Problem 59
Question
Solve the absolute-value inequality. (Lesson 6.7) $$|x+13| \geq 33$$
Step-by-Step Solution
Verified Answer
The solution to the inequality \(|x+13| \geq 33\) is \(x \leq -46\) or \(x \geq 20\).
1Step 1: Identify the two cases
The first step to solve \(|x+13| \geq 33\) is to set up two separate inequalities based on the definition of the absolute-value inequality. These cases are \(x+13 \geq 33\) (the positive case) and \(-(x+13) \geq 33\) (the negative case).
2Step 2: Solve the positive case
To solve the positive case, \(x+13 \geq 33\), subtract 13 from both sides to isolate \(x\), resulting in \(x \geq 20\).
3Step 3: Solve the negative case
To solve the negative case, \(-(x+13) \geq 33\), multiply the inequality by -1 to make it \((x+13) \leq -33\), which simplifies to \(x \leq -46\) after subtracting 13 from both sides.
4Step 4: Combine the solutions
These solutions combine to give one solution consisting of two ranges. The solution to the original absolute-value inequality \(|x+13| \geq 33\) is \(x \leq -46\) or \(x \geq 20\).
Key Concepts
Positive CaseNegative CaseInequality Solutions
Positive Case
An absolute-value expression, such as \(|x+13| \geq 33\), considers two scenarios. The first is the positive case. Here, we assume that the expression inside the absolute value is non-negative. In other words, the expression is simply as it is without any changes. For the positive case, the inequality becomes:
- \(x+13 \geq 33\)
- \(x \geq 20\)
Negative Case
The negative case considers when the expression inside of the absolute value could be negative. This means the absolute value flips the sign of the expressions to make it positive. For our inequality,
- \(-(x+13) \geq 33\)
- \(x+13 \leq -33\)
- \(x \leq -46\)
Inequality Solutions
After determining the results of both the positive and negative cases, we combine them to comprehend the full solution of the absolute-value inequality. These kinds of inequalities generally provide two possible ranges for solutions, which might sometimes seem "spread apart."For \(|x+13| \geq 33\), our combined solution states:
- \(x \geq 20\)
- or \(x \leq -46\)
Other exercises in this chapter
Problem 59
Completely factor the expression. $$ 15 x^{4}-50 x^{3}-40 x^{2} $$
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Simplify the expression. The simplified expression should have no negative exponents. (Lesson 8.4). $$ \left(\frac{a^{8}}{a^{3}}\right)^{-1} $$
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Write in point-slope form the equation of the line that passes through the given point and has the given slope. $$ (7,0), m=\frac{3}{7} $$
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Solve the equation \(\frac{5}{x+1}+\frac{x}{x^{2}-1}=\frac{1}{x-1}\). F) 1 G) 0 H) \(\frac{5}{6}\) J) \(\frac{6}{5}\)
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