Problem 58
Question
Which of the following sets has the strongest tendency to form anions? (a) \(\mathrm{V}, \mathrm{Cr}, \mathrm{Mn}\) (b) \(\mathrm{N}, \mathrm{O}, \mathrm{F}\) (c) \(\mathrm{Ga}, \mathrm{In}, \mathrm{Tl}\) (d) \(\mathrm{Na}, \mathrm{Mg}, \mathrm{Al}\)
Step-by-Step Solution
Verified Answer
The set \( \mathrm{N, O, F} \) has the strongest tendency to form anions.
1Step 1: Recognize Element Properties
First, identify the major property linked to the tendency of elements to form anions: high electronegativity. Elements with high electronegativity have a stronger pull on electrons and, thus, a greater tendency to form anions.
2Step 2: Analyze Set (a)
Consider the elements V (Vanadium), Cr (Chromium), and Mn (Manganese). These are transition metals, which typically do not have a strong tendency to form anions due to their lower electronegativity compared to nonmetals.
3Step 3: Analyze Set (b)
Look at the elements N (Nitrogen), O (Oxygen), and F (Fluorine). These are nonmetals with high electronegativity values. Fluorine is the most electronegative element and has the strongest tendency to form anions, followed by oxygen and nitrogen.
4Step 4: Analyze Set (c)
Review the elements Ga (Gallium), In (Indium), and Tl (Thallium). These elements are metals with relatively low electronegativity, hence they do not have a strong tendency to form anions.
5Step 5: Analyze Set (d)
Check the elements Na (Sodium), Mg (Magnesium), and Al (Aluminum). These are metals with low electronegativity, especially when compared to nonmetals. They are more likely to form cations than anions.
6Step 6: Compare and Decide
Compare all sets observed. Set (b) with elements N, O, and F consists of nonmetals with the highest electronegativity values, indicating a strong tendency to form anions. Therefore, set (b) is the answer.
Key Concepts
Anion FormationNonmetalsPeriodic Table Trends
Anion Formation
Anions are negatively charged ions formed when an atom gains one or more electrons. This process is particularly favorable for elements with high electronegativity. Electronegativity refers to an atom’s ability to attract and hold onto electrons.
Elements most likely to form anions include nonmetals. Their atoms have a high affinity for electrons, enabling them to form stable anions by completing their outer electron shells.
Elements most likely to form anions include nonmetals. Their atoms have a high affinity for electrons, enabling them to form stable anions by completing their outer electron shells.
- When nonmetals, such as fluorine, gain electrons, they fill their outer shell, achieving a more stable, noble gas electronic configuration. This process of electron gain results in anions.
- This is in contrast to metals, which generally form cations by losing electrons due to their lower electronegativity values.
Nonmetals
Nonmetals are elements typically found on the right side of the periodic table. They possess several unique properties that distinguish them from metals.
Primarily, nonmetals have high electronegativity and ionization energy, which makes them more likely to gain electrons during chemical reactions.
Primarily, nonmetals have high electronegativity and ionization energy, which makes them more likely to gain electrons during chemical reactions.
- Common nonmetals that readily form anions are elements like nitrogen (N), oxygen (O), and fluorine (F). These elements have almost full outer electron shells, and need only a few additional electrons to achieve a stable form.
- This strong tendency to gain electrons results from their desire to attain a complete valence shell, similar to the stable configuration of noble gases.
Periodic Table Trends
The periodic table is a powerful tool that helps us understand the behavior of elements, including their tendency to form anions.
A key trend to note is how electronegativity changes across the table:
A key trend to note is how electronegativity changes across the table:
- As you move from left to right across a period, electronegativity increases. This explains why elements like fluorine, close to the noble gases on the right, are highly electronegative.
- As you move down a group, electronegativity decreases. This is because additional electron shells added in each new period increase the distance between the nucleus and outermost electrons, reducing the effective nuclear charge experienced by these electrons.
Other exercises in this chapter
Problem 56
Which one of the following elements does not form the compound, \(\mathrm{M}_{4} \mathrm{O}_{10}(\mathrm{M}=\) element \() ?\) (a) As (b) \(\mathrm{Bi}\) (c) \(
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Which of the following bonds will be mostpolar? (a) \(\mathrm{O}-\mathrm{F}\) (b) \(\mathrm{N}-\mathrm{F}\) (c) \(\mathrm{N}-\mathrm{N}\) (d) \(\mathrm{N}-\math
View solution Problem 59
Which one of the following statements is correct with respect to the basic character? (a) \(\mathrm{PH}_{3}=\mathrm{NH}_{3}\) (b) \(\mathrm{PH}_{3}>\mathrm{P}\l
View solution Problem 62
Which of the following has the least bond energy? (a) \(\mathrm{H}_{2}\) (b) \(\mathrm{F}_{2}\) (c) \(\mathrm{O}_{2}^{2}\) (d) \(\mathrm{N}_{2}\)
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