Problem 58
Question
Replace the Cartesian equations in Exercises \(49-62\) by equivalent polar equations. $$ x^{2}+x y+y^{2}=1 $$
Step-by-Step Solution
Verified Answer
The polar equation is \(r^2 = \frac{1}{1 + \cos\theta\sin\theta}\).
1Step 1: Understanding Cartesian Coordinates
The given equation is in Cartesian form: \(x^2 + xy + y^2 = 1\). Our task is to convert this equation into polar coordinates using the relationships between Cartesian and polar coordinates.
2Step 2: Define Polar Coordinate Relationships
In polar coordinates, any point in the plane can be represented as \((r, \theta)\) where \(x = r\cos\theta\) and \(y = r\sin\theta\). Additionally, \(r^2 = x^2 + y^2\). We'll use these to rewrite the given Cartesian equation.
3Step 3: Substitute Polar Relationships
Start by substituting \(x = r\cos\theta\) and \(y = r\sin\theta\) into the equation: \(x^2 + xy + y^2 = (r\cos\theta)^2 + (r\cos\theta)(r\sin\theta) + (r\sin\theta)^2 = 1\).
4Step 4: Simplify the Equation
Simplify the expression: \((r\cos\theta)^2 + (r^2 \cos\theta\sin\theta) + (r\sin\theta)^2\). This becomes \(r^2 \cos^2\theta + r^2 \cos\theta\sin\theta + r^2 \sin^2\theta\).
5Step 5: Factor and Use Identity
Notice that \(r^2 = r^2\cos^2\theta + r^2\sin^2\theta\) since this follows from the Pythagorean identity \(\cos^2\theta + \sin^2\theta = 1\). Factor \(r^2\) out: \(r^2(\cos^2\theta + \cos\theta\sin\theta + \sin^2\theta) = 1\).
6Step 6: Further Simplify
By observing the terms, \(\cos^2\theta + \sin^2\theta = 1\), so the expression simplifies to \(r^2 (1 + \cos\theta\sin\theta) = 1\).
7Step 7: Final Polar Equation
Since we have \(r^2 (1 + \cos\theta\sin\theta) = 1\), we rearrange it to get the polar equation: \(r^2 = \frac{1}{1 + \cos\theta\sin\theta}\).
Key Concepts
Convert Cartesian to PolarPolar CoordinatesTrigonometric Identities
Convert Cartesian to Polar
Converting a Cartesian equation into a polar equation involves using the relationship between the two coordinate systems. In Cartesian coordinates, points are defined by their horizontal and vertical distances, represented by \(x\) and \(y\). In polar coordinates, each point is defined by its distance from the origin, \(r\), and the angle, \(\theta\), from the positive \(x\)-axis. This relationship can be described with these conversions:
- \(x = r\cos\theta\)
- \(y = r\sin\theta\)
- \(r^2 = x^2 + y^2\)
Polar Coordinates
Polar coordinates are a useful alternative to Cartesian coordinates, especially when dealing with problems involving curves, circles, and angles. Instead of defining a point by \(x\) and \(y\) positions, polar coordinates make use of:
- \(r\) - the radial distance: the straight-line distance from the origin to the point.
- \(\theta\) - the angular coordinate: the angle measured in counterclockwise direction from the positive \(x\)-axis.
Trigonometric Identities
Trigonometric identities play a vital role in simplifying both Cartesian and polar equations. These identities are fundamental relationships involving trigonometric functions like sine and cosine. One of the most common and useful identities is the Pythagorean identity:
- \(\cos^2\theta + \sin^2\theta = 1\)
Other exercises in this chapter
Problem 57
Find the center, foci, vertices, asymptotes, and radius, as appropriate, of the conic sections in Exercises \(57-68 .\) $$ x^{2}+4 x+y^{2}=12 $$
View solution Problem 58
Find the center, foci, vertices, asymptotes, and radius, as appropriate, of the conic sections in Exercises \(57-68 .\) $$ 2 x^{2}+2 y^{2}-28 x+12 y+114=0 $$
View solution Problem 59
a. Find Cartesian equations for the curves \(r=4 \sin \theta\) and \(r=\sqrt{3} \sec \theta\) b. Sketch the curves together and label their points of intersecti
View solution Problem 59
Replace the Cartesian equations in Exercises \(49-62\) by equivalent polar equations. $$ x^{2}+(y-2)^{2}=4 $$
View solution