Problem 6
Question
Both earth and moon are subject to the gravitational force of the sun. As observed from the sun, the orbit of the moon \(\quad\) [NCERT Exemplar] (a) will be elliptical (b) will not be strictly elliptical because the total gravitational force on it is not central (c) is not elliptical but will necessarily be a closed curve (d) deviates considerably from being elliptical due to influence of planets other than earth
Step-by-Step Solution
Verified Answer
(b) The orbit will not be strictly elliptical due to non-central forces.
1Step 1: Understanding the Problem Context
The problem involves understanding the movement of the Moon as observed from the Sun. The Moon is subject to the gravitational force of both the Earth and the Sun. Our task is to determine how the orbit of the Moon appears.
2Step 2: Analyzing Gravitational Forces
Consider the gravitational forces acting on the Moon. The most significant forces are those from the Earth (as the Moon's primary) and the Sun. The Moon's motion is primarily governed by its interactions with these two bodies.
3Step 3: Evaluating the Motion of the Moon Relatively to the Sun
The Moon orbits the Earth while the Earth orbits the Sun. This dual motion leads to a more complex path when observed from the Sun. The orbit of the Moon around the Sun will not be a simple ellipse, because of the superimposed Earth-Moon system's movement.
4Step 4: Analyzing the Influence of Non-Central Gravitational Forces
Since the gravitational force from the Earth is significant and non-negligible, the total gravitational force acting on the Moon is not central with respect to the Sun alone. This means that the force doesn't point towards a fixed center (the Sun) resulting in non-elliptical motion.
5Step 5: Conclusion Based on Analysis
Considering the analysis in previous steps, the correct answer must consider the non-strictly central nature of the forces involved. Hence, while the Moon's path is a closed curve due to periodic orbits, it cannot be strictly elliptical solely from the Sun's perspective.
Key Concepts
Orbit of the MoonElliptical OrbitsNon-Central ForcesCelestial Mechanics
Orbit of the Moon
The orbit of the Moon is a fascinating phenomenon that involves complex motions. Observing the Moon's path from the Sun, we see that it does not follow a simple elliptical orbit. This is because the Moon, Earth, and Sun are in constant motion with respect to each other.
- The Moon revolves around the Earth.
- The Earth orbits the Sun.
Elliptical Orbits
Elliptical orbits are paths followed by celestial bodies due to gravity. These orbits are not perfect circles; they are slightly stretched round shapes. Johannes Kepler, a famous astronomer, was the first to describe planetary motion in these terms.
- An ellipse is defined by its two foci, with the center of mass at one of these points.
- Planets in our solar system, including Earth, follow elliptical orbits around the Sun.
Non-Central Forces
Non-central forces are forces that do not always point towards a single center of mass. In the case of the Moon’s movement, these forces play a crucial role.
- The Earth's gravity is a significant force acting on the Moon, influencing its path.
- Similarly, the Sun exerts its gravitational pull, further affecting movement.
Celestial Mechanics
Celestial mechanics is the branch of astronomical science dedicated to studying the movements of celestial bodies under the influence of gravitational forces. This field combines physics and mathematics to describe how planets, moons, and stars move through space.
- It explains how gravitational interactions cause bodies like the Moon to follow complex paths.
- It uses the laws of motion to predict future positions and paths of celestial objects.
Other exercises in this chapter
Problem 4
Imagine a light planet revolving around a very massive star in a circular orbit of radius \(r\) with a period of revolution \(T\). If the gravitational force of
View solution Problem 6
Linear acceleration for rolling, \(a=\frac{g \sin \theta}{\sqrt{1+\frac{K^{2}}{R^{2}}}}\) For cylinder, \(\frac{K^{2}}{R^{2}}=\frac{1}{2}\) \(\therefore \quad a
View solution Problem 6
The work that must be done in lifting a body of weight \(P\) from the surface of the earth to a height \(h\) is (a) \(\frac{P R h}{R-h}\) (b) \(\frac{R+h}{P R h
View solution Problem 7
Different points in earth are at slightly different distances from the sun and hence experience different forces due to gravitation. For a rigid body, we know t
View solution