Problem 59
Question
To estimate the height of a mountain above a level plain, the angle of elevation to the top of the mountain is measured to be \(32^{\circ} .\) One thousand feet closer to the mountain along the plain, it is found that the angle of elevation is \(35^{\circ} .\) Estimate the height of the mountain.
Step-by-Step Solution
Verified Answer
The mountain is approximately 1797 feet high.
1Step 1: Understanding the Problem
We need to find the height of a mountain by using trigonometric methods given two angles of elevation and a horizontal distance between them.
2Step 2: Drawing the Diagram
Visualize the scenario with two right triangles. Place two observation points on the horizontal ground with known distance apart, and measure angles of elevation from these points to the top of the mountain.
3Step 3: Defining Variables and Known Values
Let \(h\) be the height of the mountain. Let \(d_1\) be the distance from the first point to the mountain and \(d_2 = d_1 + 1000\) ft be the distance from the second point. The angles given are \(32^{\circ}\) and \(35^{\circ}\).
4Step 4: Using Trigonometric Functions
For the first triangle, \(\tan(32^{\circ}) = \frac{h}{d_2}\). For the second triangle, \(\tan(35^{\circ}) = \frac{h}{d_1}\). These equations represent the tangent of the angles in terms of \(h\) and the distances.
5Step 5: Setting Up Equations
From \(\tan(32^{\circ}) = \frac{h}{d_2}\), we have \(h = d_2 \cdot \tan(32^{\circ})\). From \(\tan(35^{\circ}) = \frac{h}{d_1}\), we have \(h = d_1 \cdot \tan(35^{\circ})\).
6Step 6: Equating and Solving for Distances
Set \(d_2 \cdot \tan(32^{\circ}) = d_1 \cdot \tan(35^{\circ})\). Since \(d_2 = d_1 + 1000\), substitute and solve for \(d_1\).
7Step 7: Calculate \(d_1\)
\((d_1 + 1000) \cdot \tan(32^{\circ}) = d_1 \cdot \tan(35^{\circ})\). This simplifies to calculate \(d_1\).
8Step 8: Determine the mountain height
Use the determined \(d_1\) to find \(h = d_1 \cdot \tan(35^{\circ})\) or \(h = (d_1 + 1000) \cdot \tan(32^{\circ})\).
Key Concepts
Angle of ElevationTangent FunctionRight TriangleHeight Estimation
Angle of Elevation
The **Angle of Elevation** is a useful concept when estimating the height of an object, like a mountain, from a distance. Imagine standing at a certain point and looking up towards the peak of a mountain. The angle formed between the line of sight—drawn straight from the eye to the mountain top—and the horizontal ground line is called the angle of elevation.
In our problem, two angles of elevation are considered: one observed from a point 1000 feet closer to the mountain and another from a more distant point. These angles measure at 32° and 35°, respectively. A larger angle of elevation usually indicates closer proximity in a horizontal direction. By using these angles, we can determine unknown heights using trigonometric functions effectively.
In our problem, two angles of elevation are considered: one observed from a point 1000 feet closer to the mountain and another from a more distant point. These angles measure at 32° and 35°, respectively. A larger angle of elevation usually indicates closer proximity in a horizontal direction. By using these angles, we can determine unknown heights using trigonometric functions effectively.
Tangent Function
Trigonometry inherently involves relationships between angles and sides of triangles, especially right triangles. The **Tangent Function** is one such relationship. In a right triangle, the tangent of an angle is the ratio of the length of the opposite side to the length of the adjacent side.
If we denote the height of the mountain as \(h\) and the horizontal distances from the points of observations as \(d_1\) and \(d_2\), then:
If we denote the height of the mountain as \(h\) and the horizontal distances from the points of observations as \(d_1\) and \(d_2\), then:
- \(\tan(32^{\circ}) = \frac{h}{d_2}\)
- \(\tan(35^{\circ}) = \frac{h}{d_1}\)
Right Triangle
A **Right Triangle** is a triangle with one of its angles measuring exactly 90°. In trigonometric problems like the one discussed, right triangles provide the basis for establishing relationships between various trigonometric functions and triangle sides.
The scenario of estimating a mountain's height by using angles of elevation is visualized through right triangles. The mountain is perpendicular to the base, making the setup a classic example of a right triangle problem. This helps because trigonometric functions like sine, cosine, and tangent are all based on the properties of right triangles.
The two observation points and the mountain form two separate right triangles with different angles of elevation. Thus, the height estimation heavily relies on understanding these triangles and using trigonometric identities effectively.
The scenario of estimating a mountain's height by using angles of elevation is visualized through right triangles. The mountain is perpendicular to the base, making the setup a classic example of a right triangle problem. This helps because trigonometric functions like sine, cosine, and tangent are all based on the properties of right triangles.
The two observation points and the mountain form two separate right triangles with different angles of elevation. Thus, the height estimation heavily relies on understanding these triangles and using trigonometric identities effectively.
Height Estimation
**Height Estimation** involves calculating the actual height of an object by using indirect measurements and mathematical concepts. In this exercise, it was necessary to estimate the height of a mountain by applying trigonometry to two right triangles formed by two observation points on the plain.
Here’s how height estimation unfolds:
Here’s how height estimation unfolds:
- Use given angles of elevation to establish equations: \(\tan(32^{\circ})\) and \(\tan(35^{\circ})\) relate height \(h\) to distances \(d_1\) and \(d_2.\)
- Rearrange these to solve for one unknown variable: \(h = d_1 \cdot \tan(35^{\circ})\) or \(h = (d_1 + 1000) \cdot \tan(32^{\circ})\).
- Use the equations to find distances and height by substitution and rearranging methods.
Other exercises in this chapter
Problem 58
A hot-air balloon is floating above a straight road. To estimate their height above the ground, the balloonists simultaneously measure the angle of depression t
View solution Problem 58
A circular arc of length 3 ft subtends a central angle of \(25^{\circ}\). Find the radius of the circle.
View solution Problem 59
Find the radius of the circle if an arc of length \(6 \mathrm{m}\) on the circle subtends a central angle of \(\pi / 6\) rad.
View solution Problem 60
Find the radius of the circle if an arc of length \(4 \mathrm{ft}\) on the circle subtends a central angle of \(135^{\circ}\).
View solution