Problem 58
Question
Write the general form of the equation of the line that passes through the points. $$(-6,1),(4,-5)$$
Step-by-Step Solution
Verified Answer
The general form of the line that passes through the points (-6,1) and (4,-5) is \(3x + 5y = -13\).
1Step 1: Calculate the Slope of the Line
The formula for calculating the slope (m) of a line given two points \((x_1, y_1)\) and \((x_2, y_2)\) is\[m = \frac{{y_2 - y_1}}{{x_2 - x_1}}\]So, with the points (-6,1) and (4,-5), substitute into the formula and get\[m = \frac{{-5 - 1}}{{4 - (-6)}} = -\frac{6}{10} = -\frac{3}{5}\]
2Step 2: Use Point-Slope Form and Convert to General Form
The point-slope form of a line is given by\[y - y_1 = m(x - x_1)\]Here, substitute \((x_1, y_1)\) with one of the given points, let's say (-6,1), and m=-3/5. This gives\[y - 1 = -\frac{3}{5}(x + 6)\]. To convert it to the general form \[Ax + By = C\], clear out the fractions and simplify the equation: \(5y - 5 = -3x - 18\), which simplifies further to \(3x + 5y = -13\).
Key Concepts
Slope CalculationPoint-Slope FormGeneral Form of Linear Equation
Slope Calculation
Understanding how to calculate the slope of a line is important when working with linear equations. The slope, often denoted as \(m\), represents the steepness or incline of a line. It tells us how far and in what direction the line moves between two points. To find the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\), use the formula:\[m = \frac{{y_2 - y_1}}{{x_2 - x_1}}\]Here, the difference in the \(y\)-coordinates (\(y_2 - y_1\)) is divided by the difference in the \(x\)-coordinates (\(x_2 - x_1\)). This ratio gives us the slope.
- In our example, using points \((-6,1)\) and \((4,-5)\), the calculation becomes \(m = \frac{-5 - 1}{4 - (-6)} = -\frac{6}{10} = -\frac{3}{5}\).
- The negative sign indicates the line slopes downwards as we move from left to right.
Point-Slope Form
The point-slope form of a line's equation offers a straightforward way to write the equation when you know a point on the line and its slope. The formula is expressed as:\[y - y_1 = m(x - x_1)\]This is handy because it incorporates a specific point, \((x_1, y_1)\), directly into the equation along with the slope \(m\).
- In our case, we can choose the point \((-6, 1)\) and use the slope \(-\frac{3}{5}\) to produce the equation: \(y - 1 = -\frac{3}{5}(x + 6)\).
- This format is especially useful because of its simplicity and how easily you can rearrange it into other forms, such as the general form.
General Form of Linear Equation
The general form of a linear equation is a more standardized way of representing a line, written as \(Ax + By = C\). Here, \(A\), \(B\), and \(C\) are constants.
To convert from point-slope to this form, focus on expanding and simplifying the equation. Consider the point-slope form \(y - 1 = -\frac{3}{5}(x + 6)\).
To convert from point-slope to this form, focus on expanding and simplifying the equation. Consider the point-slope form \(y - 1 = -\frac{3}{5}(x + 6)\).
- First, clear the fraction by multiplying through by 5, giving us \(5(y - 1) = -3(x + 6)\).
- Simplify to find \(5y - 5 = -3x - 18\).
- Rearrange to get all terms involving variables on one side: \(3x + 5y = -13\).
Other exercises in this chapter
Problem 57
Find two quadratic functions, one that opens upward and one that opens downward, whose graphs have the given \(x\) -intercepts. (There are many correct answers.
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Find all the real zeros of the polynomial function. Determine the multiplicity of each zero. Use a graphing utility to verify your results. \(f(x)=\frac{1}{2} x
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Write the polynomial (a) as the product of factors that are irreducible over the rationals, (b) as the product of linear and quadratic factors that are irreduci
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Find two quadratic functions, one that opens upward and one that opens downward, whose graphs have the given \(x\) -intercepts. (There are many correct answers.
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