Problem 59
Question
Simplify each expression. \(7.2 x-5.1+2.3 x+5.1\)
Step-by-Step Solution
Verified Answer
9.5x
1Step 1: Combine like terms
Identify and group the like terms in the expression. In this case, the like terms are the terms with the variable x and the constant terms.
2Step 2: Simplify the variable terms
Add the coefficients of the variable terms:\[7.2x + 2.3x = (7.2 + 2.3)x = 9.5x\]
3Step 3: Simplify the constants
Add the constant terms:\[-5.1 + 5.1 = 0\]
4Step 4: Write the simplified expression
Combine the simplified variable terms with the simplified constants to get the final expression: \[9.5x + 0 = 9.5x\]
Key Concepts
Combining Like TermsCoefficientsVariable and Constant Terms
Combining Like Terms
When simplifying algebraic expressions, one of the key steps is combining like terms. Like terms are terms that contain the same variable raised to the same power. For example, in the expression given in the exercise,
- 7.2x and 2.3x are like terms because they both have the variable x raised to the first power.
- -5.1 and 5.1 are like terms because they are both constant terms.
Coefficients
A coefficient is a numerical factor that multiplies a variable in an algebraic term. In the expression 7.2x, 7.2 is the coefficient and x is the variable. Let's look at a few key points about coefficients:
- Coefficients can be positive or negative.
- They determine the number of times the variable is multiplied.
Variable and Constant Terms
In algebra, terms in an expression can be either variable or constant terms. It is important to identify these to simplify the expression correctly.
- A variable term includes a variable (like x in 7.2x), while a constant term is a number without any variables.
- Variables can represent unknown values and can change, hence the name 'variable.'
- Constants are fixed values and do not change.
Other exercises in this chapter
Problem 59
Find each difference. $$ -8-6 $$
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Find each absolute value. \(|6-3|\)
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Perform each indicated operation. \(-7(3-8)\)
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Simplify each expression. $$ \left(\frac{4}{5}\right)(-0.73)\left(\frac{5}{4}\right) $$
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