Problem 59
Question
Use slopes to show that \(A(1,1), B(11,3), \quad G(10,8),\) and \(D(0,6)\) are vertices of a rectangle.
Step-by-Step Solution
Verified Answer
The slopes show AB || DG, indicating possible rectangle setup, check diagonal lengths for complete proof.
1Step 1: Calculate Slope of AB
To find the slope of line segment AB, use the formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \). Substituting the coordinates of A(1,1) and B(11,3), we get: \( m = \frac{3 - 1}{11 - 1} = \frac{2}{10} = \frac{1}{5} \). So, the slope of AB is \( \frac{1}{5} \).
2Step 2: Calculate Slope of BD
Using the formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \) for B(11,3) and D(0,6), we have: \( m = \frac{6 - 3}{0 - 11} = \frac{3}{-11} = -\frac{3}{11} \). Thus, the slope of BD is \( -\frac{3}{11} \).
3Step 3: Calculate Slope of DG
Use the coordinates D(0,6) and G(10,8) in the slope formula: \( m = \frac{8 - 6}{10 - 0} = \frac{2}{10} = \frac{1}{5} \). So, the slope of DG is \( \frac{1}{5} \).
4Step 4: Calculate Slope of GA
Using G(10,8) and A(1,1), the slope is: \( m = \frac{1 - 8}{1 - 10} = \frac{-7}{-9} = \frac{7}{9} \). Hence, the slope of GA is \( \frac{7}{9} \).
5Step 5: Compare Slopes
In a rectangle, opposite sides are parallel (equal slopes), and adjacent sides are perpendicular (negative reciprocal slopes). Compare the slopes calculated:- Slopes of AB and DG are both \( \frac{1}{5} \), indicating they are parallel.- Slopes of BD and GA are \(-\frac{3}{11}\) and \(\frac{7}{9}\) respectively, which are not negative reciprocals. However, if calculated correctly the vector products should turn up parallel lines and perpendicular diagonals for a complete check.To confirm these sides shape a rectangle, additional checks could ensure diagonals bisect perpendicularly or have equal lengths (not provided in calculated examples).
6Step 6: Conclusion
Given the slopes for opposite sides are equal (AB || DG) and if checked, any perpendicularity or equal diagonals suggest the arrangement specifies a rectangle. The unintended variance may occur from vertices mislabelled or additional geometric proof like diagonal checks is needed.
Key Concepts
Slope FormulaParallel LinesPerpendicular LinesGeometry Proof
Slope Formula
The slope formula helps us determine the "steepness" of a line. In coordinate geometry, the slope is useful for understanding how two points are related in space. Let's dive into the formula:
- The slope formula is
m = \frac{y_2 - y_1}{x_2 - x_1} - "m" represents the slope of the line through points \((x_1, y_1)\) and \((x_2, y_2)\).
- This formula calculates the change in y-coordinates compared to the change in x-coordinates.
Parallel Lines
Parallel lines are lines in a plane that never meet. They have the exact same slope. In geometry, this concept is vital to establish shapes like rectangles and parallelograms.
- For lines to be parallel, their slopes must be equal.
- Using the slope of line segments, such as AB and DG, both having a slope of \( \frac{1}{5} \), confirms that these two lines are parallel.
Perpendicular Lines
Perpendicular lines add depth to understanding geometry, especially when establishing right angles. For lines to be perpendicular:
- Their slopes are negative reciprocals of each other.
- If one line has a slope of \(m\), then the perpendicular line's slope should be \(-\frac{1}{m}\).
Geometry Proof
A geometry proof, using slopes and line properties, provides a solid foundation in verifying shapes like rectangles.
- Start by calculating slopes of all sides to check for parallelism and perpendicularism.
- Confirm using slopes if opposite sides are parallel and adjacent sides are perpendicular.
- No extra measurement is needed other than coordinate points.
Other exercises in this chapter
Problem 58
\(55-58\) m Find all real solutions of the equation, rounded to two decimals. $$ x^{4}=16-x^{3} $$
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\(55-62\) . Find an equation of the circle that satisfies the given conditions. Center \((-1,5) ; \quad\) passes through \((-4,-6)\)
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\(59-66\) . Find the solutions of the inequality by drawing appropriate graphs. State each answer rounded to two decimals. $$ x^{2} \leq 3 x+10 $$
View solution Problem 59
\(55-62\) . Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are \(P(-1,1)\) and \(Q(5,9)\)
View solution