Problem 59
Question
The production rules of a grammar for simple arithmetic expressions are: $$\langle\text { expression }\rangle :=\langle\text { digit })(\langle\text { expression })) |+(\langle\text { expression }\rangle) |$$ $$-(\langle\text { expression }\rangle) | \langle\text { expression }\rangle \langle\text { operator }\langle\text { expression }\rangle$$ $$\langle\text { digit }\rangle : := 0|1| 2|3| 4|5| 6|7| 8 | 9$$ $$\langle\text { operator }\rangle : :=+|-| / | \uparrow$$ Use this grammar to answer Exercises \(52-59\). Construct a derivation tree for each expression. $$-(3 \uparrow(5+2))$$
Step-by-Step Solution
Verified Answer
The derivation tree for the given expression "-(3↑(5+2))" can be constructed as follows:
┌───────\(-\langle\text{expression}\rangle\)────┐
┌(\langle\text{expression}\rangle┐ ┌\↓┐
\(\phantom{1+1}\langle\text { digit }\rangle\) ┬────┐\(\phantom{1+1}\text{derivation tree for "5+2"}\)
│ └\↑\┘
3 expression
Where the derivation tree for "5+2" is:
┌────\(+\langle\text{expression}\rangle\)─┐
─ ┌(\langle\text{expression}\rangle\phantom{1+1}\) ─┐
│ │ └\+\┘
┌\(\langle\text { digit }\rangle\phantom{1+1}\)┐
└\(\phantom{1+1}\)\┘
│
5
1Step 1: Identify the Expression Structure
The given expression is "-(3↑(5+2))" which follows the rule: \(\langle\text{expression}\rangle := -(\langle\text{expression}\rangle)\). First, split the expression into its main components (operator and expressions) by identifying the main outer minus sign and the expression inside the parenthesis.
2Step 2: Break down the expressions further
Inside the parenthesis, we have the expression "3↑(5+2)", which follows the rule: \(\langle\text{expression}\rangle := \langle\text{expression}\rangle \langle\text{operator}\rangle \langle\text{expression}\rangle\). Here, the left expression is "3", the operator is "↑", and the right expression is "(5+2)".
3Step 3: Analyze the right expression
Break down the right expression "(5+2)" into its components, which follows the rule: \(\langle\text{expression}\rangle := \langle\text{expression}\rangle \langle\text{operator}\rangle \langle\text{expression}\rangle\). Here, the left expression is "5", the operator is "+", and the right expression is "2".
4Step 4: Build the Derivation Tree
Now with all the components clearly identified, we can now build the derivation tree for the given expression:
┌───────\(-\langle\text{expression}\rangle\)────┐
┌(\langle\text{expression}\rangle┐ ┌\↓┐
\(\phantom{1+1}\langle\text { digit }\rangle\) ┬────┐\(\phantom{1+1}\text{derivation tree for "5+2"}\)
│ └\↑\┘
3 expression
Where the derivation tree for "5+2" is:
┌────\(+\langle\text{expression}\rangle\)─┐
─ ┌(\langle\text{expression}\rangle\phantom{1+1}\) ─┐
│ │ └\+\┘
┌\(\langle\text { digit }\rangle\phantom{1+1}\)┐
└\(\phantom{1+1}\)\┘
│
5
Key Concepts
Arithmetic ExpressionsDerivation TreesProduction Rules
Arithmetic Expressions
Arithmetic expressions are a fundamental part of mathematics and computer science. They allow us to represent numerical calculations in a structured and concise way.
In a context-free grammar, arithmetic expressions can often include numbers, variables, and operators.
These operators can include addition, subtraction, multiplication, division, and sometimes more complex operations like exponentiation.
In a context-free grammar, arithmetic expressions can often include numbers, variables, and operators.
These operators can include addition, subtraction, multiplication, division, and sometimes more complex operations like exponentiation.
- Components of Arithmetic Expressions: Expressions are typically made up of numbers (digits), symbols (like parenthesis), and operators (such as +, -, *, /, and ^).
- Order of Operations: Arithmetic expressions follow an order of operations, often remembered as PEMDAS (parentheses, exponents, multiplication/division, addition/subtraction).
- Example: In the expression \(-(3\uparrow(5+2))\), we first evaluate the innermost parenthesis \((5+2)\), then apply the exponentiation \(3\uparrow(7)\), and finally apply the unary minus \(-\).
Derivation Trees
Derivation trees, also known as parse trees, represent the syntactic structure of an expression generated by a grammar.
They show how the expression can be derived from the start symbol using production rules.
They show how the expression can be derived from the start symbol using production rules.
- Structure: A derivation tree starts with a root node representing the start symbol, and branches down to terminal symbols (digits and operators in our arithmetic expression example).
- Formation: Each node in the tree represents a step in the derivation process, with non-terminal nodes corresponding to grammar rules that expand into further expressions or terminals.
- Example: For the expression \(-(3\uparrow(5+2))\), the root node is the minus operation applied to the expression \(3\uparrow(5+2)\); this itself branches into the operator \(\uparrow\) with operands \(3\) and another subtree representing \((5+2)\).
Production Rules
Production rules define how non-terminal symbols in a grammar can be transformed into terminal symbols or other non-terminal symbols.
They form the blueprint of how a language (like arithmetic expressions) is constructed.
They form the blueprint of how a language (like arithmetic expressions) is constructed.
- Definition: In a context-free grammar, production rules are used to replace a non-terminal with a combination of terminals and/or non-terminals.
- Application: These rules are applied repeatedly to derive a string (such as an arithmetic expression) from the initial start symbol.
- Example: For our arithmetic expression grammar, one production rule might be \(\langle\text{expression}\rangle := \langle\text{digit}\rangle\), allowing a digit like \(3\) to be part of an expression.
Other exercises in this chapter
Problem 58
Construct a derivation tree for each expression. $$(5+3)-7 / 4$$
View solution Problem 59
Prove each, where \(A, B,\) and \(C\) are arbitrary languages over \(\Sigma\) and \(x \in \Sigma\). \(\left(A^{*}\right)^{*}=A^{*}\)
View solution Problem 60
A number in ALGOL (excluding the exponential form) is defined as follows: $$\langle\text { number }\rangle :=\langle\text { decimal number }\rangle :\langle\tex
View solution Problem 60
Prove each, where \(A, B,\) and \(C\) are arbitrary languages over \(\Sigma\) and \(x \in \Sigma\). \(\emptyset A=\varnothing\)
View solution