Problem 59
Question
\(\bullet\) When a toy car is rapidly scooted across the floor, it stores energy in a flywheel. The car has mass \(0.180 \mathrm{kg},\) and its fly- wheel has moment of inertia \(4.00 \times 10^{-5} \mathrm{kg} \cdot \mathrm{m}^{2} .\) The car is 15.0 \(\mathrm{cm}\) long. An advertisement claims that the car can travel at a scale speed of up to 700 \(\mathrm{km} / \mathrm{h}(440 \mathrm{mi} / \mathrm{h}) .\) The scale speed is the speed of the toy car multiplied by the ratio of the length of an actual car to the length of the toy. Assume a length of 3.0 \(\mathrm{m}\) for a real car. (a) For a scale speed of \(700 \mathrm{km} / \mathrm{h},\) what is the actual translational speed of the car? (b) If all the kinetic energy that is initially in the flywheel is converted to the translational kinetic energy of the toy, how much energy is originally stored in the flywheel? (c) What ini- tial angular velocity of the flywheel was needed to store the amount of energy calculated in part (b)?
Step-by-Step Solution
VerifiedKey Concepts
Kinetic Energy
- Translational Kinetic Energy: This is the energy due to the car moving in a straight line. It depends on the mass and speed of the car. We calculate it using the formula: \( KE_t = \frac{1}{2} m v^2 \), where \( m \) is the mass and \( v \) is the velocity of the car.
- Rotational Kinetic Energy: This is the energy stored in the spinning flywheel of the car. This type of energy is dependent on the moment of inertia and the angular velocity of the flywheel, and can be calculated using: \( KE_r = \frac{1}{2} I \omega^2 \).
Moment of Inertia
When a flywheel has a larger moment of inertia, it takes more energy to speed it up or slow it down. Think of it as a measure of how much the flywheel 'resists' changes in its motion.
This property is crucial because it defines how much rotational energy the flywheel stores, which can later be transferred to the car, affecting its speed along the floor.
In our case, to find the initial angular velocity, we used the equation \( KE_r = \frac{1}{2} I \omega^2 \) and related it to the energy calculation to back out the flywheel's rotational speed.
Angular Velocity
- Calculating Angular Velocity: We know that the rotational kinetic energy of the flywheel is \( KE_r = \frac{1}{2} I \omega^2 \). From this equation, we can find \( \omega \), the angular velocity, if we know how much energy is initially in the flywheel and its moment of inertia.
- Conversion of Energy: Angular velocity is important because it directly connects to how much rotational energy is availble to be transferred to the car’s motion. Here, solving for angular velocity using known values led us to \( \omega = 652 \text{ rad/s} \).
Scale Speed
To find scale speed:
- Identify the Scale Factor: This is the ratio of the real car length to the toy car length, here \( \frac{3.0 \text{ m}}{0.15 \text{ m}} = 20 \).
- Adjust the Speed: Multiply the toy car's actual speed by this scale factor to simulate how the toy car's speed would appear if it were car-sized. The exercise shows us this concept using a scale speed of 700 km/h.