Problem 6
Question
Convert the following Kelvin temperatures to the Celsius and Fahrenheit scales: (a) the midday temperature at the surface of the moon \((400 \mathrm{K}) ;\) (b) the temperature at the tops of the clouds in the atmosphere of Saturn \((95 \mathrm{K}) ;(\mathrm{c})\) the temperature at the center of the sun \(\left(1.55 \times 10^{7} \mathrm{K}\right)\) .
Step-by-Step Solution
Verified Answer
400 K: 126.85 °C, 260.33 °F; 95 K: -178.15 °C, -288.67 °F; 1.55 × 10⁷ K: 1.54997 × 10⁷ °C, 2.78995 × 10⁷ °F.
1Step 1: Understand the Kelvin to Celsius Conversion
The equation to convert a temperature from Kelvin to Celsius is given by: \[ T_{\text{Celsius}} = T_{\text{Kelvin}} - 273.15 \] This equation allows you to subtract the constant 273.15 from a temperature given in Kelvin to find the equivalent temperature in Celsius.
2Step 2: Convert 400 K to Celsius
Using the equation from Step 1, convert 400 K to Celsius as follows:\[ T_{\text{Celsius}} = 400 - 273.15 = 126.85 \, \text{°C} \] Thus, 400 K is equivalent to 126.85 °C.
3Step 3: Convert 400 K to Fahrenheit
First, convert the Kelvin temperature to Celsius using Step 1, then use the formula to convert Celsius to Fahrenheit:\[ T_{\text{Fahrenheit}} = \frac{9}{5}T_{\text{Celsius}} + 32 \] Apply this to the Celsius temperature from Step 2:\[ T_{\text{Fahrenheit}} = \frac{9}{5} \times 126.85 + 32 = 260.33 \, \text{°F} \]Thus, 400 K is equivalent to 260.33 °F.
4Step 4: Convert 95 K to Celsius
Convert 95 K to Celsius using the Kelvin to Celsius formula:\[ T_{\text{Celsius}} = 95 - 273.15 = -178.15 \, \text{°C} \] So, 95 K is equivalent to -178.15 °C.
5Step 5: Convert 95 K to Fahrenheit
First, convert the Kelvin temperature to Celsius using Step 4, then convert Celsius to Fahrenheit:\[ T_{\text{Fahrenheit}} = \frac{9}{5} \times (-178.15) + 32 = -288.67 \, \text{°F} \] Thus, 95 K is equivalent to -288.67 °F.
6Step 6: Convert 1.55 × 10⁷ K to Celsius
Use the Kelvin to Celsius conversion formula for a large number:\[ T_{\text{Celsius}} = 1.55 \times 10^7 - 273.15 = 1.549972685 \times 10^7 \, \text{°C} \] So, 1.55 × 10⁷ K is equivalent to approximately 1.549972685 × 10⁷ °C.
7Step 7: Convert 1.55 × 10⁷ K to Fahrenheit
Convert the Celsius temperature from Step 6 to Fahrenheit:\[ T_{\text{Fahrenheit}} = \frac{9}{5} \times 1.549972685 \times 10^7 + 32 = 2.789950833 \times 10^7 \, \text{°F} \] Thus, 1.55 × 10⁷ K is approximately 2.789950833 × 10⁷ °F.
Key Concepts
Kelvin to CelsiusKelvin to FahrenheitPhysics Problem SolvingCelsius to FahrenheitThermodynamic Temperature Scales
Kelvin to Celsius
The Kelvin to Celsius conversion is straightforward. We use the formula:
For example, 400 K translates into 126.85 °C as shown in the solution. Simply subtract 273.15 from the given temperature in Kelvin.
This conversion is commonly used in scientific fields because Kelvin is the SI unit for temperature, but Celsius is more familiar in everyday contexts.
- \[ T_{\text{Celsius}} = T_{\text{Kelvin}} - 273.15 \]
For example, 400 K translates into 126.85 °C as shown in the solution. Simply subtract 273.15 from the given temperature in Kelvin.
This conversion is commonly used in scientific fields because Kelvin is the SI unit for temperature, but Celsius is more familiar in everyday contexts.
Kelvin to Fahrenheit
To convert Kelvin to Fahrenheit, first convert Kelvin to Celsius, then Celsius to Fahrenheit. The full conversion is:
This two-step process ensures accuracy by leveraging the familiar Celsius to Fahrenheit formula.
- Use: \[ T_{\text{Celsius}} = T_{\text{Kelvin}} - 273.15 \]
- Then apply: \[ T_{\text{Fahrenheit}} = \frac{9}{5}T_{\text{Celsius}} + 32 \]
This two-step process ensures accuracy by leveraging the familiar Celsius to Fahrenheit formula.
Physics Problem Solving
Physics problems often require converting temperatures across different scales. Understanding conversion formulas is vital.
Start by identifying the units provided and required. Apply the appropriate equations in sequence.
Simplicity is key:
Start by identifying the units provided and required. Apply the appropriate equations in sequence.
Simplicity is key:
- Use Kelvin for calculations related to physical laws due to its absolute nature.
- Convert to Celsius or Fahrenheit for readability or specific requirements.
Celsius to Fahrenheit
Celsius and Fahrenheit are both common temperature scales. Their conversion helps in practical applications:
For example, 126.85 °C converts to 260.33 °F. Always perform calculations carefully to avoid mistakes in conversion, especially with decimals.
Remember, accurate conversions are essential for exact science applications.
- The formula is: \[ T_{\text{Fahrenheit}} = \frac{9}{5}T_{\text{Celsius}} + 32 \]
For example, 126.85 °C converts to 260.33 °F. Always perform calculations carefully to avoid mistakes in conversion, especially with decimals.
Remember, accurate conversions are essential for exact science applications.
Thermodynamic Temperature Scales
Thermodynamic temperature scales, like Kelvin and Rankine, are essential in scientific measurements. Kelvin is an absolute scale starting at absolute zero, the minimum theoretical temperature.
It’s pivotal in scientific fields like physics and chemistry due to its direct ties with energy calculations.
Key points:
It’s pivotal in scientific fields like physics and chemistry due to its direct ties with energy calculations.
Key points:
- Kelvin avoids negative numbers by setting absolute zero as 0 K.
- Celsius, familiar in everyday life, is offset by 273.15 degrees from Kelvin.
Other exercises in this chapter
Problem 4
\(\cdot\) Inside the earth and the sun. (a) Geophysicists have esti- mated that the temperature at the center of the earth's core is \(5000^{\circ} \mathrm{C}\)
View solution Problem 5
(a) At what temperature do the Fahrenheit and Celsius scales coincide? (b) Is there any temperature at which the Kelvin and Celsius scales coincide?
View solution Problem 7
\(\cdot\) The Eiffel Tower in Paris is 984 ft tall and is made mostly of steel. If this is its height in winter when its temperature is \(-8.00^{\circ} \mathrm{
View solution Problem 9
\(\cdot\) A metal rod is 40.125 \(\mathrm{cm}\) long at \(20.0^{\circ} \mathrm{C}\) and 40.148 \(\mathrm{cm}\) long at \(45.0^{\circ} \mathrm{C} .\) Calculate t
View solution