Problem 59
Question
Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium.$$ A=\left[\begin{array}{rr} -1 & -1 \\ 5 & -3 \end{array}\right] $$
Step-by-Step Solution
Verified1Step 1: Identify the biological concept
Determine which biology area this addresses.
2Step 2: Recall relevant principles
Review key concepts.
3Step 3: Apply knowledge
Use biological reasoning.
4Step 4: State the answer
The answer is:
Key Concepts
Understanding EigenvaluesEquilibrium ClassificationThe Characteristic Equation
Understanding Eigenvalues
To analyze the stability of an equilibrium point in a system described by a matrix, one crucial step is to determine the eigenvalues of the matrix. An eigenvalue, represented typically by the Greek letter \( \lambda \), is a scalar that indicates how a vector associated with a transformation gets scaled. If you imagine each vector in the matrix as a direction, the eigenvalues tell us how much the vector grows or shrinks when the transformation is applied.
The process involves solving the characteristic equation of the matrix, which we will discuss in detail in the following section. Finding the correct eigenvalues is essential for understanding how the system behaves over time, especially at equilibrium points like \((0,0)\) in our matrix \( A \).
The process involves solving the characteristic equation of the matrix, which we will discuss in detail in the following section. Finding the correct eigenvalues is essential for understanding how the system behaves over time, especially at equilibrium points like \((0,0)\) in our matrix \( A \).
- Eigenvalues show the direction and stability behavior.
- They can be real or complex numbers.
- Their sign indicates whether the system is stable, unstable, or in a different state.
Equilibrium Classification
Equilibrium points in a system describe where the system can be at rest or unchanging over time. Once we have the eigenvalues, they help us to classify these points. This classification is based on their real parts and can tell us a lot about how the system behaves when it's at equilibrium.
In the context of linear systems, after identifying eigenvalues, equilibrium points are classified as:
In the context of linear systems, after identifying eigenvalues, equilibrium points are classified as:
- Stable Node: All eigenvalues have negative real parts.
- Unstable Node: Some eigenvalues have positive real parts.
- Saddle Point: Eigenvalues with both positive and negative real parts.
- Spiral or Center: Complex eigenvalues which may indicate a rotational behavior.
The Characteristic Equation
The characteristic equation is a fundamental concept in finding the eigenvalues of a matrix. It derives from the characteristic polynomial, formed by subtracting \( \lambda I \) from matrix \( A \), where \( I \) is the identity matrix, and setting the determinant of the resulting matrix to zero.
In our specific problem, we have the matrix \( A \) as:\[A = \begin{bmatrix} -1 & -1 \ 5 & -3 \end{bmatrix}\]and the identity matrix \( I \) for a 2x2 matrix:\[I = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\]Substituting \( A - \lambda I \) yields:\[A - \lambda I = \begin{bmatrix} -1 - \lambda & -1 \ 5 & -3 - \lambda \end{bmatrix}\]Then, the characteristic polynomial from the determinant \( \det(A - \lambda I) = \lambda^2 + 4\lambda + 2 = 0 \) is solved for \( \lambda \).
In our specific problem, we have the matrix \( A \) as:\[A = \begin{bmatrix} -1 & -1 \ 5 & -3 \end{bmatrix}\]and the identity matrix \( I \) for a 2x2 matrix:\[I = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\]Substituting \( A - \lambda I \) yields:\[A - \lambda I = \begin{bmatrix} -1 - \lambda & -1 \ 5 & -3 - \lambda \end{bmatrix}\]Then, the characteristic polynomial from the determinant \( \det(A - \lambda I) = \lambda^2 + 4\lambda + 2 = 0 \) is solved for \( \lambda \).
- The roots of this polynomial are the eigenvalues.
- It provides a mathematical foundation for understanding system stability.
- Simplifying and solving the polynomial is a key step in any stability analysis.
Other exercises in this chapter
Problem 57
Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium. $$ A=\left[\begin{array}{rr} -1 & -2 \\ 1 & 3 \end{array}\right] $$
View solution Problem 57
The Michaelis-Menten law [Equation (11.76)] states that $$ \frac{d p}{d t}=\frac{v_{m} s}{K_{m}+s} $$ where \(p=p(t)\) is the concentration of the product of th
View solution Problem 60
Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium. $$ A=\left[\begin{array}{ll} 2 & 2 \\ 2 & 3 \end{array}\right] $$
View solution Problem 61
Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium. $$ A=\left[\begin{array}{ll} 1 & 3 \\ 2 & 3 \end{array}\right] $$
View solution