Problem 59
Question
Solve. See Example 7. A rock is dropped from the top of a 400 -foot building. After 1 second, the rock is traveling 32 feet per second. After 3 seconds, the rock is traveling 96 feet per second. Let \(y\) be the rate of descent and \(x\) be the number of seconds since the rock was dropped. a. Write a linear equation that relates time \(x\) to rate \(y\). [Hint: Use the ordered pairs (1,32) and \((3,96) .]\) b. Use this equation to determine the rate of travel of the rock 4 seconds after it was dropped.
Step-by-Step Solution
Verified Answer
The linear equation is \(y = 32x\). At 4 seconds, the rate is 128 feet/sec.
1Step 1: Identify Given Points
We're given two points on the line: \((1, 32)\) and \((3, 96)\). These represent the values of \(x\) (time in seconds) and \(y\) (rate of descent in feet per second).
2Step 2: Calculate the Slope
The slope \(m\) of a linear equation can be calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting the given points \((x_1, y_1) = (1, 32)\) and \((x_2, y_2) = (3, 96)\), we get: \[ m = \frac{96 - 32}{3 - 1} = \frac{64}{2} = 32 \] So, the slope is 32.
3Step 3: Formulate the Linear Equation
Using the slope-intercept form \(y = mx + b\), where \(m\) is the slope, and \(b\) is the y-intercept. We know \(m = 32\), and using the point \((1, 32)\), substitute into the equation: \[ 32 = 32(1) + b \] Solving for \(b\), we get: \[ b = 0 \] Therefore, the equation is \(y = 32x\).
4Step 4: Determine the Rate at 4 Seconds
Substitute \(x = 4\) into the equation \(y = 32x\) to find the rate at 4 seconds: \[ y = 32 \times 4 = 128 \] So, the rate of travel 4 seconds after the rock was dropped is 128 feet per second.
Key Concepts
Slope-Intercept FormRate of ChangeOrdered Pairs
Slope-Intercept Form
Linear equations are often expressed in what is called the slope-intercept form. This is a straightforward way to describe a line with an equation written as \(y = mx + b\). Here, \(m\) represents the slope of the line, which tells us how steep the line is. The variable \(b\) is the y-intercept, indicating where the line crosses the y-axis.
Think of the slope as the rate of change between two variables. It reflects how much \(y\) changes when \(x\) changes. When you know both the slope and y-intercept, you can easily locate any point on the line.
Think of the slope as the rate of change between two variables. It reflects how much \(y\) changes when \(x\) changes. When you know both the slope and y-intercept, you can easily locate any point on the line.
- \(m\) - Slope, demonstrating the change in \(y\) per change in \(x\).
- \(b\) - y-intercept, where the line meets the y-axis.
Rate of Change
The rate of change in a linear equation is synonymous with the slope, \(m\). It quantifies the relationship between two variables, showing how one variable changes when the other changes.
To calculate the rate of change, we used the formula: \[ m = \frac{y_2-y_1}{x_2-x_1} \]
To calculate the rate of change, we used the formula: \[ m = \frac{y_2-y_1}{x_2-x_1} \]
- Choose two points on the line, \((x_1, y_1)\) and \((x_2, y_2)\).
- Subtract the \(y\)-values and the \(x\)-values, then divide \((y_2-y_1)\) by \((x_2-x_1)\).
Ordered Pairs
Ordered pairs \((x, y)\) are a way to represent data points on a coordinate plane. Each pair consists of two elements: the first is the value of \(x\), and the second represents the corresponding \(y\) value.
When examining linear relationships, these pairs are crucial as they provide specific points that help in drawing the line on a graph. For example, in the exercise, we were provided with two ordered pairs: \((1, 32)\) and \((3, 96)\). This means:
When examining linear relationships, these pairs are crucial as they provide specific points that help in drawing the line on a graph. For example, in the exercise, we were provided with two ordered pairs: \((1, 32)\) and \((3, 96)\). This means:
- At \(x = 1\) second, \(y = 32\) feet per second is the descent rate.
- At \(x = 3\) seconds, \(y = 96\) feet per second.
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