Problem 6
Question
\(3-12\) . Write the form of the partial fraction decomposition of the function (as in Example 4 ). Do not determine the numerical values of the coefficients. $$ \frac{1}{x^{4}-x^{3}} $$
Step-by-Step Solution
Verified Answer
The partial fraction decomposition is \(\frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3} + \frac{D}{x-1}\).
1Step 1: Factor the Denominator
The first step is to factor the denominator of the given function. The denominator is \(x^4 - x^3\). Factor out the greatest common factor, which is \(x^3\), resulting in: \[ x^4 - x^3 = x^3(x-1) \]
2Step 2: Set Up Partial Fraction Decomposition
Given the factored form \(x^3(x-1)\), write the expression for partial fractions. Since \(x^3\) is a repeated factor, each form (\(x\), \(x^2\), \(x^3\)) needs a separate term. The factor \(x-1\) is a simple linear factor. Therefore, the partial fraction decomposition is:\[ \frac{1}{x^3(x-1)} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3} + \frac{D}{x-1} \]
Key Concepts
Rational FunctionsFactoring PolynomialsRepeated Factors
Rational Functions
Rational functions are a type of function that represent the ratio of two polynomials. These functions can be expressed in the form \(\frac{P(x)}{Q(x)}\), where \(P(x)\) and \(Q(x)\) are polynomials and \(Q(x)eq0\). This formula defines a relationship between two polynomial expressions, indicating how one changes in response to changes in the other.
It's important to understand that the behavior of rational functions is dictated by their numerators and denominators.
It's important to understand that the behavior of rational functions is dictated by their numerators and denominators.
- The numerator \(P(x)\) controls the zeros of the function, or where the function equals zero.
- The denominator \(Q(x)\) determines the function's asymptotes, or where the function is undefined (these are the *singularities*).
Factoring Polynomials
Factoring polynomials is a crucial skill for determining a rational function's behavior. It involves breaking down a polynomial into simpler polynomials that, when multiplied together, produce the original polynomial.
For example, in the provided problem, the denominator \(x^4 - x^3\) is factored by pulling out the greatest common factor, which is \(x^3\). This simplifies the problem significantly, transforming it into \(x^3(x-1)\).
Understanding how to factor polynomials effectively helps in:
For example, in the provided problem, the denominator \(x^4 - x^3\) is factored by pulling out the greatest common factor, which is \(x^3\). This simplifies the problem significantly, transforming it into \(x^3(x-1)\).
Understanding how to factor polynomials effectively helps in:
- Finding the zeros of the polynomial, which correspond to the function's x-intercepts or roots.
- Simplifying the rational function for easier integration or differentiation.
- Preparing the function for partial fraction decomposition by identifying repeated factors and handling each separately.
Repeated Factors
Repeated factors in polynomials are factors that appear more than once. In the context of partial fraction decomposition, it's important to address each of these factors separately.
In our exercise, \(x^3\) is a repeated factor, which means we need to account for each power of \(x\) up to the highest occurrence, in this case, \(x^3\). This results in individual terms for each occurrence:
Repeated factors can increase the algebraic complexity, but by breaking them down, we transform the rational function into more manageable parts, thus simplifying further mathematical operations.
In our exercise, \(x^3\) is a repeated factor, which means we need to account for each power of \(x\) up to the highest occurrence, in this case, \(x^3\). This results in individual terms for each occurrence:
- \(\frac{A}{x}\)
- \(\frac{B}{x^2}\)
- \(\frac{C}{x^3}\)
Repeated factors can increase the algebraic complexity, but by breaking them down, we transform the rational function into more manageable parts, thus simplifying further mathematical operations.
Other exercises in this chapter
Problem 6
\(3-8=\) Use the substitution method to find all solutions of the system of equations. $$ \left\\{\begin{aligned} x^{2}+y &=9 \\ x-y+3 &=0 \end{aligned}\right.
View solution Problem 6
State the dimension of the matrix. $$ \left[\begin{array}{rrrr}{-1} & {5} & {4} & {0} \\ {0} & {2} & {11} & {3}\end{array}\right] $$
View solution Problem 6
Calculate the products \(A B\) and \(B A\) to verify that \(B\) is the inverse of \(A .\) $$ A=\left[\begin{array}{rrr}{3} & {2} & {4} \\ {1} & {1} & {-6} \\ {2
View solution Problem 6
Determine whether the matrices \(A\) and \(B\) are equal. $$ A=\left[\begin{array}{cc}{\frac{1}{4}} & {\ln 1} \\ {2} & {3}\end{array}\right] \quad B=\left[\begi
View solution