Problem 59
Question
Draw Lewis structures that show how electron pairs move and bonds form and break during the autoionization of water. Label the appropriate \(\mathrm{H}_{2} \mathrm{O}\) molecules as the Lewis acid and Lewis base.
Step-by-Step Solution
Verified Answer
Answer: In the autoionization process, one water molecule acts as a Lewis base, donating a hydrogen atom with its electron pair to the other water molecule, which acts as a Lewis acid. This process results in the formation of a hydronium ion (H₃O⁺) and a hydroxide ion (OH⁻).
1Step 1: Draw the Lewis structure of a water molecule
To draw the Lewis structure of a water molecule (\(\mathrm{H}_{2} \mathrm{O}\)), first, arrange the atoms: the central atom (oxygen) is bonded to two hydrogen atoms. The oxygen atom has 6 valence electrons, and each hydrogen has 1 valence electron. Oxygen forms two single bonds with the hydrogen atoms, and it's left with two lone pairs of electrons.
Lewis structure for water:
O
/ \
H H
2Step 2: Identify a molecule as a Lewis acid and another as a Lewis base
In autoionization, one water molecule will act as a Lewis acid by accepting an electron pair, and the other will act as a Lewis base by donating an electron pair. In this case, the oxygen atom of the Lewis acid molecule will accept the electron pair from a hydrogen atom of the Lewis base molecule.
3Step 3: Draw the Lewis structures showing the movement of electron pairs and bonds formation and breakage during autoionization
During the autoionization process, the electron pair from an oxygen-hydrogen bond of one water molecule (Lewis base) is donated to the oxygen of another water molecule (Lewis acid), forming a hydronium ion (\(\mathrm{H}_{3} \mathrm{O}^{+}\)) and a hydroxide ion (\(\mathrm{OH}^{-}\)). The Lewis structures showing this process are:
Lewis base Lewis acid
O O
/ \ / \
H H + H H
|---|
Movement: v
Hydronium ion Hydroxide ion
O O
/|\ / \
H H H H ..
4Step 4: Label the structures as Lewis acid and Lewis base
Now, we can label the water molecules as the Lewis acid and Lewis base in the initial reaction:
Lewis base Lewis Acid
O O
/ \ / \
H H + H H
Overall, the autoionization process of water involves one water molecule acting as a Lewis base, donating a hydrogen atom with its electron pair to the other water molecule as a Lewis acid, resulting in the hydronium and hydroxide ions.
Other exercises in this chapter
Problem 57
Are all Brensted-Lowry acids also Lewis acids? Explain why or why not.
View solution Problem 58
Why is \(\mathrm{BF}_{3}\) a Lewis acid but not a Bronsted-Lowry acid?
View solution Problem 60
Draw Lewis structures that show how electron pairs move and bonds form and break in the following reaction, and identify the Lewis acid and Lewis base. $$ \math
View solution Problem 61
Draw Lewis structures that show how electron pairs move and bonds form and break in the following reaction, and identify the Lewis acid and Lewis base. $$ \math
View solution