Problem 58
Question
Show that the equation is not an Identity. $$\sin (t+\pi)=\sin t$$
Step-by-Step Solution
Verified Answer
The equation \( \sin(t + \pi) = \sin t \) is not an identity because it simplifies to \( \sin(t + \pi) = -\sin t \).
1Step 1: Recall the Sine Addition Formula
The identity for the sine of a sum can be given by the formula \( \sin(a + b) = \sin a \cos b + \cos a \sin b \). In this exercise, we will use \( a = t \) and \( b = \pi \).
2Step 2: Apply the Sine Addition Formula
Substitute \( a = t \) and \( b = \pi \) into the sine addition formula. We get \( \sin(t + \pi) = \sin t \cos \pi + \cos t \sin \pi \).
3Step 3: Evaluate Trigonometric Values
Recall that \( \cos \pi = -1 \) and \( \sin \pi = 0 \). Substitute these values into the equation: \( \sin(t + \pi) = \sin t \times (-1) + \cos t \times 0 \).
4Step 4: Simplification
After substitution, the equation simplifies to \( \sin(t + \pi) = -\sin t \).
5Step 5: Compare Both Sides of the Equation
The original equation \( \sin(t + \pi) = \sin t \) is not equivalent to \( \sin(t + \pi) = -\sin t \), thus showing they are not identical. Therefore, the given equation is not an identity.
Key Concepts
Sine Addition FormulaTrigonometric FunctionsSine FunctionEquivalence of Trigonometric Expressions
Sine Addition Formula
The sine addition formula is a fundamental identity in trigonometry that combines the sine of two angles into a single expression. It states:
- \( \sin(a + b) = \sin a \cos b + \cos a \sin b \).
Trigonometric Functions
Trigonometric functions are mathematical functions that relate angles to the ratios of the sides of a right triangle. There are six main trigonometric functions: sine, cosine, tangent, cosecant, secant, and cotangent. Each of these functions has its own unique properties and applications. But they are all interconnected through various identities and formulas.
- Sine (\( \sin \)) represents the ratio of the opposite side to the hypotenuse.
- Cosine (\( \cos \)) is the ratio of the adjacent side to the hypotenuse.
- Tangent (\( \tan \)) is the ratio of the sine of an angle to the cosine of that angle.
Sine Function
The sine function, noted as \( \sin \), is a periodic function with a wave-like pattern. It is important for its role in the unit circle. For any angle \( t \), \( \sin t \) gives the y-coordinate of the point where the terminal side of the angle intercepts the unit circle. A few key features of the sine function are:
- The function oscillates between -1 and 1.
- It has a period of \( 2\pi \), meaning it repeats every \( 2\pi \) radians.
- The sine function is an odd function, so \( \sin(-t) = -\sin t \).
Equivalence of Trigonometric Expressions
Determining whether two trigonometric expressions are equivalent is an important aspect of solving trigonometric problems. Two expressions are equivalent if they yield the same values for all permissible values of the variable.In the exercise, we investigated the supposed identity \( \sin(t + \pi) = \sin t \). By using the sine addition formula, we rewrote the left-hand side:
- \( \sin(t + \pi) = \sin t \cos \pi + \cos t \sin \pi \).
- Given \( \cos \pi = -1 \) and \( \sin \pi = 0 \), this simplifies to \( -\sin t \).
Other exercises in this chapter
Problem 57
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$\cot \alpha+\tan \alpha=\csc \alpha \sec \alpha$$
View solution Problem 58
Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places.
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Exer. \(57-62:\) Use an addition or subtraction formula to find the solutions of the equation that are in the Interval \([0, \pi)\) $$\cos 5 t \cos 3 t=\frac{1}
View solution Problem 58
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$\sin x+\cos x \cot x=\csc x$$
View solution