Problem 59
Question
A \(14-\Omega\) coffee maker and a \(16-\Omega\) frying pan are connected in series across a \(120-\mathrm{V}\) source of voltage. A \(23-\Omega\) bread maker is also connected across the \(120-\mathrm{V}\) source and is in parallel with the series combination. Find the total current supplied by the source of voltage.
Step-by-Step Solution
Verified Answer
The total current supplied by the source is approximately 9.22 A.
1Step 1: Calculate the Series Resistance
When resistors are connected in series, the total resistance is the sum of their resistances. The coffee maker and frying pan are in series, so we sum their resistances: \[ R_{series} = 14 \, \Omega + 16 \, \Omega = 30 \, \Omega \]
2Step 2: Calculate the Total Resistance
The series combination is in parallel with the bread maker's resistance. For resistors in parallel, use:\[ \frac{1}{R_{total}} = \frac{1}{R_{series}} + \frac{1}{R_{bread}} \] Plug in the values,\[ \frac{1}{R_{total}} = \frac{1}{30 \, \Omega} + \frac{1}{23 \, \Omega} \]This gives:\[ \frac{1}{R_{total}} = \frac{23 + 30}{690} = \frac{53}{690} \]Thus,\[ R_{total} = \frac{690}{53} \approx 13.02 \, \Omega \]
3Step 3: Calculate the Total Current
Use Ohm's Law \( I = \frac{V}{R} \) to find the current. The voltage \( V \) across the source is 120 V. Using the total resistance from Step 2, substitute:\[ I = \frac{120 \, V}{13.02 \, \Omega} \approx 9.22 \, A \]
Key Concepts
Ohm's LawSeries and Parallel CircuitsResistance Calculation
Ohm's Law
Ohm's Law is a fundamental principle in electrical circuits. It relates the voltage ( \( V \) ), current ( \( I \) ), and resistance ( \( R \) ) in a circuit through the equation:
\[ I = \frac{V}{R} \] This equation tells us that the current flowing through a circuit is directly proportional to the voltage and inversely proportional to the resistance. When you know any two of these quantities, you can use Ohm's Law to find the third.
Using Ohm's Law is straightforward:
\[ I = \frac{V}{R} \] This equation tells us that the current flowing through a circuit is directly proportional to the voltage and inversely proportional to the resistance. When you know any two of these quantities, you can use Ohm's Law to find the third.
Using Ohm's Law is straightforward:
- If you increase the voltage in the circuit and keep the resistance constant, the current will increase.
- If the resistance increases while the voltage remains constant, the current will decrease.
Series and Parallel Circuits
When dealing with circuits made of multiple components, it's important to recognize whether they are arranged in series or parallel.
**Series Circuits:**In a series circuit, components are linked one after the other, forming a single path for the current to flow. In our exercise, the coffee maker and frying pan are in series. The total resistance for series circuits is simply the sum of the individual resistances:
\[ R_{series} = R_1 + R_2 + ... + R_n \]This means that an increase in any of these resistances will increase the total resistance, affecting the current.
**Parallel Circuits:**Parallel circuits, on the other hand, offer multiple pathways for the current. Components are connected across the same voltage source. The bread maker in the exercise is parallel to the series combination of the coffee maker and frying pan.
The formula for calculating total resistance in parallel circuits is:\[ \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n} \]As resistors are added in parallel, the total resistance decreases. Understanding how current and resistance work in these configurations helps in solving complex circuit problems.
**Series Circuits:**In a series circuit, components are linked one after the other, forming a single path for the current to flow. In our exercise, the coffee maker and frying pan are in series. The total resistance for series circuits is simply the sum of the individual resistances:
\[ R_{series} = R_1 + R_2 + ... + R_n \]This means that an increase in any of these resistances will increase the total resistance, affecting the current.
**Parallel Circuits:**Parallel circuits, on the other hand, offer multiple pathways for the current. Components are connected across the same voltage source. The bread maker in the exercise is parallel to the series combination of the coffee maker and frying pan.
The formula for calculating total resistance in parallel circuits is:\[ \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n} \]As resistors are added in parallel, the total resistance decreases. Understanding how current and resistance work in these configurations helps in solving complex circuit problems.
Resistance Calculation
Calculating resistance is a key step in understanding how circuits behave. By being able to calculate total resistance, we can determine how much current will flow in a circuit given a certain voltage.
In the example provided, the coffee maker and frying pan create a combined resistance:
For parallel calculations:
In the example provided, the coffee maker and frying pan create a combined resistance:
- The sum of their resistances ( \( 14 \Omega + 16 \Omega \) ) is \( 30 \Omega \) .
- This forms a series resistance.
For parallel calculations:
- Use the reciprocal formula, \( \frac{1}{R_{total}} = \frac{1}{R_{series}} + \frac{1}{R_{bread}} \) , to find the total equivalent resistance.
- This gives us a total resistance of approximately \( 13.02 \Omega \) .
Other exercises in this chapter
Problem 56
A cylindrical aluminum pipe of length \(1.50 \mathrm{~m}\) has an inner radius of \(2.00 \times 10^{-3} \mathrm{~m}\) and an outer radius of \(3.00 \times 10^{-
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The rear window defogger of a car consists of thirteen thin wires (resistivity \(\left.=88.0 \times 10^{-8} \Omega \cdot \mathrm{m}\right\\}\) embedded in the g
View solution Problem 62
A \(60.0-\Omega\) resistor is connected in parallel with a \(120-\Omega\) resistor. This parallel group is connected in series with a \(20.0-\Omega\) resistor.
View solution Problem 66
Three identical resistors are connected in parallel. The equivalent resistance increases by \(700-\Omega\) when one resistor is removed and connected in series
View solution