Problem 59
Question
Convert the polar equation to rectangular coordinates. $$ r=1+2 \sin \theta $$
Step-by-Step Solution
Verified Answer
The rectangular equation is \( x^4 + 2x^2y^2 + y^4 - 4x^2y - 4y^3 + 3y^2 - x^2 = 0 \).
1Step 1: Recall Polar to Rectangular Formulas
To convert the given polar equation to rectangular coordinates, we use the following conversion formulas: \[ x = r \cos \theta \]\[ y = r \sin \theta \]\[ r^2 = x^2 + y^2 \] These relationships will help to rewrite the equation in terms of \(x\) and \(y\).
2Step 2: Express r in Terms of y
In the given equation \( r = 1 + 2 \sin \theta \), substitute the formula \( y = r \sin \theta \). Rearrange it as \( \sin \theta = \frac{y}{r} \). Substitute it into the equation:\[ r = 1 + 2 \left(\frac{y}{r}\right) \]
3Step 3: Clear the Fraction
Multiply both sides of the equation by \( r \) to clear the fraction:\[ r^2 = r + 2y \]
4Step 4: Substitute r² in Terms of x and y
Use the formula \( r^2 = x^2 + y^2 \) to replace \( r^2 \) in the equation:\[ x^2 + y^2 = r + 2y \]
5Step 5: Substitute r in Terms of x and y
Recognize that \( r = \sqrt{x^2 + y^2} \). Substitute this in place of \( r \) in the equation:\[ x^2 + y^2 = \sqrt{x^2 + y^2} + 2y \]
6Step 6: Isolate the Square Root
Rearrange the equation to isolate the square root:\[ x^2 + y^2 - 2y = \sqrt{x^2 + y^2} \]
7Step 7: Square Both Sides
Square both sides to eliminate the square root:\[ \left(x^2 + y^2 - 2y\right)^2 = x^2 + y^2 \]
8Step 8: Expand and Simplify
Expand the left side and simplify:\[ x^4 + 2x^2y^2 + y^4 - 4x^2y - 4y^3 + 4y^2 = x^2 + y^2 \]
9Step 9: Collect Like Terms
Rearrange the terms to get everything on one side of the equation:\[ x^4 + 2x^2y^2 + y^4 - 4x^2y - 4y^3 + 3y^2 - x^2 = 0 \]This is the equation in rectangular form.
Key Concepts
Polar CoordinatesRectangular CoordinatesCoordinate ConversionTrigonometric Functions
Polar Coordinates
Polar coordinates are a way to represent points in a plane using a distance and an angle. This method is particularly useful when dealing with problems involving circles and curves. Rather than the typical x and y axis, polar coordinates use:
- r: the length from the origin to the point.
- θ (theta): the angle from the positive x-axis to the line connecting the origin and the point.
Rectangular Coordinates
Rectangular coordinates, sometimes referred to as Cartesian coordinates, involve the standard grid system designated by x and y values. These coordinates are straightforward for representing the position of a point on a simple plane. In a rectangular coordinate system:
- x is the horizontal distance from the origin.
- y is the vertical distance from the origin.
Coordinate Conversion
Coordinate conversion is the process of transforming one type of coordinate system into another. When converting from polar to rectangular coordinates, as outlined in the original exercise, a set of formulas is employed:
- Formula for x: \( x = r \cos \theta \)
- Formula for y: \( y = r \sin \theta \)
- Relation for r: \( r^2 = x^2 + y^2 \)
Trigonometric Functions
Trigonometric functions are mathematical relations based on angles and their standard position on a unit circle. In the context of coordinate conversion, these functions help link polar and rectangular coordinates. The primary trigonometric functions involved are:
- Sine (\( \sin \theta \)): represents the y-coordinate on the unit circle.
- Cosine (\( \cos \theta \)): represents the x-coordinate on the unit circle.
Other exercises in this chapter
Problem 58
(a) Graph the polar equation \(r=\tan \theta \sec \theta\) in the viewing rectangle \([-3,3]\) by \([-1,9]\) . (b) Note that your graph in part (a) looks like a
View solution Problem 58
Find the product \(z_{1} z_{2}\) and the quotient \(z_{1} / z_{2}\) . Express your answer in polar form. $$ \begin{array}{l}{z_{1}=\sqrt{2}\left(\cos 75^{\circ}
View solution Problem 59
Orbit of a Satellite Scientists and engineers often use polar equations to model the motion of satellites in earth orbit. Let's consider a satellite whose orbit
View solution Problem 59
Find the product \(z_{1} z_{2}\) and the quotient \(z_{1} / z_{2}\) . Express your answer in polar form. $$ \begin{array}{l}{z_{1}=4\left(\cos 200^{\circ}+i \si
View solution