Problem 58
Question
Verify that each equation is an identity. $$\frac{\tan (A+B)-\tan B}{1+\tan (A+B) \tan B}=\tan A$$
Step-by-Step Solution
Verified Answer
The given equation is an identity: the equation reduces to \( \tan A \).
1Step 1: Recall tangent sum formula
First, we need to recall the tangent sum formula. The formula for \( \tan(A+B) \) is: \[ \tan(A+B) = \frac{\tan A + \tan B}{1 - \tan A \tan B} \]. We will use this formula to simplify \( \tan(A+B) \) in the given expression.
2Step 2: Substitute the tangent sum formula into the equation
Substitute \( \tan(A+B) \) with \( \frac{\tan A + \tan B}{1 - \tan A \tan B} \) in the equation: \[ \frac{\frac{\tan A + \tan B}{1 - \tan A \tan B} - \tan B}{1 + \frac{\tan A + \tan B}{1 - \tan A \tan B} \cdot \tan B} = \tan A \].
3Step 3: Simplify the numerator of the fraction
Now focus on the numerator of the expression: \[ \frac{\tan A + \tan B}{1 - \tan A \tan B} - \tan B \]. Simplify it to get: \[ \frac{\tan A + \tan B - \tan B (1 - \tan A \tan B)}{1 - \tan A \tan B} = \frac{\tan A + \tan B - \tan B + \tan B \tan A \tan B}{1 - \tan A \tan B} \]. The simplification gives us: \[ \frac{\tan A (1+\tan^2 B)}{1 - \tan A \tan B} \].
4Step 4: Simplify the denominator of the fraction
Next, simplify the denominator: \[ 1 + \frac{\tan A + \tan B}{1 - \tan A \tan B} \tan B \]. This becomes \[ \frac{1 - \tan A \tan B + (\tan A + \tan B) \tan B}{1 - \tan A \tan B} \], which simplifies to \[ \frac{1 - \tan A \tan B + \tan A \tan B + \tan^2 B}{1 - \tan A \tan B} = \frac{1 + \tan^2 B}{1 - \tan A \tan B} \].
5Step 5: Verify the identity
Now plug the simplified numerator and denominator back into the main fraction: \[ \frac{\frac{\tan A (1+\tan^2 B)}{1 - \tan A \tan B}}{\frac{1 + \tan^2 B}{1 - \tan A \tan B}} = \tan A \]. On simplifying, this equates to \[ \frac{\tan A (1+\tan^2 B)}{1 + \tan^2 B} = \tan A \]. Indeed, this simplifies to \( \tan A \), verifying that the original expression is an identity.
Key Concepts
Tangent FunctionAngle Sum FormulasIdentity Verification
Tangent Function
The tangent function is one of the basic trigonometric functions, alongside sine and cosine. When dealing with right triangles, the tangent of an angle represents the ratio of the opposite side to the adjacent side:
Furthermore, in the unit circle approach, tangent can be understood as the y-coordinate divided by the x-coordinate of a point on the unit circle corresponding to an angle \( \theta \). This relationship opens up deeper trigonometric identities and properties useful in solving equations and verifying identities in trigonometry.
The tangent function plays a crucial role when investigating properties such as periodicity and symmetry, and it is especially important in calculus when considering derivatives and integrals of trigonometric functions.
- Opposite Side: The side opposite to the angle in question.
- Adjacent Side: The side next to the angle, forming a right-angled triangle, excluding the hypotenuse.
Furthermore, in the unit circle approach, tangent can be understood as the y-coordinate divided by the x-coordinate of a point on the unit circle corresponding to an angle \( \theta \). This relationship opens up deeper trigonometric identities and properties useful in solving equations and verifying identities in trigonometry.
The tangent function plays a crucial role when investigating properties such as periodicity and symmetry, and it is especially important in calculus when considering derivatives and integrals of trigonometric functions.
Angle Sum Formulas
The angle sum formulas are crucial for adding or subtracting angles in trigonometry. Specifically, the formula for the tangent of a sum of two angles \( A \) and \( B \) is:
\[\tan(A+B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}.\]This formula is particularly useful when you need to express the tangent of a sum in terms of individual tangents.
These sum formulas reveal that the tangent of an angle is not simply the sum of the tangents but involves a complex interaction of multiple angles.
When verifying identities or solving equations involving
\[\tan(A+B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}.\]This formula is particularly useful when you need to express the tangent of a sum in terms of individual tangents.
These sum formulas reveal that the tangent of an angle is not simply the sum of the tangents but involves a complex interaction of multiple angles.
When verifying identities or solving equations involving
- angles of 90 degrees apart
- complicated sum differences
Identity Verification
Identity verification in trigonometry involves proving that two trigonometric expressions are equivalent under all permissible conditions. This requires strategic manipulations using known identities and algebraic rules.
For example, in the given exercise, our goal is to prove the equation
Throughout the verification process, it's vital to identify and match similar terms through cancellation or strategic factoring. By the end, the left side must simplify entirely to the right side, confirming the expression as an identity. Identity verification builds foundational skills in formal mathematical proofs and ensures comprehension of trigonometric functions beyond simple computations.
For example, in the given exercise, our goal is to prove the equation
- \(\frac{\tan (A+B)-\tan B}{1+\tan (A+B) \tan B}=\tan A\)
Throughout the verification process, it's vital to identify and match similar terms through cancellation or strategic factoring. By the end, the left side must simplify entirely to the right side, confirming the expression as an identity. Identity verification builds foundational skills in formal mathematical proofs and ensures comprehension of trigonometric functions beyond simple computations.
Other exercises in this chapter
Problem 57
Give solutions over the interval \([0,2 \pi)\) as approximations to the nearest hundredth when exact values cannot be determined. You may need to use the quadra
View solution Problem 57
Write expression in terms of sine and cosine, and simplify it. (The final expression does not have to be in terms of sine and cosine.) $$\sin \theta(\csc \theta
View solution Problem 58
Use a calculator to give each real-number value of \(y .\) $$y=\arccos 0.44624593$$
View solution Problem 58
Use an identity to write each expression as a single trigonometric function value. $$\frac{\sin 158.2^{\circ}}{1+\cos 158.2^{\circ}}$$
View solution