Problem 58
Question
The ionization of the hydrogen atom can be calculated from Bohr's equation for the electron energy. $$ E=-(N R h c)\left(Z^{2} / n^{2}\right) $$ where \(N R h c=1312 \mathrm{kJ} / \mathrm{mol}\) and \(Z\) is the atomic number. Let us use this approach to calculate a possible ionization energy for helium. First, assume the electrons of the He experience the full \(2+\) nuclear charge. This gives us the upper limit for the ionization energy. Next, assume one electron of He completely screens the nuclear charge from the other electrons, so \(Z=1 .\) This gives us a lower limit to the ionization energy. Compare these calculated values for the upper and lower limits to the experimental value of \(2372.3 \mathrm{kJ} / \mathrm{mol} .\) What does this tell us about the ability of one electron to screen the nuclear charge?
Step-by-Step Solution
VerifiedKey Concepts
Ionization Energy
- It determines chemical reactivity. Atoms with high ionization energy, like noble gases, tend to be less reactive.
- It helps in predicting the bond formation between atoms. Lower ionization energy usually indicates a higher likelihood of forming positive ions (cations).
Hydrogen Atom
- Discrete energy levels or orbits where the electron can exist without radiating energy.
- Movement of electrons between orbits, correlating with absorption or emission of specific quantized energy.
- Application in calculating energy states via Bohr's equation, as seen in this exercise.
Atomic Number
- It defines the electric charge of the nucleus, hence influencing the pull on electrons.
- It's crucial for calculating ionization energy through Bohr's equation, as seen where \(Z\) influences the energy value for ionization.
- Understanding \(Z\) enables insights into how atoms of different elements behave chemically and physically.
Screening Effect
- Inner electrons acting as a shield between the nucleus and outer electrons, reducing the net positive charge felt by outer electrons.
- Influencing ionization energies by effectively lowering the attractive force on valence electrons, making them easier to remove.