Problem 59
Question
Exercises \(59-66:\) Solve the linear equation with the intersection-of-graphs method. Approximate the solution to the nearest thousandth whenever appropriate. $$ 5 x-1.5=5 $$
Step-by-Step Solution
Verified Answer
The solution is \(x = 1.3\).
1Step 1: Rearrange the Equation
Start with the linear equation \(5x - 1.5 = 5\). The goal is to express this as two separate functions to use the intersection-of-graphs method. We leave 5 on the right, and rearrange the left: \(5x - 1.5\) becomes \(y_1 = 5x - 1.5\) and \(y_2 = 5\).
2Step 2: Set Up the Functions
Define \(y_1 = 5x - 1.5\) as the first function and \(y_2 = 5\) as the second function. These will be the equations of two lines on a graph.
3Step 3: Graph the Functions
Graph \(y_1 = 5x - 1.5\) and \(y_2 = 5\) on the same set of axes. The line for \(y_2 = 5\) is horizontal because it is constant. The line for \(y_1 = 5x - 1.5\) has a slope of 5 and a y-intercept of -1.5.
4Step 4: Find the Intersection
Look at the graph and find the point where the two lines intersect. The x-coordinate of this intersection point is the solution to the equation. Algebraically, set \(5x - 1.5\) equal to 5 and solve for \(x\): \(5x - 1.5 = 5 \rightarrow 5x = 6.5 \rightarrow x = 1.3\).
5Step 5: Approximate the Solution
Since the solution must be to the nearest thousandth, ensure accuracy. The intersection point gives \(x = 1.3\), which is already at the nearest thousandth precision.
Key Concepts
Intersection of Graphs MethodGraphing Linear FunctionsSolving for x
Intersection of Graphs Method
The intersection of graphs method is a visual approach to finding the solution to a system of equations or a single equation presented as two separate functions. Instead of solving the equation algebraically, we graphically depict the problem on an x-y coordinate plane.
In this context, the linear equation given, which is **\(5x - 1.5 = 5\)**, can be represented graphically by splitting it up into two functions. You define:
Once plotted, the \(x\)-coordinate of this intersection point tells us the solution to the original equation. This method is particularly beneficial because it provides a visual verification of the solution and clearly demonstrates the relationship between the functions.
In this context, the linear equation given, which is **\(5x - 1.5 = 5\)**, can be represented graphically by splitting it up into two functions. You define:
- \(y_1 = 5x - 1.5\)
- \(y_2 = 5\)
Once plotted, the \(x\)-coordinate of this intersection point tells us the solution to the original equation. This method is particularly beneficial because it provides a visual verification of the solution and clearly demonstrates the relationship between the functions.
Graphing Linear Functions
Graphing linear functions involves plotting straight lines on a coordinate grid, defined by the equation \(y = mx + b\), where \(m\) represents the slope and \(b\) the y-intercept. In our example, the functions are \(y_1 = 5x - 1.5\) and \(y_2 = 5\).
The first function, \(y_1 = 5x - 1.5\), is a line with a slope \(m = 5\) and a y-intercept of \(-1.5\). This tells you that for every unit the \(x\) value increases, the \(y\) value increases by 5. Start plotting this graph from the y-intercept \(-1.5\), and use the slope to determine the line's direction and steepness.
The second function, \(y_2 = 5\), is a horizontal line. It does not depend on \(x\) and remains constant at all points where \(y = 5\), no matter what \(x\) is. Plot this line across the graph.
Together, these steps create a visual of the linear functions and their behaviors, allowing us to clearly discern where they intersect.
The first function, \(y_1 = 5x - 1.5\), is a line with a slope \(m = 5\) and a y-intercept of \(-1.5\). This tells you that for every unit the \(x\) value increases, the \(y\) value increases by 5. Start plotting this graph from the y-intercept \(-1.5\), and use the slope to determine the line's direction and steepness.
The second function, \(y_2 = 5\), is a horizontal line. It does not depend on \(x\) and remains constant at all points where \(y = 5\), no matter what \(x\) is. Plot this line across the graph.
Together, these steps create a visual of the linear functions and their behaviors, allowing us to clearly discern where they intersect.
Solving for x
Solving for \(x\) is the process of finding the value of the variable that makes the equation true. In our example, once visualized on the graph, the point where \(y_1\) and \(y_2\) intersect gives the solution for \(x\).
To do this algebraically, we set the expressions for \(y_1\) and \(y_2\) equal: \(5x - 1.5 = 5\).
Here's how we solve step by step:
To do this algebraically, we set the expressions for \(y_1\) and \(y_2\) equal: \(5x - 1.5 = 5\).
Here's how we solve step by step:
- Add 1.5 to both sides to isolate terms with \(x\): \(5x = 6.5\)
- Divide both sides by 5 to solve for \(x\): \(x = 1.3\)
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