Problem 59
Question
Find the pH for each substance with the given hydronium ion \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) concentration. Crackers, \(3.9 \times 10^{-9}\)
Step-by-Step Solution
Verified Answer
The pH is approximately 8.41.
1Step 1: Understanding the pH formula
The pH of a solution is calculated using the formula: \[pH = -\log_{10}[\mathrm{H}_3\mathrm{O}^+]\]where \([\mathrm{H}_3\mathrm{O}^+]\) is the concentration of hydronium ions.
2Step 2: Inserting the given values
Insert the given hydronium ion concentration for the crackers into the formula. The concentration is \(3.9 \times 10^{-9} \text{ M}\).
3Step 3: Calculating the pH
Calculate the pH by taking the negative logarithm (base 10) of the hydronium ion concentration:\[pH = -\log_{10}(3.9 \times 10^{-9})\]Use a calculator to perform this calculation.
4Step 4: Evaluating the logarithm
Using a calculator, compute the logarithm:\[\log_{10}(3.9 \times 10^{-9}) \approx -8.409\]Thus,\[pH = -(-8.409) = 8.409\]
5Step 5: Conclusion
The pH of the solution, which represents the hydronium ion concentration of the crackers, is approximately 8.41.
Key Concepts
Hydronium Ion ConcentrationLogarithmic FunctionspH Scale
Hydronium Ion Concentration
Hydronium ion concentration is pivotal in understanding the acidity or basicity of a solution. Hydronium ions \(\text{H}_3\text{O}^+\) are formed when water molecules combine with hydrogen ions. This process is crucial to determining how acidic or basic a solution is.
Understanding this concept lays the groundwork for appreciating how substances interact within solutions.
- The concentration is typically expressed in moles per liter (M), which shows how many hydronium ions are present per liter of solution.
- The concentration directly influences the pH, as seen in the formula \(pH = -\log_{10}[\mathrm{H}_3\mathrm{O}^+]\). A higher concentration means more acidity.
Understanding this concept lays the groundwork for appreciating how substances interact within solutions.
Logarithmic Functions
Logarithms are mathematical functions that simplify the process of working with very large or very small numbers. When calculating pH, the logarithmic function \(\log_{10}\) is used. This is the logarithm to the base 10, which aligns perfectly with the pH scale.
This results in a friendly number like \(-8.409\), making it easier to assess the acidity level.
- A logarithm is the exponent that indicates the power to which a base number must be raised to yield a specific result.
- In pH calculation, it helps in determining how concentrated hydronium ions are by converting multiplication into addition.
This results in a friendly number like \(-8.409\), making it easier to assess the acidity level.
pH Scale
The pH scale is a numeric representation of solution acidity or basicity, ranging from 0 to 14. It is a logarithmic scale, meaning each unit change represents a tenfold change in acidity or basicity.
Understanding the pH scale is essential in fields such as chemistry, biology, and environmental science, due to its impact on chemical reactivity and organism survival.
- Solutions with a pH less than 7 are acidic, while those with a pH greater than 7 are basic. A pH of exactly 7 indicates a neutral solution.
- The scale is based on the concentration of hydronium ions \([\text{H}_3\text{O}^+]\), where a lower concentration reflects a higher pH.
Understanding the pH scale is essential in fields such as chemistry, biology, and environmental science, due to its impact on chemical reactivity and organism survival.
Other exercises in this chapter
Problem 59
For each exponential function f, find f^{-1} analytically and graph both f and f^{-1} in the same viewing window. $$f(x)=-10^{x}+4$$
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Solve each equation in part (a) analytically. Support your answer with a calculator graph. Then use the graph to solve the associated inequalities in parts (b)
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For each function that is one-to-one, write an equation for the inverse function in the form \(y=f^{-1}(x)\) and then graph \(f\) and \(f^{-1}\) on the same axe
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Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\ln e^{x}-2 \ln e=\ln e^{4}$$
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