Problem 6
Question
Choosing a Formula In Exercises \(5-14\) , select the basic integration formula you can use to find the integral, and identify \(u\) and \(a\) when appropriate. $$ \int \frac{2 t+1}{t^{2}+t-4} d t $$
Step-by-Step Solution
Verified Answer
The integral \(\int \frac{2t+1}{t^{2}+t-4} dt\) can be solved using the formula \(\int \frac{f'}{f} dt=\ln |f| + C\), with \(u = t^2 + t - 4\) and \(a = 1\), and results in \(\ln |t^2 + t - 4| + C\).
1Step 1: Identify the Formula
The integral has the form \(\int \frac{f'}{f} dt\), where \(f' = 2t+1\) and \(f = t^{2}+t-4\). The integral can therefore be solved using the formula \(\int \frac{f'}{f} dt = \ln |f| + C\) .
2Step 2: Identify u and a
Here, the variable \(u\) can be identified as \(u=t^2 +t - 4\) as it is the function at the denominator, and \(a = 1\) as there is no scaling factor for \(u\) in the integral.
3Step 3: Apply the Formula
Applying the formula from step 1 using the identifications from step 2 results in the following integral: \(\int \frac{2t+1}{t^2 + t - 4} dt = \ln |t^2 + t - 4| + C\).
Key Concepts
Basic Integration FormulaIntegration by SubstitutionLogarithmic Integration
Basic Integration Formula
The basic integration formula is a cornerstone of calculus. It helps us to solve integrals of functions that fit certain standard forms.
For example, the integral \[\int \frac{f'}{f} \, dt \]can be solved using the basic logarithmic integration, yielding:\[\ln |f| + C\]where \(C\) is the constant of integration. This is particularly useful when the integrand is the derivative of its denominator.
In the given exercise, we have:
For example, the integral \[\int \frac{f'}{f} \, dt \]can be solved using the basic logarithmic integration, yielding:\[\ln |f| + C\]where \(C\) is the constant of integration. This is particularly useful when the integrand is the derivative of its denominator.
In the given exercise, we have:
- Numerator \(f' = 2t+1\)
- Denominator \(f = t^{2}+t-4\)
Integration by Substitution
Integration by substitution is akin to the reverse of differentiating using the chain rule.
This method simplifies integration by replacing a variable with another to make the problem easier. In many cases, this involves identifying a function and its derivative in the integral, which helps in substituting variables effectively.
This method simplifies integration by replacing a variable with another to make the problem easier. In many cases, this involves identifying a function and its derivative in the integral, which helps in substituting variables effectively.
- In our exercise, identifying \(f = t^2 + t - 4\) helps us see the structure of the integral.
- This allows us to set \(u = t^2 + t - 4\).
- Since \(f' = 2t+1\) matches the numerator, substitution can proceed seamlessly.
Logarithmic Integration
Logarithmic integration is a specific technique used when integrating rational functions, particularly when the form fits \(\frac{f'}{f}\).
This method results in expressions that are natural logarithms due to the derivative-numerator structure. In simpler terms, if the derivative of the denominator is present in the numerator, the integral can be easily expressed using logarithms:
This method results in expressions that are natural logarithms due to the derivative-numerator structure. In simpler terms, if the derivative of the denominator is present in the numerator, the integral can be easily expressed using logarithms:
- Here, \(\int \frac{2t+1}{t^{2}+t-4} dt\) fits perfectly into this form.
- We use the basic formula \(\ln |f| + C\).
Other exercises in this chapter
Problem 6
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