Problem 59
Question
For the following problems, note how many: $$ (9+y) \text { 's in } 8(9+y) ? $$
Step-by-Step Solution
Verified Answer
Answer: 0 times
1Step 1: Rewrite the expression using distributive property
Distribute the 8 across the expression (9+y). To do this, multiply 8 by each term inside the parentheses:
$$
8(9+y) = 8 \cdot 9 + 8 \cdot y
$$
2Step 2: Simplify the expression
Perform the multiplication in the expression:
$$
8 \cdot 9 + 8 \cdot y = 72 + 8y
$$
3Step 3: Count the term (9+y) in the expression
The simplified expression is 72 + 8y. The term (9+y) does not appear in this expression because it got distributed and simplified. Therefore, there are 0 occurrences of (9+y) in the expression 8(9+y).
Key Concepts
Understanding Algebraic ExpressionsSimplifying Expressions with the Distributive PropertyMultiplication in Algebra
Understanding Algebraic Expressions
Algebraic expressions are the backbone of algebra and enable us to express mathematical ideas clearly and succinctly. They consist of variables, constants, and operations such as addition, subtraction, multiplication, and division. For example, in the expression \(8(9+y)\), the number 8 is called a coefficient, which multiplies the quantity \((9+y)\).
The quantity \((9+y)\) itself is a binomial because it has two terms. Variables, represented by letters like 'y' in this case, stand in for unknown values and allow us to work with general principles before substituting specific numbers. Understanding algebraic expressions is crucial; they are used to model real-world situations, solve equations, and as we'll see next, they can be simplified to make them easier to work with.
The quantity \((9+y)\) itself is a binomial because it has two terms. Variables, represented by letters like 'y' in this case, stand in for unknown values and allow us to work with general principles before substituting specific numbers. Understanding algebraic expressions is crucial; they are used to model real-world situations, solve equations, and as we'll see next, they can be simplified to make them easier to work with.
Simplifying Expressions with the Distributive Property
Simplifying expressions, a key skill in algebra, often requires the use of the distributive property. This property allows us to remove parentheses by distributing a multiplication over addition or subtraction inside. The distributive property is vital for simplifying because it breaks down complex expressions into simpler components.
Consider this operation: \(8(9+y)\). We use the distributive property to 'distribute' the 8 across each term in the parentheses: \(8 \cdot 9 + 8 \cdot y\), which simplifies to \(72 + 8y\). Simplification like this helps clarify what the expression represents and allows for further mathematical operations to be performed more easily. It’s a process of making the complex simple while maintaining equivalence.
Consider this operation: \(8(9+y)\). We use the distributive property to 'distribute' the 8 across each term in the parentheses: \(8 \cdot 9 + 8 \cdot y\), which simplifies to \(72 + 8y\). Simplification like this helps clarify what the expression represents and allows for further mathematical operations to be performed more easily. It’s a process of making the complex simple while maintaining equivalence.
Multiplication in Algebra
Multiplication is an essential operation in algebra that allows us to combine quantities efficiently. In algebraic expressions, multiplication connects coefficients with variables or multiplies constants together to simplify expressions.
For instance, in our example where we multiply a number by a binomial, express it as \(8 \cdot (9 + y)\). Here, the 8 multiplies both the 9 and the y. This is not just simple arithmetic; it's an application of algebra where multiplication is used to reveal structure underneath what might seem like complicated expressions. Remember, multiplication in algebra is key to understanding and simplifying terms, as it scales quantities and affects the outcome of algebraic solutions.
For instance, in our example where we multiply a number by a binomial, express it as \(8 \cdot (9 + y)\). Here, the 8 multiplies both the 9 and the y. This is not just simple arithmetic; it's an application of algebra where multiplication is used to reveal structure underneath what might seem like complicated expressions. Remember, multiplication in algebra is key to understanding and simplifying terms, as it scales quantities and affects the outcome of algebraic solutions.
Other exercises in this chapter
Problem 59
Find the value of \(4^{-2} \cdot 8^{2}-3^{2}\).
View solution Problem 59
For the following problems, perform the multiplications and combine any like terms. $$ 2 b(b-1) $$
View solution Problem 59
Simplify the algebraic expressions for the following problems. $$ a b c(3 a b c+c+b)+6 a\left(2 b c+b c^{2}\right) $$
View solution Problem 59
For the following problems, find the products. $$ (5 h-2 k)(5 h+2 k) $$
View solution