Problem 6
Question
A \(10 \mathrm{~L}\) cylinder of nitrogen at \(4.0\) atm pressure and \(27^{\circ} \mathrm{C}\) developed a leak. When the leak was repaired \(2.36\) atm of nitrogen remained in the cylinder still at \(27^{\circ} \mathrm{C}\). How many grams of nitrogen escaped ? (a) \(18.7 \mathrm{~g}\) (b) \(0.67 \mathrm{~g}\) (c) \(52.6 \mathrm{~g}\) (d) \(10.0 \mathrm{~g}\)
Step-by-Step Solution
Verified Answer
18.7 g of nitrogen escaped, option (a).
1Step 1: Use Ideal Gas Law to Find Initial Moles
The ideal gas law is given by \( PV = nRT \). First, we calculate the initial amount of moles \( n_1 \) in the cylinder using the initial conditions: \( P_1 = 4.0 \) atm, \( V = 10 \) L, and \( T = 27^{\circ}C = 300 \) K. The ideal gas constant \( R \) is \( 0.0821 \) L·atm/(mol·K).\[ n_1 = \frac{P_1 V}{RT} = \frac{4.0 \times 10}{0.0821 \times 300} \approx 1.63 \]
2Step 2: Use Ideal Gas Law for Final Moles
Next, find the moles of nitrogen \( n_2 \) remaining after the leak using the final pressure \( P_2 = 2.36 \) atm but with the same volume and temperature.\[ n_2 = \frac{P_2 V}{RT} = \frac{2.36 \times 10}{0.0821 \times 300} \approx 0.961 \]
3Step 3: Calculate Moles Escaped
Subtract the moles remaining \( n_2 \) from the initial moles \( n_1 \) to find the moles of nitrogen that escaped.\[ n_{\text{escaped}} = n_1 - n_2 = 1.63 - 0.961 = 0.669 \]
4Step 4: Convert Moles Escaped to Grams
Using the molar mass of nitrogen gas (\( N_2 \)), which is \( 28 \text{ g/mol} \), convert the moles of nitrogen that escaped into grams.\[ ext{grams escaped} = n_{\text{escaped}} \times 28 = 0.669 \times 28 \approx 18.732 \]
5Step 5: Determine Correct Answer
The calculated mass of nitrogen that escaped is approximately \( 18.7 \) g. This matches with option (a).
Key Concepts
Moles CalculationNitrogen GasGas LeaksChemical Problem-Solving
Moles Calculation
Understanding moles calculation is crucial in solving chemical problems. The number of moles is a measure of how many molecules are in a given amount of substance. It is represented by the formula from the ideal gas law:
- \( PV = nRT \), where:
- \( P \) is pressure in atmospheres
- \( V \) is volume in liters
- \( n \) is the number of moles
- \( R \) is the ideal gas constant (\ 0.0821 L·atm/(mol·K)
- \( T \) is temperature in Kelvin
Nitrogen Gas
Nitrogen gas, symbolized as \( N_2 \), is a diatomic molecule that is colorless, odorless, and makes up about 78% of the Earth's atmosphere. Here are some key points about nitrogen gas:
- It is essential for life, as it is a major component of amino acids and proteins.
- Nitrogen gas has a molar mass of 28 g/mol, which is useful for converting between moles and grams when solving chemical problems.
- It behaves as an ideal gas under many conditions commonly found in textbook problems.
Gas Leaks
Gas leaks may seem like a challenging concept, but understanding them is vital for safety and calculations in chemistry. When a gas leaks from a container:
- The number of molecules within the container decreases, leading to changes in pressure.
- The volume and temperature may remain constant, which simplifies the use of the ideal gas law in calculations.
Chemical Problem-Solving
Chemical problem-solving involves applying scientific principles to find solutions. In the exercise, multiple skills were combined to solve the problem of the escaping nitrogen gas. Here's a breakdown of the approach:
- Understanding the properties of the involved substances, like nitrogen gas.
- Applying the ideal gas law to establish relationships between pressure, volume, and temperature to calculate moles.
- Utilizing stoichiometry to convert between different units, such as moles to grams.
- Critical analysis of the problem to ensure each step accurately reflects the chemical principles involved.
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