Problem 58
Question
Transform the equation \(x^{1 / 2}+y^{1 / 2}=a^{1 / 2}\) by a rotation of axes through \(45^{\circ}\) and then square twice to eliminate radicals on variables. Identify the corresponding curve.
Step-by-Step Solution
Verified Answer
The transformed equation represents a hyperbola.
1Step 1: Formulate the rotation transformation
To rotate the coordinate system by \(45^{\circ}\), we use the transformation formulas: \( x = X \cos(\theta) - Y \sin(\theta) \) and \( y = X \sin(\theta) + Y \cos(\theta) \). For a \(45^{\circ}\) rotation, \(\cos(45^\circ) = \sin(45^\circ) = \frac{\sqrt{2}}{2}\). Therefore, the equations become: \( x = \frac{\sqrt{2}}{2}(X - Y) \) and \( y = \frac{\sqrt{2}}{2}(X + Y) \).
2Step 2: Substitute the new variables
Substitute the rotated coordinates into the original equation: \( \left(\frac{\sqrt{2}}{2}(X - Y)\right)^{1/2} + \left(\frac{\sqrt{2}}{2}(X + Y)\right)^{1/2} = a^{1/2} \). Simplifying inside the roots gives: \( \sqrt{\frac{\sqrt{2}}{2}} (X - Y)^{1/2} + \sqrt{\frac{\sqrt{2}}{2}} (X + Y)^{1/2} = a^{1/2} \).
3Step 3: Simplify the expression
Recognize that \( \sqrt{\frac{\sqrt{2}}{2}} = \left(\frac{\sqrt{2}}{2}\right)^{1/4} \). This simplifies the expression to: \( \left(\frac{1}{\sqrt[4]{2}}\right) (X - Y)^{1/2} + \left(\frac{1}{\sqrt[4]{2}}\right) (X + Y)^{1/2} = a^{1/2} \). Factor out \( \frac{1}{\sqrt[4]{2}} \) to get: \( \frac{1}{\sqrt[4]{2}}((X - Y)^{1/2} + (X + Y)^{1/2}) = a^{1/2} \).
4Step 4: Eliminate single radical by squaring
Square both sides to remove the first radical: \( \left((X - Y)^{1/2} + (X + Y)^{1/2}\right)^2 = (a^{1/2} \cdot \sqrt[4]{2})^2 \). This simplifies to: \( X - Y + X + Y + 2\sqrt{(X-Y)(X+Y)} = a^{1/2} \cdot 2 \), resulting in \( 2X + 2\sqrt{X^2 - Y^2} = a^{1/2} \cdot 2 \).
5Step 5: Square again to remove final radicals
Now, solve for \( \sqrt{X^2 - Y^2} \) and square both sides again to eliminate the remaining radical:\( (a^{1/2} - 2X) = 2\sqrt{X^2 - Y^2} \) becomes \( \left(a^{1/2} - 2X\right)^2 = 4(X^2 - Y^2) \). Expand and simplify: \( (a - 4a^{1/2}X + 4X^2) = 4X^2 - 4Y^2 \).
6Step 6: Bring to a standard form
Reorganize the equation to find its relationship: \( a - 4a^{1/2}X = -4Y^2 \) or \( 4Y^2 = -a + 4a^{1/2}X \). Simplifying gives an equation of a hyperbola.
Key Concepts
Rotation of AxesElimination of RadicalsHyperbola Identification
Rotation of Axes
Rotating the axes is a vital mathematical technique often used to simplify complex equations. When you rotate the axes, you're essentially modifying the coordinate system to obtain a new perspective that might be easier to work with. In the context of this exercise, we rotate the axes by \( 45^{\circ} \). This involves applying transformation formulas:
- \( x = X \cos(\theta) - Y \sin(\theta) \)
- \( y = X \sin(\theta) + Y \cos(\theta) \)
- \( x = \frac{\sqrt{2}}{2}(X - Y) \)
- \( y = \frac{\sqrt{2}}{2}(X + Y) \)
Elimination of Radicals
Eliminating radicals is a common strategy to simplify equations, transforming them from their complex form into something more tangible. Radicals, like square roots, can often make equations unwieldy. In this exercise, our goal was to remove these radicals to simplify the expression.
Initially, we squared both sides of the equation to ease out the first layer of radicals:
\[\left((X - Y)^{1/2} + (X + Y)^{1/2}\right)^2 = (a^{1/2} \cdot \sqrt[4]{2})^2\]This first operation simplifies the equation but doesn't completely rid us of radicals. We are left with:
\[2X + 2\sqrt{X^2 - Y^2} = a^{1/2} \cdot 2\]To eradicate the remaining radical, we square once more. This additional step gives us:\[\left(a^{1/2} - 2X\right)^2 = 4(X^2 - Y^2)\]Through these logical steps, we effectively eliminate radicals, paving the way for a clearer form of the equation that helps in further mathematical manipulations.
Initially, we squared both sides of the equation to ease out the first layer of radicals:
\[\left((X - Y)^{1/2} + (X + Y)^{1/2}\right)^2 = (a^{1/2} \cdot \sqrt[4]{2})^2\]This first operation simplifies the equation but doesn't completely rid us of radicals. We are left with:
\[2X + 2\sqrt{X^2 - Y^2} = a^{1/2} \cdot 2\]To eradicate the remaining radical, we square once more. This additional step gives us:\[\left(a^{1/2} - 2X\right)^2 = 4(X^2 - Y^2)\]Through these logical steps, we effectively eliminate radicals, paving the way for a clearer form of the equation that helps in further mathematical manipulations.
Hyperbola Identification
Identifying the type of conic section represented by an equation is crucial in understanding geometric properties. A hyperbola is a specific type of conic section characterized by its distinct open curves.
In this problem, once the radicals were eliminated, the equation simplified to reveal itself as a hyperbola:
\[4Y^2 = -a + 4a^{1/2}X\]The general equation for a hyperbola is typically seen as:
By breaking down the transformed and simplified equation, the structure of the equation as a hyperbola becomes apparent. This reveals fascinating aspects of the curve's asymptotic nature and how it opens up along the axes, boosting comprehension of the geometric form it takes.
In this problem, once the radicals were eliminated, the equation simplified to reveal itself as a hyperbola:
\[4Y^2 = -a + 4a^{1/2}X\]The general equation for a hyperbola is typically seen as:
- \( Ax^2 - By^2 = C \)
By breaking down the transformed and simplified equation, the structure of the equation as a hyperbola becomes apparent. This reveals fascinating aspects of the curve's asymptotic nature and how it opens up along the axes, boosting comprehension of the geometric form it takes.
Other exercises in this chapter
Problem 57
The graph of \(x \cos \alpha+y \sin \alpha=d\) is a line. Show that the perpendicular distance from the origin to this line is \(|d|\) by making a rotation of a
View solution Problem 58
The path of a projectile fired from level ground with a speed of \(v_{0}\) feet per second at an angle \(\alpha\) with the ground is given by the parametric equ
View solution Problem 59
Find the dimensions of the rectangle having the greatest possible area that can be inscribed in the ellipse \(b^{2} x^{2}+a^{2} y^{2}=a^{2} b^{2}\). Assume that
View solution Problem 61
Find the point in the first quadrant where the two hyperbolas \(25 x^{2}-9 y^{2}=225\) and \(-25 x^{2}+18 y^{2}=450\) intersect.
View solution