Problem 59
Question
Unique solution Assume that \(f\) is continuous on \([a, b]\) and differentiable on \((a, b) .\) Also assume that \(f(a)\) and \(f(b)\) have opposite signs and that \(f^{\prime} \neq 0\) between \(a\) and \(b .\) Show that \(f(x)=0\) exactly once between \(a\) and \(b .\)
Step-by-Step Solution
Verified Answer
Given conditions ensure exactly one root in \((a, b)\).
1Step 1: Understand the Intermediate Value Theorem (IVT)
The Intermediate Value Theorem states that if a function \( f \) is continuous on a closed interval \([a, b]\) and \( N \) is any number between \( f(a) \) and \( f(b) \), then there exists at least one number \( c \) in the interval \((a, b)\) such that \( f(c) = N \). Given that \( f(a) \) and \( f(b) \) have opposite signs, this means that 0 lies between \( f(a) \) and \( f(b) \), thus there exists some \( c \) where \( f(c) = 0 \).
2Step 2: Use Bolzano's Theorem
Bolzano's Theorem is a special case of the Intermediate Value Theorem that concludes if a continuous function changes sign over an interval, there is a root in the interval. Since \( f(a) \) and \( f(b) \) have opposite signs, \( f(x) = 0 \) must have at least one root in \((a, b)\).
3Step 3: Establish Uniqueness Using Differentiability
Since \( f \) is differentiable and \( f'(x) eq 0 \) everywhere in the interval \((a, b)\), the function does not have a horizontal tangent, and it cannot have multiple zero crossings within \( (a, b) \). If there were two distinct roots, by Rolle's Theorem, \( f'(x) = 0 \) at some point between the roots, contradicting our assumption that \( f'(x) eq 0 \) throughout \((a, b)\).
4Step 4: Conclusion
Since \( f(x) \) is continuous and \( f(a) \) and \( f(b) \) are of opposite signs, there is at least one root within \((a, b)\). Further, the condition that \( f'(x) eq 0 \) ensures that there cannot be more than one root. Therefore, \( f(x) = 0 \) exactly once on the interval \((a, b)\).
Key Concepts
Bolzano's TheoremRolle's TheoremDifferentiabilityContinuous Functions
Bolzano's Theorem
Bolzano's Theorem is an essential concept in mathematics that helps us understand when a function has a root in a specific interval. This theorem is a more focused version of the Intermediate Value Theorem (IVT). Bolzano's Theorem specifically deals with continuous functions over a closed interval where the function values at the endpoints have opposite signs. Let's break it down:
- The function must be continuous on the interval [a, b]. This means there should be no breaks, jumps, or holes in the graph of the function within this interval.
- There should be a sign change between f(a) and f(b), meaning if one is positive, the other must be negative.
Rolle's Theorem
Rolle's Theorem is a fascinating result in calculus relating to differentiable functions. It gives conditions under which a function must have a horizontal tangent line between two points where the function values are equal:
- The function must be differentiable across the open interval (a, b).
- The endpoints of the interval must satisfy \( f(a) = f(b) \).
- The function should be continuous over the closed interval [a, b].
Differentiability
Differentiability is a key concept in calculus that informs us about the behavior of a function. When we say a function is differentiable on an interval, we mean:
- A derivative exists at each point within that interval.
- The function is smooth and has no sharp corners or cusps in the interval.
Continuous Functions
Understanding continuous functions is crucial for solving problems involving theorems like Bolzano's and Rolle's. A function is continuous on an interval if:
- There are no breaks, jumps, or gaps in the function within that interval.
- For every value \( x \) in the interval, the value of the function approaches \( f(x) \) as closely as desired from both sides.
Other exercises in this chapter
Problem 59
In Exercises 59 and \(60,\) give reasons for your answers. Let $$ f(x)=(x-2)^{2 / 3} $$ $$ \begin{array}{l}{\text { a. Does } f^{\prime}(2) \text { exist? }} \\
View solution Problem 59
a. Find the local extrema of each function on the given interval, and say where they occur. b. Graph the function and its derivative together. Comment on the be
View solution Problem 60
Production level Suppose that \(c(x)=x^{3}-20 x^{2}+20,000 x\) is the cost of manufacturing \(x\) items. Find a production level that will minimize the average
View solution Problem 60
Verify the formulas in Exercises 57-62 by differentiation. $$\int \csc ^{2}\left(\frac{x-1}{3}\right) d x=-3 \cot \left(\frac{x-1}{3}\right)+C$$
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