x^{2}\) in the integral that defines the gamma function, show that $$ \Gamma(1 / 2)=2 \int_{0}^{\infty} e^{-x^{2}} d x
View solution Problem 7
Determine whether \(x=0\) is an ordinary point or a regular singular point of the given differential equation. Then obtain two linearly independent solutions to
View solution Problem 7
Determine the roots of the indicial equation of the given differential equation. $$4 x^{2} y^{\prime \prime}+x e^{x} y^{\prime}-y=0$$
View solution