Problem 58
Question
Solve for \(x\). See Example 3 . $$ \log _{3} x=-4 $$
Step-by-Step Solution
Verified Answer
\(x = \frac{1}{81}\).
1Step 1: Understand the Logarithm Equation
The given equation is \(\log_{3} x = -4\). This equation asks which power of 3 gives \(x\).
2Step 2: Convert Logarithmic Form to Exponential Form
To solve the equation \(\log_{3} x = -4\), convert it into its exponential form using the property: \(\log_{b} a = c\) implies \(b^c = a\). Here, \(b = 3\), \(a = x\), and \(c = -4\). Thus, the equation becomes \(3^{-4} = x\).
3Step 3: Calculate the Exponential Expression
Now calculate \(3^{-4}\). This means taking the reciprocal of 3 raised to the power of 4, as negative exponent indicates reciprocal: \(3^{-4} = \frac{1}{3^4}\).
4Step 4: Compute Powers
Compute \(3^4\), which is \(3 \times 3 \times 3 \times 3 = 81\). Thus, \(3^{-4} = \frac{1}{81}\).
5Step 5: Write the Solution
From the previous steps, we found that \(x = \frac{1}{81}\). This is the solution to the equation \(\log_{3} x = -4\).
Key Concepts
Exponential FormNegative ExponentsPowers of Numbers
Exponential Form
The concept of exponential form is a cornerstone in understanding logarithms. When we express a logarithmic equation in exponential form, we uncover the "secret" life of the equation by showing its power base structure.
In simpler terms:
Thus, the process of converting a logarithmic equation to an exponential form is like shifting perspectives from "what power of this number...?” to "this number raised to this power gives...".
In simpler terms:
- A logarithm like \( \log_b a = c \) translates to \( b^c = a \). This means the base \( b \) raised to the power of \( c \) equals \( a \).
- It's turning a logarithm back into its exponential "story".
Thus, the process of converting a logarithmic equation to an exponential form is like shifting perspectives from "what power of this number...?” to "this number raised to this power gives...".
Negative Exponents
Negative exponents might seem a bit mysterious at first, but they are quite straightforward once you familiarize yourself with them. They provide a clever way to express reciprocals.
Here's how they work:
Understanding negative exponents is vital because they frequently appear in equations and functions. Mastering them unlocks the ability to solve not just logarithmic, but also many types of algebraic problems.
Here's how they work:
- A negative exponent like \( b^{-n} \) means \( \frac{1}{b^n} \).
- It's like flipping the base to the denominator and then raising it to the positive exponent.
Understanding negative exponents is vital because they frequently appear in equations and functions. Mastering them unlocks the ability to solve not just logarithmic, but also many types of algebraic problems.
Powers of Numbers
Powers of numbers is a fundamental concept in both algebra and the broader scope of mathematics. Powers are used to express repeated multiplication succinctly.
Let's break it down:
It's useful in contexts ranging from simple arithmetic to complex scientific calculations. In solutions like the one provided, accurately calculating the power \( 3^4 \) was key in determining the exact value of \( x = \frac{1}{81} \).
With this skill, you can tackle various mathematical challenges, providing a solid base for further studies in mathematics.
Let's break it down:
- When you see \( b^n \), it means multiplying the base \( b \) by itself \( n \) times.
- In our equation, \( 3^4 \) is calculated as \( 3 \times 3 \times 3 \times 3 \), which results in 81.
It's useful in contexts ranging from simple arithmetic to complex scientific calculations. In solutions like the one provided, accurately calculating the power \( 3^4 \) was key in determining the exact value of \( x = \frac{1}{81} \).
With this skill, you can tackle various mathematical challenges, providing a solid base for further studies in mathematics.
Other exercises in this chapter
Problem 58
Solve each equation. See Example \(9 .\) $$ \log 11-\log x=2 $$
View solution Problem 58
Let \(f(x)=3 x-2\) and \(g(x)=x^{2}+x .\) Find each of the following. $$ (g \circ f)(4) $$
View solution Problem 58
Show that each pair of functions are inverses. \(f(x)=\sqrt[3]{x-6}, f^{-1}(x)=x^{3}+6\)
View solution Problem 58
Write logarithm without an exponent or a radical symbol. Then simplify, if possible. \(\log _{3}(\sqrt{10})^{5}\)
View solution