Problem 59
Question
Find \(h(5)\) and \(h(-2) .\) See Example 4. $$ h(x)=|x|+2 $$
Step-by-Step Solution
Verified Answer
\( h(5) = 7 \) and \( h(-2) = 4 \).
1Step 1: Understand the Function
The function given is \( h(x) = |x| + 2 \). This means you take the absolute value of \( x \) and then add 2 to the result.
2Step 2: Evaluate \( h(5) \)
Substitute \( x = 5 \) into the function. Calculate the absolute value of 5, which is 5, and then add 2. So, \( h(5) = |5| + 2 = 5 + 2 = 7 \).
3Step 3: Evaluate \( h(-2) \)
Substitute \( x = -2 \) into the function. Calculate the absolute value of -2, which is 2, and then add 2. So, \( h(-2) = |-2| + 2 = 2 + 2 = 4 \).
Key Concepts
Function EvaluationAbsolute ValueAlgebraic Expressions
Function Evaluation
Function evaluation is a fundamental concept in mathematics. It involves substituting a given value into a function. This helps us find the corresponding output of that function. For example, if you have a function like \( h(x) = |x|+2 \), evaluating \( h(5) \) means substituting 5 into \( x \):
- Start by replacing \( x \) with 5: \( h(5) = |5|+2 \).
- Find the absolute value: \( |5| = 5 \).
- Add 2 to the result: \( 5+2 = 7 \). Thus, \( h(5) = 7 \).
Absolute Value
The concept of absolute value is vital in algebra and mathematics in general. The absolute value of a number refers to its distance from 0 on the number line, without considering direction. Let's break it down:
- The absolute value is always non-negative.
- For any positive number \( x \), \( |x| = x \).
- For any negative number \( x \), \( |x| = -x \) (which makes it positive).
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and operations such as addition, subtraction, multiplication, and division. They form the basis of algebra and allow us to describe patterns and relationships between numbers. An example of an algebraic expression is \( h(x) = |x| + 2 \).Here's how it works:
- \( h(x) \) refers to the output based on input \( x \).
- The term \( |x| \) finds the absolute value of \( x \).
- Adding 2 is the last operation to get the final output.
Other exercises in this chapter
Problem 58
Solve each compound inequality, if possible. Graph the solution set (if one exists) and write it using interval notation. $$ -4 \leq-2(x+8)
View solution Problem 58
Solve each inequality. Graph the solution set and write it using interval notation. \(|x-8| \leq 12\)
View solution Problem 59
As the cost of a purchase that is less than \(\$ 5\) increases, the amount of change received from a five-dollar bill decreases. Is this inverse variation? Expl
View solution Problem 59
Solve for the specified variable or expression. $$ b^{2} x^{2}+a^{2} y^{2}=a^{2} b^{2} \text { for } a^{2} $$
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