Problem 58
Question
Graph the plane whose equation is given. $$ 3 x-y-6=0 $$
Step-by-Step Solution
Verified Answer
Plot points (0,-6) and (1,-3) from the equation \( y = 3x - 6 \) and draw the line.
1Step 1: Rewrite the Plane Equation in Slope-Intercept Form
To graph the plane, we first rewrite the given equation in slope-intercept form, which is \( y = mx + b \). Start by isolating \( y \) on one side of the equation.\[3x - y - 6 = 0\]Add \( y \) and 6 to both sides:\[-y = -3x + 6\] Finally, multiply every term by -1 to solve for \( y \):\[ y = 3x - 6 \] This form tells us that the plane intersects the y-axis at \( -6 \) and has a slope \( m = 3 \).
2Step 2: Determine the Y-Intercept
The y-intercept is the point where the plane crosses the y-axis. From the equation \( y = 3x - 6 \), we see that the intercept is at \( (0, -6) \).This is the point where we will begin plotting the line on the graph.
3Step 3: Use the Slope to Find Another Point
The slope of the line is \( 3 \), which means that for every unit increase in \( x \), \( y \) increases by 3 units. Starting from the y-intercept at \( (0, -6) \), move 1 unit to the right and 3 units up to find another point on the graph.This gives us the point \( (1, -3) \).
4Step 4: Plot the Points and Draw the Line
Plot the points \( (0, -6) \) and \( (1, -3) \) on the graph. Once these points are plotted, draw a straight line through them, extending it in both directions, which represents the graph of the plane \( 3x - y - 6 = 0 \).
5Step 5: Verify by Checking a Point on the Plane
To ensure accuracy, substitute a point from the line (other than the intercepts) back into the original equation to check if it satisfies the equation.For example, using \( (2, 0) \):\[3(2) - 0 - 6 = 0\]This simplifies to \(6 - 6 = 0\), which holds true, confirming the accuracy of our graph.
Key Concepts
Slope-Intercept FormY-InterceptSlope of a LineChecking Solutions
Slope-Intercept Form
The slope-intercept form of a linear equation is a way to quickly identify the slope and the y-intercept of a line. This form is expressed as \( y = mx + b \), where \( m \) represents the slope and \( b \) is the y-intercept.
This makes it easier to graph a line because it gives you all the information you need right from the equation.To convert an equation to this form, you isolate \( y \) on one side of the equation. Consider the equation from our exercise, \( 3x - y - 6 = 0 \):
This makes it easier to graph a line because it gives you all the information you need right from the equation.To convert an equation to this form, you isolate \( y \) on one side of the equation. Consider the equation from our exercise, \( 3x - y - 6 = 0 \):
- First, move the \( y \) and constant to one side: \( -y = -3x + 6 \).
- Next, multiply every term by \(-1\) to get \( y = 3x - 6 \).
Y-Intercept
The y-intercept of a line is the point where the line crosses the y-axis. It occurs when \( x = 0 \). From the slope-intercept form \( y = mx + b \), the \( b \) value represents this intercept.
In the exercise, the equation is \( y = 3x - 6 \) which means:
Simply locate \( -6 \) on the y-axis and place a point there. This is the position where the line will meet the axis.
In the exercise, the equation is \( y = 3x - 6 \) which means:
- When \( x = 0 \), \( y = -6 \).
Simply locate \( -6 \) on the y-axis and place a point there. This is the position where the line will meet the axis.
Slope of a Line
The slope of a line is a measure of its steepness and direction. In the equation \( y = mx + b \), \( m \) is the slope. The slope tells you how much \( y \) changes for a unit change in \( x \).
A positive slope increases upwards as you move to the right, while a negative slope decreases. In the exercise, the equation is \( y = 3x - 6 \) with slope \( m = 3 \):
This lands on another point, \( (1, -3) \). These outstretched steps form the line on the graph.
A positive slope increases upwards as you move to the right, while a negative slope decreases. In the exercise, the equation is \( y = 3x - 6 \) with slope \( m = 3 \):
- This means for a change of 1 in \( x \), \( y \) increases by 3.
This lands on another point, \( (1, -3) \). These outstretched steps form the line on the graph.
Checking Solutions
Verifying your graph can be done by plugging a specific point from the line back into the original equation to see if it satisfies that equation.
This step ensures that you haven't made any errors in plotting.In the exercise, after plotting points like \( (0, -6) \) and \( (1, -3) \), you might choose another point, such as \( (2, 0) \), to verify:
This step ensures that you haven't made any errors in plotting.In the exercise, after plotting points like \( (0, -6) \) and \( (1, -3) \), you might choose another point, such as \( (2, 0) \), to verify:
- Substitute \( x = 2 \), \( y = 0 \) into the original equation \( 3x - y - 6 = 0 \).
- You get \( 3(2) - 0 - 6 = 0 \) which simplifies to \( 6 - 6 = 0 \).
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