Problem 59
Question
The board of directors of Saner Automatic Door Company consists of 12 members, 3 of whom are women. A new policy and procedures manual is to be written for the company. A committee of 3 is randomly selected from the board to do the writing. a. What is the probability that all members of the committee are men? b. What is the probability that at least 1 member of the committee is a woman?
Step-by-Step Solution
Verified Answer
a. Probability all are men: \( \frac{21}{55} \) or approximately 0.3818.
b. Probability at least one is a woman: \( \frac{34}{55} \) or approximately 0.6182.
1Step 1: Calculate Total Ways to Select the Committee
First, we need to determine how many ways we can select 3 members from the total of 12 board members. We use the combination formula \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \). Here, \( n = 12 \) and \( k = 3 \). So, the total ways to choose 3 members from 12 is \( \binom{12}{3} = \frac{12!}{3!(12-3)!} = 220 \).
2Step 2: Calculate Ways to Select All Men
Since there are 9 men on the board, we need to calculate how many ways we can select 3 men from these 9. Again, we use the combination formula \( \binom{n}{k} \). Here, \( n = 9 \) and \( k = 3 \). Thus, the number of ways to choose 3 men is \( \binom{9}{3} = \frac{9!}{3!(9-3)!} = 84 \).
3Step 3: Calculate Probability of All Men on Committee
The probability that all members of the committee are men is the number of ways to select all men divided by the total ways to select the committee. Using our results from steps 1 and 2, \( P(\text{all men}) = \frac{84}{220} = \frac{42}{110} = \frac{21}{55} \approx 0.3818 \).
4Step 4: Calculate Probability of At Least One Woman on Committee
To find the probability that at least one member is a woman, we use the complement rule. We subtract the probability that all members are men from 1. Thus, \( P(\text{at least 1 woman}) = 1 - P(\text{all men}) = 1 - \frac{21}{55} = \frac{34}{55} \approx 0.6182 \).
Key Concepts
Combination FormulaProbability of EventComplement Rule
Combination Formula
The combination formula is a powerful tool in probability and combinatorics used to find out how many ways we can select items from a larger set. It answers questions like "How many groups of a certain size can be chosen from a larger group?" The formula itself is given by:\[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]Here, \(n\) represents the total number of items, and \(k\) is the number of items we want to choose. The exclamation mark, \(!\), denotes a factorial, which is the product of all positive integers up to that number.
For instance, to calculate the number of ways we can choose 3 members from a group of 12, we set \(n = 12\) and \(k = 3\). Plugging these into the formula, we get:\[\binom{12}{3} = \frac{12!}{3!(12-3)!} = 220\]This tells us there are 220 different ways to choose a group of 3 from 12. It’s important because we use this value as the denominator in probability calculations, representing all possible outcomes.
For instance, to calculate the number of ways we can choose 3 members from a group of 12, we set \(n = 12\) and \(k = 3\). Plugging these into the formula, we get:\[\binom{12}{3} = \frac{12!}{3!(12-3)!} = 220\]This tells us there are 220 different ways to choose a group of 3 from 12. It’s important because we use this value as the denominator in probability calculations, representing all possible outcomes.
Probability of Event
Probability is a way of quantifying the chance of an event occurring. It is a ratio of favorable outcomes to all possible outcomes, and is always a number between 0 and 1. In the context of our exercise, to find the probability that all members of the committee are men, we first need the number of ways to choose such a group.
We begin by identifying the number of favorable outcomes. Since there are 9 men on the board, we calculate how many ways we can select 3 men from these 9 using the combination formula:\[\binom{9}{3} = \frac{9!}{3!(9-3)!} = 84\]The probability that all members of the committee are men (our favorable event) is thus the number of favorable outcomes (84) divided by the total number of possible outcomes (220):\[P(\text{all men}) = \frac{84}{220} = \frac{21}{55} \approx 0.3818\]This gives us a probability of approximately 0.3818, indicating the likelihood that every committee member is male.
We begin by identifying the number of favorable outcomes. Since there are 9 men on the board, we calculate how many ways we can select 3 men from these 9 using the combination formula:\[\binom{9}{3} = \frac{9!}{3!(9-3)!} = 84\]The probability that all members of the committee are men (our favorable event) is thus the number of favorable outcomes (84) divided by the total number of possible outcomes (220):\[P(\text{all men}) = \frac{84}{220} = \frac{21}{55} \approx 0.3818\]This gives us a probability of approximately 0.3818, indicating the likelihood that every committee member is male.
Complement Rule
The complement rule is a useful probability tool that helps us find the probability of the opposite event occurring. If you know the probability of an event \(A\) happening, the probability of \(A\) not happening (complement of \(A\)) is 1 minus the probability of \(A\). This is written as:\[P(\text{not } A) = 1 - P(A)\]In our exercise, the complement rule is essential for finding the probability that at least one member of the committee is a woman. Instead of directly calculating this probability, which could be complex, we use the complement of this event, which is all members being men.
Having calculated that the probability all members are men is approximately 0.3818, we can now find:\[P(\text{at least 1 woman}) = 1 - P(\text{all men}) = 1 - 0.3818 \approx 0.6182\]This gives us a probability of about 0.6182 that there is at least one woman on the committee, demonstrating how effectively the complement rule simplifies certain probability calculations.
Having calculated that the probability all members are men is approximately 0.3818, we can now find:\[P(\text{at least 1 woman}) = 1 - P(\text{all men}) = 1 - 0.3818 \approx 0.6182\]This gives us a probability of about 0.6182 that there is at least one woman on the committee, demonstrating how effectively the complement rule simplifies certain probability calculations.
Other exercises in this chapter
Problem 57
Refer to Exercise \(56,\) but assume there are 10 homes in the Quail Creek area and four of them have a security system. Three homes are selected at random: a.
View solution Problem 58
There are 20 families living in the Willbrook Farms Development. Of these families 10 prepared their own federal income taxes for last year, 7 had their taxes p
View solution Problem 61
Althoff and Roll, an investment firm in Augusta, Georgia, advertises extensively in the Augusta Morning Gazette, the newspaper serving the region. The Gazette m
View solution Problem 62
An Internet company located in Southern California has season tickets to the Los Angeles Lakers basketbal games. The company president always invites one of the
View solution