Problem 58
Question
How do we know that the graph of \(y=-4 x\) is a straight line that contains the origin?
Step-by-Step Solution
Verified Answer
The graph is a straight line with slope -4, and it contains the origin because the y-intercept is 0.
1Step 1: Identify the equation format
The given equation is \(y = -4x\). This is a linear equation in the slope-intercept form, \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
2Step 2: Determine the slope and y-intercept
From the equation \(y = -4x\), we identify that the slope \(m = -4\) and the y-intercept \(b = 0\). This means the graph of the equation will be a line with a slope of \(-4\) and it crosses the y-axis at the origin (0,0).
3Step 3: Reason why the graph passes through the origin
The y-intercept \(b = 0\) indicates the point where the line crosses the y-axis. Since \(b = 0\), the line passes through the origin (0,0).
4Step 4: Verify with a point calculation
To confirm that the line contains the origin, substitute \(x = 0\) into the equation: \(y = -4(0) = 0\). This confirms that the point (0,0) lies on the line, meaning the graph indeed passes through the origin.
5Step 5: Visualize the line
A linear equation like \(y = -4x\) always results in a straight line. The equation has no additional powers of \(x\), which confirms that the graph of this equation is a straight line.
Key Concepts
Slope-Intercept FormGraphing Linear EquationsY-Intercept
Slope-Intercept Form
The slope-intercept form is a way to describe a straight line using an easy-to-understand equation. It's written as \(y = mx + b\). Here, \(m\) represents the slope of the line and \(b\) represents the y-intercept. This form helps us quickly recognize key characteristics of a line just by looking at the equation.
- Slope \((m)\): Indicates how steep the line is. A positive slope means the line goes upwards as you move from left to right, while a negative slope, like \(-4\), means the line goes downwards.
- Y-intercept \((b)\): Points to the spot where the line crosses the y-axis. In our exercise, \(b = 0\), indicating the line passes through the origin.
Graphing Linear Equations
Graphing linear equations involves plotting points on a coordinate plane that satisfy the equation. This process, for the given equation \(y = -4x\), allows us to see the straight line visually. Here's how we can map it out:
- Start with the y-intercept: Since the y-intercept \(b = 0\), the line passes through the origin, (0, 0).
- Use the slope: The slope, \(-4\), shows for each unit increase in \(x\), \(y\) decreases by 4 units. If you move 1 unit to the right on the x-axis, you move down 4 units on the y-axis.
- Plot more points: From the origin, go straight down 4 units while moving right 1 unit, and plot the next point.
- Draw the line: Connect the points you've mapped out, and extend the line to fill the graph.
Y-Intercept
The y-intercept is an important concept in graphing because it's the point at which a line crosses the y-axis. In slope-intercept form \(y = mx + b\), the y-intercept is represented by \(b\). For the equation \(y = -4x\), the y-intercept is 0.
This means the graph crosses the y-axis at the origin, (0, 0). The y-intercept provides a starting point for graphing the line.
This means the graph crosses the y-axis at the origin, (0, 0). The y-intercept provides a starting point for graphing the line.
- If \(b > 0\), the line would cross the y-axis above the origin.
- If \(b < 0\), the line crosses below the origin.
- When \(b = 0\), as in our example, the line crosses the y-axis exactly at the origin.
Other exercises in this chapter
Problem 58
Write the equation of the line that satisfies the given conditions. Express final equations in standard form. Contains the point \((-2,-3)\) and is perpendicula
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Contains the point \((-2,-3)\) and is perpendicular to the line \(x+4 y=6\)
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Find the coordinates of two points on the given line, and then use those coordinates to find the slope of the line. $$y=3$$
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Write the equation of the line that satisfies the given conditions. Express final equations in standard form. Contains the origin and is perpendicular to the li
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