Problem 6
Question
1-8 Find \(\sin 2 x, \cos 2 x,\) and \(\tan 2 x\) from the given information. \(\sec x=2, \quad x\) in quadrant \(\mathrm{IV}\)
Step-by-Step Solution
Verified Answer
\( \sin 2x = -\frac{\sqrt{3}}{2} \), \( \cos 2x = -\frac{1}{2} \), \( \tan 2x = \sqrt{3} \).
1Step 1: Identify Given Information and Needed Formulas
We know that \( \sec x = 2 \), which means \( \cos x = \frac{1}{2} \) because \( \sec x = \frac{1}{\cos x} \). Since \( x \) is in quadrant IV, \( \cos x \) is positive and \( \sin x \) is negative. To find the double angle identities, we'll need the formulas: \[ \sin 2x = 2 \sin x \cos x \]\[ \cos 2x = \cos^2 x - \sin^2 x \]\[ \tan 2x = \frac{2 \tan x}{1 - \tan^2 x} \]
2Step 2: Determine \( \sin x \) Using Trigonometric Identity
Use the identity \( \sin^2 x + \cos^2 x = 1 \) to find \( \sin x \): \[ \sin^2 x + \left( \frac{1}{2} \right)^2 = 1 \] \[ \sin^2 x + \frac{1}{4} = 1 \] \[ \sin^2 x = \frac{3}{4} \] Since \( x \) is in quadrant IV, \( \sin x \) is negative, thus:\[ \sin x = -\sqrt{\frac{3}{4}} = -\frac{\sqrt{3}}{2} \]
3Step 3: Calculate \( \sin 2x \)
Now substitute \( \sin x = -\frac{\sqrt{3}}{2} \) and \( \cos x = \frac{1}{2} \) into the double angle formula for sine:\[ \sin 2x = 2 \sin x \cos x = 2 \left(-\frac{\sqrt{3}}{2}\right) \left(\frac{1}{2}\right) = -\frac{\sqrt{3}}{2} \]
4Step 4: Calculate \( \cos 2x \)
Use the double angle formula for cosine:\[ \cos 2x = \cos^2 x - \sin^2 x = \left(\frac{1}{2}\right)^2 - \left(-\frac{\sqrt{3}}{2}\right)^2 \] \[ = \frac{1}{4} - \frac{3}{4} = -\frac{1}{2} \]
5Step 5: Calculate \( \tan 2x \)
Find \( \tan x \) first:\[ \tan x = \frac{\sin x}{\cos x} = \frac{-\frac{\sqrt{3}}{2}}{\frac{1}{2}} = -\sqrt{3} \] Then use the double angle formula for tangent:\[ \tan 2x = \frac{2 \tan x}{1 - \tan^2 x} = \frac{2(-\sqrt{3})}{1 - (-\sqrt{3})^2} = \frac{-2\sqrt{3}}{1 - 3} = \frac{-2\sqrt{3}}{-2} = \sqrt{3} \]
Key Concepts
Double Angle FormulasTrigonometric FunctionsQuadrants in Trigonometry
Double Angle Formulas
Double angle formulas are important tools in trigonometry that allow you to express trigonometric functions of double angles, such as \(2x\), in terms of trigonometric functions of single angles \(x\). These formulas are particularly useful for simplifying trigonometric expressions and solving equations. The three primary double angle formulas are for sine, cosine, and tangent:
- \(\sin 2x = 2 \sin x \cos x\)
- \(\cos 2x = \cos^2 x - \sin^2 x\)
- \(\tan 2x = \frac{2 \tan x}{1 - \tan^2 x}\)
Trigonometric Functions
Trigonometric functions are mathematical functions that relate the angles of a triangle to the lengths of its sides. The primary trigonometric functions are sine (\(\sin\)), cosine (\(\cos\)), and tangent (\(\tan\)). These functions are pivotal in the study of periodic phenomena such as waves and oscillations. Each of these functions has a reciprocal:
- Cosecant (\(\csc\)), the reciprocal of sine, calculated as \(\csc x = \frac{1}{\sin x}\).
- Secant (\(\sec\)), the reciprocal of cosine, seen as \(\sec x = \frac{1}{\cos x}\).
- Cotangent (\(\cot\)), the reciprocal of tangent, calculated using \(\cot x = \frac{1}{\tan x}\).
Quadrants in Trigonometry
In trigonometry, the coordinate plane is divided into four distinct quadrants, with each quadrant affecting the signs of the trigonometric functions differently. Quadrant I includes positive x and y values, Quadrant II has negative x and positive y, Quadrant III includes negative x and y values, and Quadrant IV has positive x and negative y values.
- In Quadrant I, all trigonometric functions are positive.
- In Quadrant II, sine is positive, while cosine and tangent are negative.
- In Quadrant III, tangent is positive, while sine and cosine are negative.
- In Quadrant IV, cosine is positive, whereas sine and tangent are negative.
Other exercises in this chapter
Problem 6
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