Problem 59
Question
If \(\theta\) is in Quadrant \(|\) and \(\sin \theta=\frac{3}{5},\) what is an exact value of \(\sin 2 \theta ?\) $$ \begin{array}{llll}{\text { F. } \frac{9}{25}} & {\text { G. } \frac{24}{25}} & {\text { H. } \frac{6}{5}} & {\text { J. } 73.7}\end{array} $$
Step-by-Step Solution
Verified Answer
\(\sin 2 \theta = \frac{24}{25}\)
1Step 1: Recall the Double Angle Formula for Sine
Remember that the double angle formula for sine is given by \(\sin 2\theta = 2\sin \theta \cos \theta\). In order to use this, we need the value of \(\sin \theta\) and \(\cos \theta\). We are given the value of \(\sin \theta\).
2Step 2: Find the Value of \(\cos \theta\)
Since \(\theta\) is in Quadrant II, where cosine is negative, and we know \(\sin \theta = \frac{3}{5}\), we can find \(\cos \theta\) using the Pythagorean identity \(\sin^2 \theta + \cos^2 \theta = 1\). Solving for \(\cos \theta\) gives us \(\cos \theta = -\sqrt{1 - \sin^2 \theta} = -\sqrt{1 - \left(\frac{3}{5}\right)^2} = -\sqrt{1 - \frac{9}{25}} = -\sqrt{\frac{25}{25} - \frac{9}{25}} = -\sqrt{\frac{16}{25}} = -\frac{4}{5}\).
3Step 3: Calculate \(\sin 2\theta\)
Now we can use the values of \(\sin \theta\) and \(\cos \theta\) in the double angle formula to find \(\sin 2\theta\): \(\sin 2\theta = 2 * \frac{3}{5} * \left(-\frac{4}{5}\right) = 2 * \frac{3}{5} * \frac{-4}{5} = \frac{-24}{25}\). However, because \(\sin 2\theta\) is a positive value as \(2\theta\) is in Quadrant I, the correct answer is \(\frac{24}{25}\).
Key Concepts
Pythagorean IdentityTrigonometric FunctionsQuadrant System
Pythagorean Identity
Understanding the Pythagorean identity is crucial in solving many trigonometry problems, particularly when dealing with relationships between sine and cosine functions. The identity states that for any angle \(\theta\), the square of the sine of the angle plus the square of the cosine of the angle is equal to 1: \[\sin^2\theta + \cos^2\theta = 1.\]
This equation stems from the Pythagorean theorem related to right-angled triangles, where the sum of the squares of the lengths of the legs equals the square of the length of the hypotenuse. In trigonometry, the legs represent \(\sin\theta\) and \(\cos\theta\) while the hypotenuse is always 1 (for a unit circle).
For example, in the given exercise, knowing that \(\sin\theta = \frac{3}{5}\), we use the Pythagorean identity to find \(\cos\theta\). This is how we determine the cosine component, which, in this case, is negative because the angle is in the second quadrant where the cosine values are negative.
This equation stems from the Pythagorean theorem related to right-angled triangles, where the sum of the squares of the lengths of the legs equals the square of the length of the hypotenuse. In trigonometry, the legs represent \(\sin\theta\) and \(\cos\theta\) while the hypotenuse is always 1 (for a unit circle).
For example, in the given exercise, knowing that \(\sin\theta = \frac{3}{5}\), we use the Pythagorean identity to find \(\cos\theta\). This is how we determine the cosine component, which, in this case, is negative because the angle is in the second quadrant where the cosine values are negative.
Trigonometric Functions
Trigonometric functions are foundational to the study of geometry and periodic phenomena, with sine and cosine being the most frequently used in many fields. They are defined as ratios of the sides of a right triangle relative to an acute angle, but they can also be understood in terms of points on the unit circle.
Sine and Cosine Functions
Considering a unit circle, the sine of an angle \(\theta\) is the y-coordinate of the point where the terminal side of the angle intersects the circle. Similarly, the cosine of \(\theta\) is the x-coordinate of that intersection point. When the angle \(\theta\) is doubled, as in \(\sin2\theta\), the double angle formulas come into play:- \(\sin 2\theta = 2\sin \theta \cos \theta\)
- \(\cos 2\theta = \cos^2\theta - \sin^2\theta\) (or other equivalent expressions)
Quadrant System
The quadrant system is used in trigonometry to determine the sign of trigonometric functions depending on the angle's position. A full rotation of 360 degrees is divided into four quadrants, each with a range of 90 degrees:
Implications weigh heavily when working with formulas, such as the double angle formula. For instance, the double angle \(2\theta\) results in an angle that falls into Quadrant I, leading to a positive \(\sin 2\theta\) even though \(\theta\) itself might result in a negative cosine value. Being aware of these quadrant rules ensures accurate computations in trigonometric problems.
- Quadrant I (0 to 90 degrees), where sine and cosine are both positive,
- Quadrant II (90 to 180 degrees), where sine is positive, and cosine is negative,
- Quadrant III (180 to 270 degrees), where both are negative,
- Quadrant IV (270 to 360 degrees), where sine is negative, and cosine is positive.
Implications weigh heavily when working with formulas, such as the double angle formula. For instance, the double angle \(2\theta\) results in an angle that falls into Quadrant I, leading to a positive \(\sin 2\theta\) even though \(\theta\) itself might result in a negative cosine value. Being aware of these quadrant rules ensures accurate computations in trigonometric problems.
Other exercises in this chapter
Problem 59
Find the measures of the acute angles of a right triangle, to the nearest tenth, if the legs are 135 \(\mathrm{cm}\) and 95 \(\mathrm{cm} .\)
View solution Problem 59
Simplify each trigonometric expression. $$ \frac{\cot ^{2} \theta-\csc ^{2} \theta}{\tan ^{2} \theta-\sec ^{2} \theta} $$
View solution Problem 60
In \(\triangle J K L, m \angle L=71^{\circ}, j=11 \mathrm{m},\) and \(m \angle K=46^{\circ} .\) Find \(k\)
View solution Problem 60
Use a half-angle identity to find an exact value of \(\sin 67.5^{\circ} .\)
View solution