Problem 59
Question
Solve each formula for the specified variable. $$ \frac{1}{a}+\frac{1}{b}=1 \text { for } a $$
Step-by-Step Solution
Verified Answer
The solution is \( a = \frac{b}{b-1} \).
1Step 1: Clear the fractions
Multiply every term by \( ab \), (the common denominator) to eliminate the fractions:\[ab\left(\frac{1}{a}+\frac{1}{b}\right) = ab \times 1\]Simplifying the equation, we get:\[b + a = ab\]
2Step 2: Rearrange the equation
Isolate the term \( a \) on one side of the equation by moving \( a \) to the right side:\[b = ab - a\]
3Step 3: Factor the equation
Factor out \( a \) from the right-hand side:\[b = a(b - 1)\]
4Step 4: Solve for a
Divide both sides of the equation by \( b-1 \) to find \( a \):\[a = \frac{b}{b-1}\]
Key Concepts
Solving EquationsFormula TransformationIsolating Variables
Solving Equations
Solving equations is a fundamental skill in algebra that involves finding the values of variables that satisfy a given equality. In our original exercise, we aimed to solve for the variable \(a\) in the equation \(\frac{1}{a}+\frac{1}{b}=1\). Here's a brief run-through of the essential steps taken in our solution:
Breaking equations down into smaller, more manageable pieces is crucial for accurate problem solving.
- First, we cleared the equation of fractions by multiplying both sides by the common denominator \(ab\), which simplifies the equation considerably.
- Next, we simplified it to \(b + a = ab\).
- This allowed us to proceed with isolating the desired variable \(a\), as we will see in more detail in the following sections.
Breaking equations down into smaller, more manageable pieces is crucial for accurate problem solving.
Formula Transformation
Formula transformation is the process of rewriting a formula to express a variable in terms of other variables. This is particularly useful when dealing with more complex mathematical formulas. In our original exercise, transforming the formula involved:
- Rearranging the terms to isolate the target variable, \(a\).
- Moving \(a\) across the equality sign to enable factoring.
Isolating Variables
Isolating a variable involves rearranging an equation so that a single variable stands alone on one side of the equation. This is the key objective when solving for a specified variable in algebraic expressions. To isolate \(a\) in our problem, here’s what occurred:
- We started by obtaining a linear expression \(b = ab - a\).
- Factored out \(a\) from the right side to make \(b = a(b - 1)\).
- To complete the isolation, we divided both sides by \(b - 1\) to achieve \(a = \frac{b}{b-1}\).
Other exercises in this chapter
Problem 59
Simplify. See Example 7 . $$ \frac{2 x-7}{7-2 x} $$
View solution Problem 59
Simplify each complex fraction. $$ \frac{\frac{10 x}{x-3}}{\frac{6}{x-3}} $$
View solution Problem 59
Find the LCD of pair of rational expressions. \(\frac{5 n^{2}-16}{2 n^{2}+13 n+20}, \frac{3 n^{2}}{n^{2}+8 n+16}\)
View solution Problem 59
Divide, and then simplify, if possible. \(\frac{x^{2}-1}{3 x-3} \div(x+1)\)
View solution