Problem 58
Question
\(\int \frac{d x}{x^{2}+2 x+2}=\) (A) \(\ln \left(x^{2}+2 x+2\right)+C\) (B) \(\ln |x+1|+C\) (C) \(\arctan (x+1)+C\) (D) \(\frac{1}{\frac{1}{3} x^{3}+x^{2}+2 x}+C\)
Step-by-Step Solution
Verified Answer
The answer is (C) \( \arctan(x+1) + C \).
1Step 1: Recognize the Integral Form
Notice that the integral is in the form of \( \int \frac{d x}{x^{2}+bx+c} \), which is often solved by completing the square in the denominator.
2Step 2: Complete the Square
The quadratic expression \( x^2 + 2x + 2 \) can be rewritten by completing the square. Rewrite it as \( (x+1)^2 + 1 \) by adding and subtracting 1.
3Step 3: Identify the Integral Type
The integral \( \int \frac{dx}{(x+1)^2 + 1} \) is now in the standard form \( \int \frac{dx}{a^2 + u^2} \), which corresponds to \( \frac{1}{a}\arctan\left( \frac{u}{a} \right) + C \), where \( a=1 \) and \( u=x+1 \).
4Step 4: Integrate Using the Arctangent Formula
Using the formula \( \frac{1}{a} \arctan \left( \frac{u}{a} \right) + C \) for \( a=1 \) gives \( \arctan(x+1) + C \).
5Step 5: Match Solution to Answer Choices
Comparing the result \( \arctan(x+1) + C \) with the options provided, we find that it matches choice (C).
Key Concepts
Completing the SquareArctangent IntegrationQuadratic Expressions
Completing the Square
Completing the square is a method used in mathematics to transform a quadratic expression into a perfect square trinomial plus or minus a constant. This technique is particularly useful when dealing with quadratic expressions like \(x^2 + bx + c\). By rewriting the expression in the form of a square, we can simplify the integration process. For example, take the quadratic \(x^2 + 2x + 2\).
This process converts the original expression into a more manageable form for integration, highlighting the structure needed to apply arctangent integration.
- First, focus on the linear and quadratic terms: \(x^2 + 2x\).
- Find the number that completes the square: \(\left(\frac{2}{2}\right)^2 = 1\).
- Add and subtract this number inside the integral: \(x^2 + 2x + 1 - 1 + 2\).
- Rearrange to get a perfect square: \( (x+1)^2 + 1\).
This process converts the original expression into a more manageable form for integration, highlighting the structure needed to apply arctangent integration.
Arctangent Integration
Arctangent integration is an integral formula for functions in the form \(\int \frac{dx}{a^2 + u^2}\). This important technique allows us to tackle integrals that involve expressions resembling a squared variable plus a constant. It results in an arctangent function, written as:
- \[\frac{1}{a}\arctan\left(\frac{u}{a}\right) + C\]
- Substitute into the formula: \[\arctan(x+1) + C\]
Quadratic Expressions
Quadratic expressions are polynomials of degree two, fitting the general form \(ax^2 + bx + c\). Understanding these expressions is critical to various calculus operations. They often appear in integrations and require certain techniques for simplification, such as completing the square.
- Key components include the quadratic term \(ax^2\), the linear term \(bx\), and the constant \(c\).
- In calculus, transforming these into squares of binomials opens the door to further manipulation like integration.
Other exercises in this chapter
Problem 56
\(\int \frac{d v}{v \ln v}=\) (A) \(\frac{1}{\ln v^{2}}+C\) (B) \(-\frac{1}{\ln ^{2} v+C}\) (C) \(-\ln |\ln v|+C\) (D) \(\ln |\ln v|+C\)
View solution Problem 57
\(\int \frac{y-1}{y+1} d y=\) (A) \(y-2 \ln |y+1|+C\) (B) \(1-\frac{2}{y+1}+C\) (C) \(\ln \frac{|y|}{(y+1)^{2}}+C\) (D) \(1-2 \ln |y+1|+C\)
View solution Problem 59
\(\int \sqrt{x}(\sqrt{x}-1) d x=\) (A) \(2\left(x^{3 / 2}-x\right)+C\) (B) \(\frac{x^{2}}{2}-x+C\) (C) \(\frac{1}{2}(\sqrt{x}-1)^{2}+C\) (D) \(\frac{1}{2} x^{2}
View solution Problem 60
\(\int e^{\theta} \cos \theta d \theta=\) (A) \(e^{\theta}(\cos \theta-\sin \theta)+C\) (B) \(\frac{1}{2} e^{\theta}(\sin \theta+\cos \theta)+C\) (C) \(2 e^{\th
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