Problem 58
Question
The function \(f(x)\) is defined in \([0,1]\), then the domain of definition of the function \(f\left[\log \left(1-x^{2}\right)\right]\), is (A) \(x \in\\{0\\}\) (B) \(x \in[-\sqrt{1+e},-1] \cup[1,+\sqrt{1+e}]\) (C) \(x \in(-\infty, \infty)\) (D) None of these
Step-by-Step Solution
Verified Answer
(D) None of these
1Step 1: Understand the Inside Function
Consider the function inside the brackets: \( \log(1-x^2) \). This function is defined only when its argument is positive, i.e., \(1-x^2 > 0\). We need to determine the values of \(x\) for which this inequality holds true.
2Step 2: Solve the Inequality
Solve the inequality \(1-x^2 > 0\). This simplifies to \(x^2 < 1\). Solving this inequality for \(x\) gives \(|x| < 1\). Hence, \(x\) must belong to the open interval \((-1, 1)\).
3Step 3: Relate to Function Domain
We're given that \(f(x)\) is defined on \([0, 1]\). Therefore, the domain of \(f[\log(1-x^2)]\) will be the intersection of \(x \in (0, 1)\) coming from step 2 and \([0, 1]\) coming from the definition of \(f(x)\).
4Step 4: Find the Domain of Function
The intersection of \((0, 1)\) with \([0, 1]\) is \((0, 1)\). Thus, the valid domain for the entire function \(f[\log(1-x^2)]\) is \(x \in (0, 1)\).
5Step 5: Verify With Options
Review the given options. None of the options specifically list \(x \in (0, 1)\). Hence, none of the provided options are correct.
Key Concepts
Logarithmic FunctionInequalityInterval Notation
Logarithmic Function
Logarithmic functions are an essential part of understanding many mathematical concepts. They are the inverse of exponential functions, meaning they "undo" exponential growth. If we say that a number is expressed as an exponent of a base, logarithms determine the power to which the base is raised to yield that number. For instance, in a logarithmic function like \( \log_b(x) \), \( b \) is the base, and we find the power needed to raise \( b \) to obtain \( x \).
Understanding Logarithmic Functions:
Understanding Logarithmic Functions:
- The domain of a logarithmic function \( \log_b(x) \) is all positive numbers because you can only take the logarithm of positive values.
- The base, \( b \), must be a positive number and cannot equal 1.
- A logarithmic function like \( \log(1-x^2) \) requires that \( 1-x^2 > 0 \) because the input must be greater than zero for the log function to be defined.
Inequality
In mathematics, inequalities are used to compare expressions or numbers. These comparisons allow us to find ranges of values for which certain expressions are valid. Inequalities use symbols such as "<" or ">" to describe the relationship between values.
Key Points about Inequalities:
Key Points about Inequalities:
- Inequalities can be linear or non-linear. A linear inequality is a first-degree relation between variables, as in \( 1 - x^2 > 0 \).
- Solving a quadratic inequality like \( 1 - x^2 > 0 \) involves finding when the expression is greater than zero. This typically requires finding the roots and testing intervals between and beyond these roots.
- For the inequality \( 1 - x^2 > 0 \), solving it gives \( |x| < 1 \), meaning the range of values for \( x \) lies between \(-1\) and \(1\).
- By comprehending inequalities, you can set the bounds for functions and evaluate which values make them valid.
Interval Notation
Interval notation is a convenient and compact way to describe a set of numbers that lie between two endpoints on the number line. It's especially useful for representing solutions to inequalities and the domains of functions.
Understanding Interval Notation:
Understanding Interval Notation:
- Intervals can be open \((a, b)\), closed \([a, b]\), or half-open/half-closed \((a, b]\) or \([a, b)\). The parentheses \(()\) indicate that the endpoints are not included, while square brackets \([]\) mean the endpoints are included.
- For example, the interval \((0, 1)\) indicates all real numbers between 0 and 1 but does not include 0 and 1 themselves.
- In the context of the exercise, the domain for \( f[\log(1-x^2)] \) after considering the intersection of constraints was \((0, 1)\), highlighting that \( x \) must be strictly greater than 0 and less than 1.
Other exercises in this chapter
Problem 56
A function \(f\) from the set of natural numbers to integers defined by, $$ f(n)= \begin{cases}\frac{n-1}{2}, & \text { when } n \text { is odd } \\\ -\frac{n}{
View solution Problem 57
If \(\alpha \in\left(0, \frac{\pi}{2}\right)\) then \(\sqrt{x^{2}+x}+\frac{\tan ^{2} \alpha}{\sqrt{x^{2}+x}}\) is always greater than or equal to (A) \(2 \tan \
View solution Problem 59
If \(f: R \rightarrow S\), defined by \(f(x)=\sin x-\sqrt{3} \cos x+1\), is onto then the interval of \(S\) is (A) \([-1,3]\) (B) \([-1,1]\) (C) \([0,1]\) (D) \
View solution Problem 60
If \(a\) and \(b\) are natural numbers and \(f(x)=\sin \left(\sqrt{a^{2}-3}\right) x+\cos \left(\sqrt{b^{2}+7}\right) x\) is periodic with finite fundamental pe
View solution