Problem 59
Question
Mixed Practice Multiply. $$ (a-7)^{2} $$
Step-by-Step Solution
Verified Answer
\(a^2 - 14a + 49\)
1Step 1: Expand the Expression
To expand \((a-7)^2\), we use the formula for squaring a binomial, \((x-y)^2 = x^2 - 2xy + y^2\). In this case, x = a\ and y = 7\. Applying this formula, we get:\((a-7)^2 = a^2 - 2(a)(7) + 7^2\).
2Step 2: Calculate Each Term
Now, we calculate each part:1. \(a^2 = a^2\)2. \(-2(a)(7) = -14a\)3. \(7^2 = 49\).
3Step 3: Assemble the Expanded Expression
Combine all parts to write the full expression:\(a^2 - 14a + 49\).
Key Concepts
Squaring a BinomialAlgebraic ExpressionsStep-by-Step Solution
Squaring a Binomial
When you encounter a binomial, such as \((x-y)^2\), and need to square it, we follow a specific formula to simplify this process. Squaring a binomial involves multiplying the binomial by itself. The general formula \((x-y)^2 = x^2 - 2xy + y^2\) makes it easy to expand these expressions without having to actually multiply them out manually.
For our exercise, we have the binomial \((a-7)^2\). Here, just replace \(x\) with \(a\) and \(y\) with \(7\).
Using the formula, you can see that:
For our exercise, we have the binomial \((a-7)^2\). Here, just replace \(x\) with \(a\) and \(y\) with \(7\).
Using the formula, you can see that:
- \(x^2\) becomes \(a^2\)
- \(-2xy\) becomes \(-2 \times a \times 7 = -14a\)
- \(y^2\) becomes \(49\)
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and operations. They form the building blocks of algebra.
In our exercise, the expression \((a-7)^2\) involves a variable \(a\) and a constant \(7\). Once expanded, it transforms into \(a^2 - 14a + 49\), showing a clear example of how operations and variables interact within an expression.
Here's a closer look at the structure:
In our exercise, the expression \((a-7)^2\) involves a variable \(a\) and a constant \(7\). Once expanded, it transforms into \(a^2 - 14a + 49\), showing a clear example of how operations and variables interact within an expression.
Here's a closer look at the structure:
- **Variables**: Represent symbols like \(a\), whose values can change.
- **Constants**: Fixed values represented by numbers, such as \(7\) and \(49\).
- **Coefficients**: The numbers that appear before variables, for example, \(-14\) in \(-14a\).
Step-by-Step Solution
Approaching binomial expansions with a step-by-step method simplifies the process and ensures accuracy. Here's a breakdown of the steps followed in solving our exercise:
**Step 1: Expand the Expression**
Apply the squaring formula \((x-y)^2 = x^2 - 2xy + y^2\). Insert the values for \(x\) and \(y\) from your binomial.
**Step 2: Calculate Each Term**
Individually compute the value for each part of the formula:
Combine the terms to get the full expanded form: \(a^2 - 14a + 49\). Following these steps ensures that the expansion is both systematic and comprehensible. Regular practice with these steps will enhance your understanding and confidence in handling similar algebraic tasks.
**Step 1: Expand the Expression**
Apply the squaring formula \((x-y)^2 = x^2 - 2xy + y^2\). Insert the values for \(x\) and \(y\) from your binomial.
**Step 2: Calculate Each Term**
Individually compute the value for each part of the formula:
- \(a^2\) remains as \(a^2\)
- \(-2(a)(7)\) becomes \(-14a\)
- \(7^2\) simplifies to \(49\)
Combine the terms to get the full expanded form: \(a^2 - 14a + 49\). Following these steps ensures that the expansion is both systematic and comprehensible. Regular practice with these steps will enhance your understanding and confidence in handling similar algebraic tasks.
Other exercises in this chapter
Problem 59
Explain how to check a polynomial long division result when the remainder is 0
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Simplify each expression. Write each result using positive exponents only. $$ \frac{-12 m^{5} n^{-7}}{4 m^{-2} n^{-3}} $$
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Multiply. \(-1.2 y\left(-7 y^{6}\right)\)
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Use the quotient rule and simplify each expression. $$ \frac{p^{7} q^{20}}{p q^{15}} $$
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