Problem 6
Question
\(5-12\) . Factor out the common factor. $$ -3 b+12 $$
Step-by-Step Solution
Verified Answer
Factorization is \(3(-b + 4)\).
1Step 1: Identify the Common Factor
Look at the coefficients and terms of the expression, \(-3b + 12\). The common factor in both terms is \(3\), as \(-3\) and \(12\) are both divisible by \(3\).
2Step 2: Factor Out the Common Factor
Factor \(3\) out of each term. Divide each term by \(3\): \(-3b \div 3 = -b\) and \(12 \div 3 = 4\).The expression becomes \(3(-b + 4)\).
3Step 3: Check the Factorization
Distribute the common factor back into the expression to ensure accuracy: \(3(-b + 4) = 3(-b) + 3(4) = -3b + 12\). Since the result matches the original expression, the factorization is correct.
Key Concepts
Common FactorAlgebraic ExpressionsDistributive Property
Common Factor
When working with algebraic expressions, one of the simplest yet most powerful techniques is factoring out the common factor. In essence, a common factor is a number or variable that is shared by all terms within an expression. This is important because it helps simplify complex expressions and solve equations more easily.
For instance, in the expression \(-3b + 12\), we look for a number that divides both \(-3b\) and \(12\). Here, the number is \(3\), as both \(-3\) and \(12\) can be divided evenly by \(3\).
For instance, in the expression \(-3b + 12\), we look for a number that divides both \(-3b\) and \(12\). Here, the number is \(3\), as both \(-3\) and \(12\) can be divided evenly by \(3\).
- Understanding what a common factor is involves looking at the coefficients (the numbers in front of variables) and identifying the largest number that can divide each one without a remainder.
- This is useful in simplifying expressions and making calculations more manageable.
Algebraic Expressions
Algebraic expressions are mathematical phrases that can include numbers, variables, and operators such as addition, subtraction, multiplication, and division. They are used extensively in algebra to describe relationships, patterns, and real-world situations.
In the exercise we're analyzing, the expression \(-3b + 12\) is an algebraic expression. Breaking it down:
In the exercise we're analyzing, the expression \(-3b + 12\) is an algebraic expression. Breaking it down:
- \(-3b\) is a term consisting of a coefficient \(-3\) and a variable \(b\).
- \(12\) is a constant term, which is just a number without a variable.
Distributive Property
The distributive property is a fundamental principle in algebra that allows us to multiply a single term across terms inside a parenthesis. It is expressed as \(a(b + c) = ab + ac\). This property can be applied in reverse when factoring out a common factor.
When we factor the expression \(-3b + 12\), we use the distributive property to "factor out" \(3\), leading to the expression \(3(-b + 4)\). Here’s how this works:
When we factor the expression \(-3b + 12\), we use the distributive property to "factor out" \(3\), leading to the expression \(3(-b + 4)\). Here’s how this works:
- You take the common factor \(3\) and place it outside the parenthesis.
- Then you divide each term inside the expression by \(3\), resulting in a simplified expression \((-b + 4)\) inside the parenthesis.
Other exercises in this chapter
Problem 5
When we raise a power to a new power, we _____ the exponents. So \(\left(3^{4}\right)^{2}=\) _____.
View solution Problem 6
True or false? (a) \(\frac{1}{2}+\frac{1}{x}\) is the same as \(\frac{1}{2+x}\) (b) \(\frac{1}{2}+\frac{1}{x}\) is the same as \(\frac{x+2}{2 x}\)
View solution Problem 6
The Special Product Formula for the “sum and difference of the same terms” is \((A+B)(A-B)=\) _______. So \((5+x)(5-x)=\) _________.
View solution Problem 6
Find the missing power in the following calculation: \(5^{1 / 3} \cdot 5=5 .\)
View solution