Problem 59
Question
In a "Kipp generator", hydrogen gas is produced when zinc flakes react with hydrochloric acid: $$2 \mathrm{HCl}(a q)+\mathrm{Zn}(s) \longrightarrow \mathrm{ZnCl}_{2}(a q)+\mathrm{H}_{2}(g)$$ If \(30.0 \mathrm{~mL}\) of wet \(\mathrm{H}_{2}\) is collected over water at \(20^{\circ} \mathrm{C}\) and a barometric pressure of \(101.33 \mathrm{kPa}\), how many grams of \(\mathrm{Zn}\) have been consumed? (The vapor pressure of water is tabulated in Appendix B.)
Step-by-Step Solution
Verified Answer
Approximately 0.0802 grams of zinc have been consumed in the Kipp generator.
1Step 1: Determine the partial pressure of hydrogen gas
To determine the amount of hydrogen gas produced, first find the partial pressure of hydrogen gas. Subtract the vapor pressure of water at 20°C from the given barometric pressure.
Partial Pressure of H₂ (P_H₂) = Barometric Pressure - Vapor Pressure of Water
At 20°C, the vapor pressure of water can be found using the tabulated data in Appendix B, which states that it's 2.34 kPa. So:
P_H₂ = 101.33 kPa - 2.34 kPa
P_H₂ = 98.99 kPa
2Step 2: Calculate the moles of hydrogen gas produced
Now that we have the partial pressure of hydrogen gas, we can use the Ideal Gas Law to find the moles of hydrogen gas produced. The Ideal Gas Law is given by:
PV = nRT
Where P is the pressure (in kPa), V is the volume (in L), n is the number of moles, R is the ideal gas constant (8.314 J/(mol·K)), and T is the temperature (in K). We need to convert the given volume and temperature to appropriate units.
Volume of H₂: 30.0 mL = 0.030 L
Temperature: 20°C = 293.15 K
Rearrange the Ideal Gas Law to solve for n:
n = PV/RT
Plug in the values:
n = (98.99 kPa)(0.030 L) / (8.314 J/(mol·K))(293.15 K)
n = 0.001228 mol
We have approximately 0.001228 moles of hydrogen gas.
3Step 3: Determine the amount of zinc consumed
Now we will use the stoichiometry of the reaction to determine the amount of zinc consumed. The balanced chemical equation is:
2 HCl(aq) + Zn(s) → ZnCl₂(aq) + H₂(g)
From the stoichiometry, we can see that 1 mole of H₂ is produced for 1 mole of Zn consumed. Therefore, the moles of Zn consumed are equal to the moles of H₂ produced.
Moles of Zn consumed = Moles of H₂ produced = 0.001228 mol
4Step 4: Convert moles of zinc to grams
Finally, convert the moles of zinc consumed to grams using the molar mass of zinc, which is approximately 65.38 g/mol.
Grams of Zn consumed = Moles of Zn consumed × Molar mass of Zn
Grams of Zn consumed = 0.001228 mol × 65.38 g/mol
Grams of Zn consumed ≈ 0.0802 g
Therefore, approximately 0.0802 grams of zinc have been consumed.
Key Concepts
Ideal Gas LawZinc ReactionHydrogen Gas ProductionChemical Equations
Ideal Gas Law
The Ideal Gas Law is a fundamental equation that describes the behavior of gases. It's expressed as \( PV = nRT \). This equation relates four key variables:
In our exercise, the pressure \( P \) is adjusted for the partial pressure of hydrogen after accounting for water vapor pressure. The volume \( V \) is given in liters, and the temperature \( T \) is converted to Kelvin. These conversions are essential to accurately use the Ideal Gas Law for calculations.
- \( P \) - Pressure of the gas
- \( V \) - Volume of the gas
- \( n \) - Number of moles of the gas
- \( R \) - Ideal Gas Constant (8.314 J/(mol·K))
- \( T \) - Temperature in Kelvin
In our exercise, the pressure \( P \) is adjusted for the partial pressure of hydrogen after accounting for water vapor pressure. The volume \( V \) is given in liters, and the temperature \( T \) is converted to Kelvin. These conversions are essential to accurately use the Ideal Gas Law for calculations.
Zinc Reaction
The reaction between zinc and hydrochloric acid is quite fascinating. In this process, zinc flakes react with hydrochloric acid to produce zinc chloride and hydrogen gas.
This is a single replacement reaction where zinc, being more reactive, displaces the hydrogen in hydrochloric acid, forming zinc chloride in solution and releasing hydrogen gas. It's an example of the reactivity series, which predicts the ability of an element to displace another in a chemical reaction.
The balanced equation for this reaction is:
\[ \text{2 HCl(aq) + Zn(s) } \rightarrow \text{ ZnCl}_2\text{(aq) + H}_2\text{(g)} \]This equation shows that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas.
This is a single replacement reaction where zinc, being more reactive, displaces the hydrogen in hydrochloric acid, forming zinc chloride in solution and releasing hydrogen gas. It's an example of the reactivity series, which predicts the ability of an element to displace another in a chemical reaction.
The balanced equation for this reaction is:
\[ \text{2 HCl(aq) + Zn(s) } \rightarrow \text{ ZnCl}_2\text{(aq) + H}_2\text{(g)} \]This equation shows that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas.
Hydrogen Gas Production
Hydrogen gas production in chemical reactions like the one with zinc is a well-recorded process. As zinc reacts with hydrochloric acid, we observe bubbling due to hydrogen gas being released.
- Hydrogen is collected over water, meaning it is gathered as a wet gas with water vapor mixed in.
- To find out how much pure hydrogen gas is produced, you consider the pressure exerted by the water vapor, known as the vapor pressure.
- For accurate calculations, you subtract the water vapor pressure from the total barometric pressure to get the partial pressure of the hydrogen.
Chemical Equations
Chemical equations are concise representations of chemical reactions. They list reactants and products, their phases (solid, liquid, aqueous, gas), and the stoichiometric ratios involved.
The balanced chemical equation in our problem is crucial as it reflects the exact proportions of reactants needed and products formed:
\[ \text{2 HCl(aq) + Zn(s) } \rightarrow \text{ ZnCl}_2\text{(aq) + H}_2\text{(g)} \]
The balanced chemical equation in our problem is crucial as it reflects the exact proportions of reactants needed and products formed:
\[ \text{2 HCl(aq) + Zn(s) } \rightarrow \text{ ZnCl}_2\text{(aq) + H}_2\text{(g)} \]
- "Balanced" means the number of atoms for each element is the same on both sides of the equation.
- Stoichiometry, which is the calculation of reactants and products in chemical reactions, is used alongside the balanced equation to interpret chemical changes.
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