Problem 58
Question
For the following problems, simplify each of the algebraic expressions. $$ (a+5) 4+6 a-20 $$
Step-by-Step Solution
Verified Answer
Question: Simplify the algebraic expression: (a + 5)4 + 6a - 20
Answer: 10a
1Step 1: Distribute the 4 to both terms within the parentheses
Distribute the 4 to both (a) and (5) in the expression:
\((a+5) 4 = 4a + 20\)
The updated expression becomes:
$$
4a + 20 + 6a - 20
$$
2Step 2: Combine like terms
Combine the terms with 'a' and the constant terms:
$$
(4a + 6a) + (20 - 20)
$$
4a + 6a equals 10a, and 20 - 20 equals 0. So, the simplified expression is:
$$
10a + 0
$$
However, we can simplify it further as the "+0" has no effect on the value of the expression.
3Step 3: Final Simplified Expression
The final simplified expression is:
$$
10a
$$
Key Concepts
SimplificationDistributive PropertyLike TermsConstants
Simplification
Simplification is the process of reducing an algebraic expression to its simplest form. In this exercise, we began with the expression \((a+5) 4 + 6a - 20\). The goal was to simplify it into a form that is easier to manage.
Simplification often involves a few key steps:
Simplification often involves a few key steps:
- Applying mathematical properties like the distributive property
- Combining like terms
- Reducing any unnecessary constants or excess terms
Distributive Property
The distributive property is a fundamental algebraic tool that helps in simplifying expressions. It states that multiplying a sum by a number gives the same result as multiplying each addend individually by the number and then adding the products.
In our exercise, we applied the distributive property to the expression \((a+5) 4\). This means we distributed the 4 across both terms inside the parentheses.
In our exercise, we applied the distributive property to the expression \((a+5) 4\). This means we distributed the 4 across both terms inside the parentheses.
- First multiply \(4\) by \(a\), resulting in \(4a\).
- Then multiply \(4\) by \(5\), resulting in \(20\).
Like Terms
Like terms are terms that have the same variable and can be combined. In algebra, combining like terms is a fundamental skill for simplifying expressions.
For the initial expression \(4a + 20 + 6a - 20\), the like terms are those with the variable 'a' and the constant terms.
For the initial expression \(4a + 20 + 6a - 20\), the like terms are those with the variable 'a' and the constant terms.
- 4a and 6a: Both have the variable 'a'. They are combined to make \(10a\).
- 20 and -20: These are plain numbers (constants) and when summed, result in \(0\).
Constants
Constants are numbers that stand alone in an expression and do not change; they do not contain any variables. They are the numerical counterpart in an equation, representing fixed values.
In our exercise, the constants were \(20\) and \(-20\). These appeared as part of the expression \(4a + 20 + 6a - 20\).
In our exercise, the constants were \(20\) and \(-20\). These appeared as part of the expression \(4a + 20 + 6a - 20\).
- When constants are added or subtracted, their values are simplified as part of the overall simplification process.
- In this instance, the addition of 20 and subtraction of 20 results in \(0\).
Other exercises in this chapter
Problem 57
Simplify the algebraic expressions for the following problems. $$ 3 m\left[5+2 m\left(m+6 m^{2}\right)\right]+m\left(m^{2}+4 m+1\right) $$
View solution Problem 57
For the following problems, find the products. $$ (2 a-7 b)(2 a+7 b) $$
View solution Problem 58
Is every polynomial expression an algebraic expression? If not, give an example of a polynomial expression that is not an algebraic expression.
View solution Problem 58
Simplify \(-|-8|\)
View solution