Problem 6
Question
Describe the graph of \(x=z^{2}\) in \(\mathbb{R}^{3}\).
Step-by-Step Solution
Verified Answer
Describe the graph of the equation \(x=z^2\) in \(\mathbb{R}^3\).
The graph of the equation \(x=z^2\) in \(\mathbb{R}^3\) represents a parabolic surface extending infinitely along the y-axis. The surface has a "U" shape, with its vertex at the origin (0,0,0) and opening in the positive x-direction. The graph is symmetrical with respect to the z-axis, as any point on the surface has coordinates (z^2, y, z), where both y and z can be any real value.
1Step 1: Understand the given equation in 3D space
Given the equation \(x=z^2\), we are in a 3-dimensional space, with x, y, and z as the coordinates. The equation does not involve the y-coordinate, which means that our graph will not depend on the value of y; it can be any real number. Therefore, the graph will extend infinitely along the y-axis.
2Step 2: Analyze and visualize x and z relationship
The equation given is \(x=z^2\). From this equation, we can see that the z-coordinate is squared, and that determines the x-coordinate. This means that, for every positive value of z, there will be a corresponding value of x. In addition, since z is squared, the value of x will never be negative.
To visualize this graph properly, suppose we slice the space with a plane parallel to the xz-plane at a particular y-coordinate. Each of these slices will show the graph of the equation \(x=z^2\) in 2-dimensional space. The graph in 2D space would look like the graph of a quadratic function opening to the right.
3Step 3: Describe the 3D graph
Considering the full 3-dimensional space, the graph of the equation \(x=z^2\) would look like a parabolic or a "U" shaped surface that extends infinitely along the y-axis. To be more specific, any point on this surface has the coordinates (z^2, y, z) where both y and z can take any real value. The surface will be symmetrical with respect to the z-axis since squaring z will result in the same value for x, regardless of the sign of z.
In summary, the graph of the equation \(x=z^2\) in \(\mathbb{R}^3\) represents a parabolic surface extending infinitely along the y-axis, with its vertex at the origin (0,0,0) and opening in the positive x-direction, symmetrical with respect to the z-axis.
Other exercises in this chapter
Problem 6
Explain how to approximate the change in a function \(f\) when the independent variables change from \((a, b)\) to \((a+\Delta x, b+\Delta y)\)
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The level curves of the surface \(z=x^{2}+y^{2}\) are circles in the \(x y\) -plane centered at the origin. Without computing the gradient, what is the directio
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Explain how to graph the level curves of a surface \(z=f(x, y)\).
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