Problem 58
Question
Radiation treatment of prostate cancer. In many cases, prostate cancer is treated by implanting 60 to 100 small seeds of radioactive material into the tumor. The energy released from the decays kills the tumor. One isotope that is used (there are others is palladium \((103 \mathrm{Pd}),\) with a half-life of 17 days. If a typical grain contains 0.250 \(\mathrm{g}\) of \(^{103} \mathrm{Pd},\) (a) what is its initial activity rate in \(\mathrm{Bq},\) and (b) what is the rate 68 days later?
Step-by-Step Solution
Verified Answer
The initial activity is approximately 30,000 Bq, and after 68 days, it decreases to about 1,875 Bq.
1Step 1: Understand the Problem
The problem requires us to calculate the initial activity rate of a radioactive isotope \(^{103} \mathrm{Pd}\) and its activity rate after 68 days. The half-life of the isotope is given as 17 days, and the initial mass is 0.250 g. We need to use the radioactive decay formulas to solve this.
2Step 2: Formula for Activity Rate
The activity \( A \) of a radioactive sample is given by the formula:\[ A = \frac{\ln(2) \times N}{T_{1/2}} \]where \( N \) is the number of radioactive nuclei present and \( T_{1/2} \) is the half-life. The initial activity needs to be calculated using the initial mass.
3Step 3: Convert Mass to Number of Nuclei
We first need to calculate the number of nuclei \( N \) using the formula:\[ N = \frac{m \times N_A}{M} \]where:- \( m = 0.250 \text{ g} \) is the mass,- \( N_A = 6.022 \times 10^{23} \text{ nuclei/mol} \) is Avogadro's number,- \( M = 103 \text{ g/mol} \) is the molar mass of \(^{103} \mathrm{Pd}\).
4Step 4: Calculate Initial Activity
Substitute the values of \( N \), \( T_{1/2} = 17 \text{ days} \), and convert \( T_{1/2} \) to seconds \( T_{1/2} = 17 \times 86400 \text{ s} \) into the activity formula to find the initial activity \( A_0 \).
5Step 5: Determine Activity After 68 Days
The activity after a time \( t \) can be calculated using the formula:\[ A_t = A_0 \times \left( \frac{1}{2} \right)^{\left( \frac{t}{T_{1/2}} \right)} \]where \( t = 68 \text{ days} \). Substitute \( A_0 \) from the previous step and calculate \( A_t \).
6Step 6: Perform Calculations
Carry out the calculations from the previous steps:
1. Use the conversion from mass to nuclei.
2. Calculate initial activity using decimal places and high precision.
3. Calculate the activity after 68 days using the decay formula.
Ensure to handle units correctly and check calculations.
Key Concepts
Half-Life CalculationActivity RateRadiation TreatmentProstate Cancer Treatment
Half-Life Calculation
When it comes to radioactive decay, half-life is a critical concept. It is the time required for half the atoms in a radioactive substance to undergo decay. For the isotope palladium-103, used in treating prostate cancer, its half-life is 17 days. This means every 17 days, the amount of radioactive palladium will reduce to half its original amount from time zero.
To calculate how long it takes for half of a substance to decay, we employ the half-life formula. The formula for finding the remaining amount after a certain period is:
To calculate how long it takes for half of a substance to decay, we employ the half-life formula. The formula for finding the remaining amount after a certain period is:
- \[N_t = N_0 \times \left(\frac{1}{2}\right)^{\frac{t}{T_{1/2}}} \]
- \(N_t\) is the remaining quantity,
- \(N_0\) is the initial quantity,
- \(t\) is the time elapsed,
- \(T_{1/2}\) is the half-life.
Activity Rate
The activity rate of a radioactive substance tells us how many atomic disintegrations occur per second. It is typically measured in becquerels (Bq), where one Bq equals one disintegration per second. The formula to find the activity \(A\) is:
To find \(N\), you need to convert mass to the number of atomic nuclei using
- \[ A = \frac{\ln(2) \times N}{T_{1/2}} \]
To find \(N\), you need to convert mass to the number of atomic nuclei using
- \[ N = \frac{m \times N_A}{M} \]
Radiation Treatment
Radiation treatment is a medical procedure that utilizes radioactive isotopes to damage or kill cancer cells. It's particularly applicable in cases like prostate cancer, where radioactive seeds are implanted in the tumor. These seeds emit radiation that affects cancer cells more than healthy cells.
Understanding the precise activity of the isotope allows healthcare providers to predict the effect over time.
Understanding the precise activity of the isotope allows healthcare providers to predict the effect over time.
- They calculate the initial dose using physical calculations, ensuring just enough radiation to destroy the cancer cells while minimizing harm.
- The decay of radiation over its half-life signifies its ongoing effectiveness in destroying remaining cancerous tissue, adjusting treatment plans if necessary.
- The uniform decrease in radioactivity ensures a steady treatment pace, continually targeting cancer cells.
Prostate Cancer Treatment
Prostate cancer treatment often involves techniques tailoring specifically to the prostate's size and cancer stage. One advanced method involves radioactive seeds, such as palladium-103, being implanted into the prostate. These seeds continuously release low levels of radiation aimed directly at cancer cells, minimizing exposure to surrounding healthy tissue.
This technique offers several advantages, including:
This technique offers several advantages, including:
- Fewer side effects compared to external radiation therapy since the radiation is localized.
- Shorter treatment times; once the seeds are implanted, they continue working without frequent hospital visits.
- A more targeted approach, leading to improved outcomes by focusing directly on the tumor.
Other exercises in this chapter
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