Problem 59
Question
Determine whether the infinite geometric series is convergent or divergent. If it is convergent, find its sum. $$3-3(1.1)+3(1.1)^{2}-3(1.1)^{3}+\cdots$$
Step-by-Step Solution
Verified Answer
The series is divergent.
1Step 1: Identify the first term
The first term of the series is directly given as the first term in the sequence. Here, the first term \( a = 3 \).
2Step 2: Identify the common ratio
The common ratio \( r \) is the factor by which we multiply each term to get the next term. We find it by dividing the second term by the first term: \(-3(1.1) / 3 = -1.1\).
3Step 3: Determine convergence or divergence
A geometric series converges if the absolute value of the common ratio \(|r| < 1\). Here, \(|-1.1| = 1.1\), which is greater than 1. Thus, the series is divergent.
Key Concepts
Infinite SeriesConvergenceDivergenceCommon Ratio
Infinite Series
An infinite series is essentially the sum of an infinite sequence of numbers. In the world of mathematics, infinite series allow us to explore and understand phenomena that might extend beyond simple or finite processes. Imagine stacking numbers forever in a sequence, and trying to find the sum of all of these. That's what an infinite series does.
In mathematics, one can often encounter various forms of infinite series. These series typically involve terms that go on infinitely. Examples include geometric series, arithmetic series, and even more complex series like power series.
Despite being infinite, some series can settle towards a particular value, which leads us to our next concept: convergence.
In mathematics, one can often encounter various forms of infinite series. These series typically involve terms that go on infinitely. Examples include geometric series, arithmetic series, and even more complex series like power series.
Despite being infinite, some series can settle towards a particular value, which leads us to our next concept: convergence.
Convergence
Convergence is a crucial concept in understanding infinite series. When an infinite series converges, it means the sum of its terms approaches a specific number, no matter how many terms you add.
The idea of convergence allows mathematicians to make sense of infinite processes, by essentially saying, "Even though we are dealing with infinity, we can still predict the outcome." For a geometric series, which involves numbers being multiplied by a common ratio, convergence occurs if the common ratio's absolute value is less than one, \(|r| < 1\).
In simpler terms, if you keep multiplying by a number smaller than 1, each term decreases, ensuring the sum does not shoot off to infinity. Thus, convergence helps bring the seemingly endless to a closure.
The idea of convergence allows mathematicians to make sense of infinite processes, by essentially saying, "Even though we are dealing with infinity, we can still predict the outcome." For a geometric series, which involves numbers being multiplied by a common ratio, convergence occurs if the common ratio's absolute value is less than one, \(|r| < 1\).
In simpler terms, if you keep multiplying by a number smaller than 1, each term decreases, ensuring the sum does not shoot off to infinity. Thus, convergence helps bring the seemingly endless to a closure.
Divergence
While convergence leads to a well-defined sum in an infinite series, divergence describes the opposite scenario. If an infinite series is divergent, the sum of its terms will not settle to a fixed value as more terms are added. Instead, the sum may grow infinitely large, oscillate, or lack a clear limit.
In our example with the geometric series, we determined that the common ratio \(-1.1\) has an absolute value greater than one \(\(|-1.1| = 1.1\)\). Since this exceeds 1, the series does not converge; it diverges instead.
Divergence in series often means that the series cannot be summed to a finite number, which is crucial when analyzing mathematical models, ensuring accuracy and understanding of growth behaviors.
In our example with the geometric series, we determined that the common ratio \(-1.1\) has an absolute value greater than one \(\(|-1.1| = 1.1\)\). Since this exceeds 1, the series does not converge; it diverges instead.
Divergence in series often means that the series cannot be summed to a finite number, which is crucial when analyzing mathematical models, ensuring accuracy and understanding of growth behaviors.
Common Ratio
The common ratio is a key part of geometric series. It’s what links successive terms together. To identify the common ratio, you simply divide any term by the one before it in the series.
Finding the common ratio gives insight into the behavior of the series, especially regarding convergence or divergence.
For example, in the given exercise, the common ratio was found by dividing the second term by the first. This resulted in \-1.1\. If \(|r| < 1|\), the series converges, but if \(|r| > 1\), it diverges.
Finding the common ratio gives insight into the behavior of the series, especially regarding convergence or divergence.
For example, in the given exercise, the common ratio was found by dividing the second term by the first. This resulted in \-1.1\. If \(|r| < 1|\), the series converges, but if \(|r| > 1\), it diverges.
- A positive ratio keeps the series going in one direction.
- A negative ratio makes the series alternate between positive and negative terms.
Other exercises in this chapter
Problem 58
The harmonic mean of two numbers is the reciprocal of the average of the reciprocals of the two numbers. Find the harmonic mean of 3 and 5.
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Write the sum without using sigma notation. $$\sum_{k=6}^{9} k(k+3)$$
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An arithmetic sequence has first term \(a=5\) and common difference \(d=2 .\) How many terms of this sequence must be added to get \(2700 ?\)
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Write the sum without using sigma notation. $$\sum_{k=3}^{100} x^{k}$$
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