Problem 58
Question
Find the x-intercepts of the graph of the equation. $$y=x^{2}+7 x-2$$
Step-by-Step Solution
Verified Answer
The x-intercepts of the graph of the equation \(y=x^{2}+7 x-2\) are \(x = \frac{-7 + \sqrt{57}}{2}\) and \(x = \frac{-7 - \sqrt{57}}{2}\)
1Step 1: Setting the Equation to Zero
To find the x-intercepts, set the equation equal to zero: \(0 = x^{2} +7x -2\). This is because x-intercepts are the x-coordinates where the graph of a function intersects the x-axis, at which point \(y = 0\).
2Step 2: Identify the coefficients of the quadratic equation
A general quadratic equation is given as \(ax^2 + bx + c = 0\). In this equation, \(a = 1\), \(b = 7\) and \(c = -2\).
3Step 3: Apply the Quadratic Formula
Applying the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), substitute the identified values from Step 2. This gives \(x = \frac{-7 \pm \sqrt{7^2 - 4*1*(-2)}}{2*1}\). Simplify under the square root sign to obtain \(x = \frac{-7 \pm \sqrt{49 + 8}}{2}\).
4Step 4: Final Calculation
Perform the final calculations to get the two solutions for \(x\): \(x = \frac{-7 \pm \sqrt{57}}{2}\). Therefore, the 2 solutions or x intercepts of the equation are \(x = \frac{-7 + \sqrt{57}}{2}\) and \(x = \frac{-7 - \sqrt{57}}{2}\).
Key Concepts
Quadratic EquationQuadratic FormulaGraphing
Quadratic Equation
When dealing with quadratic equations, you are essentially working with equations of the form \(ax^2 + bx + c = 0\). A quadratic equation is distinguished by the "squared" term, in this case, \(x^2\), and is a fundamental concept in algebra.
These types of equations often represent parabolas when plotted on a graph. The parabolic curve will intersect the x-axis at points called x-intercepts. Identifying these intercepts involves setting the quadratic equation equal to zero. This action determines the values of \(x\) where the curve touches the x-axis, hence making \(y = 0\).
In our exercise, the equation \(x^2 + 7x - 2\) is set to zero to find the x-intercepts. By this method, we transition from an expression for \(y\), which describes a parabola, to focusing on just \(x\) values where the graph crosses the x-axis.
These types of equations often represent parabolas when plotted on a graph. The parabolic curve will intersect the x-axis at points called x-intercepts. Identifying these intercepts involves setting the quadratic equation equal to zero. This action determines the values of \(x\) where the curve touches the x-axis, hence making \(y = 0\).
In our exercise, the equation \(x^2 + 7x - 2\) is set to zero to find the x-intercepts. By this method, we transition from an expression for \(y\), which describes a parabola, to focusing on just \(x\) values where the graph crosses the x-axis.
Quadratic Formula
The quadratic formula is a critical tool for solving quadratic equations. It provides a straightforward way to find solutions for \(x\) in any equation of the form \(ax^2 + bx + c = 0\). The formula is written as:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Understanding this formula begins with recognizing the symbols involved:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Understanding this formula begins with recognizing the symbols involved:
- "\(b\)" and "\(c\)" are coefficients from the quadratic equation.
- The "\(\pm\)" symbol indicates there will usually be two solutions: one with addition and one with subtraction.
- The part under the square root, "\(b^2 - 4ac\)," is known as the discriminant and determines the number and nature of the solutions.
Graphing
Graphing involves visually representing the solutions of equations, such as quadratic equations, on a coordinate system. For quadratic equations, graphing helps us understand the shape of the parabola, its vertex, direction of opening, and importantly, the x-intercepts.
Parabolas can open upwards or downwards based on the sign of the coefficient \(a\). If \(a > 0\), the parabola opens upwards; if \(a < 0\), it opens downwards. In our scenario with \(y = x^2 + 7x - 2\), since \(a = 1\), it opens upwards.
The x-intercepts, which we found using the quadratic formula, mark the touching points of the graph on the x-axis, at \( \frac{-7 + \sqrt{57}}{2} \) and \( \frac{-7 - \sqrt{57}}{2} \). These reflect the solutions where \(y = 0\). Seeing these on a graph provides insight into the equation's behavior, illustrating both the parabola's tangible intersection points and the symmetry around its vertex.
Parabolas can open upwards or downwards based on the sign of the coefficient \(a\). If \(a > 0\), the parabola opens upwards; if \(a < 0\), it opens downwards. In our scenario with \(y = x^2 + 7x - 2\), since \(a = 1\), it opens upwards.
The x-intercepts, which we found using the quadratic formula, mark the touching points of the graph on the x-axis, at \( \frac{-7 + \sqrt{57}}{2} \) and \( \frac{-7 - \sqrt{57}}{2} \). These reflect the solutions where \(y = 0\). Seeing these on a graph provides insight into the equation's behavior, illustrating both the parabola's tangible intersection points and the symmetry around its vertex.
Other exercises in this chapter
Problem 57
SKETCHING GRAPHS Sketch the graph of the function. Label the vertex. $$ y=-3 x^{2}-2 x-1 $$
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Solve the equation or write no solution. Write the solutions as integers if possible. Otherwise write them as radical expressions. $$x^{2}=0$$
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Sketch the graph of the exponential equation. $$y=\frac{1}{2}(2)^{x}$$
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Which is the simplified form of \(4 \frac{\sqrt{125}}{\sqrt{25}} ?\) (A) \(2 \sqrt{5}\) (B) \(4 \sqrt{5}\) (C) \(20 \sqrt{5}\) (D) \(\frac{4 \sqrt{5}}{5}\)
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