Problem 59
Question
Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form $$\lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}$$ occur frequently in calculus. In Exercises \(57-62,\) evaluate this limit for the given value of \(x\) and function \(f\) . $$f(x)=3 x-4, \quad x=2$$
Step-by-Step Solution
Verified Answer
The value of the limit is 3.
1Step 1: Substitute the function and x-value
First, substitute the given function, \(f(x) = 3x - 4\), and the x-value, \(x = 2\), into the limit expression given by: \[ \lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h} \] This leads to \[ \lim _{h \rightarrow 0} \frac{(3(x+h) - 4) - (3x - 4)}{h} \] With \(x = 2\), the expression becomes: \[ \lim _{h \rightarrow 0} \frac{(3(2+h) - 4) - (3(2) - 4)}{h} \]
2Step 2: Simplify the expression inside the limit
Simplify the expression inside the limit: Start by expanding and simplifying the terms inside the numerator: \[ \lim _{h \rightarrow 0} \frac{(6 + 3h - 4) - (6 - 4)}{h} \] This simplifies to: \[ \lim _{h \rightarrow 0} \frac{2 + 3h - 2}{h} \] Which further simplifies to: \[ \lim _{h \rightarrow 0} \frac{3h}{h} \]
3Step 3: Evaluate the limit
Cancel \(h\) in the numerator and denominator, provided \(h eq 0\). The expression becomes: \[ \lim _{h \rightarrow 0} 3 \] Since the limit no longer depends on \(h\), evaluate it by direct substitution: \[ 3 \] This is the value of the limit.
Key Concepts
LimitsTangent LinesCalculus
Limits
Limits are a cornerstone concept in calculus that help us understand behavior as values approach a specific point. In this context, limits allow us to analyze how a function behaves as it nears a particular value, which is essential in determining derivatives and understanding rates of change.
When dealing with the expression \( \lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h} \), we're working with the limit that defines the derivative. It essentially represents the slope of the tangent line at a particular point on the function's graph. The goal is to evaluate the limit by observing what value the function approaches as \( h \) gets infinitely close to 0.
In our example, the simplification of the limit involves canceling terms to get \( \frac{3h}{h} \), where the \( h \) terms can be canceled out since \( h eq 0 \). After canceling, the expression simplifies directly to 3. Thus, the limit is determined to be 3 as \( h \) approaches 0.
When dealing with the expression \( \lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h} \), we're working with the limit that defines the derivative. It essentially represents the slope of the tangent line at a particular point on the function's graph. The goal is to evaluate the limit by observing what value the function approaches as \( h \) gets infinitely close to 0.
In our example, the simplification of the limit involves canceling terms to get \( \frac{3h}{h} \), where the \( h \) terms can be canceled out since \( h eq 0 \). After canceling, the expression simplifies directly to 3. Thus, the limit is determined to be 3 as \( h \) approaches 0.
Tangent Lines
Tangent lines play a vital role in calculus, particularly in understanding the geometry of curves. A tangent line at any given point runs in a direction that just "touches" the curve at that point, without crossing it.
The slope of a tangent line is what we derive using limits, specifically using the expression \( \lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h} \). This expression is the definition of a derivative, and when evaluated, it gives us the slope of the tangent line.
The slope of a tangent line is what we derive using limits, specifically using the expression \( \lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h} \). This expression is the definition of a derivative, and when evaluated, it gives us the slope of the tangent line.
- When a derivative is computed, it essentially gives the slope of the tangent line at a point \( x \).
- For linear functions, like \( f(x) = 3x - 4 \), the derivative comes out as a constant, because the slope does not change.
Calculus
Calculus, a branch of mathematics, is fundamentally concerned with change and motion. It provides us with tools to analyze how things evolve over time, covering a wide variety of topics like velocity, rates of change, and area under curves.
Two primary tools in calculus are derivatives and integrals:
Two primary tools in calculus are derivatives and integrals:
- Derivatives: They provide information about the rate of change of quantities. This is what we calculate using limits to find slopes of tangent lines.
- Integrals: Often thought of as the inverse process of differentiation, they are used to calculate the total accumulation of quantities, like area.
Other exercises in this chapter
Problem 59
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Find the limits in Exercises \(59-62\). $$\lim \left(\frac{1}{t^{3 / 5}}+7\right)\mathrm{as}$$ $$\text { a. }t \rightarrow 0^{+} \quad \text { b. } t \rightarro
View solution Problem 60
Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form $$\lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}$$ occur fre
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