Problem 58
Question
Find the product \(z_{1} z_{2}\) and the quotient \(z_{1} / z_{2}\). Express your answer in polar form. $$z_{1}=\sqrt{2}\left(\cos 75^{\circ}+i \sin 75^{\circ}\right)$$ $$z_{2}=3 \sqrt{2}\left(\cos 60^{\circ}+i \sin 60^{\circ}\right)$$
Step-by-Step Solution
Verified Answer
Product: \( 6 (\cos 135^\circ + i \sin 135^\circ) \), Quotient: \( \frac{1}{3} (\cos 15^\circ + i \sin 15^\circ) \)."
1Step 1: Identify the Moduli
The modulus of a complex number in polar form \( z = r (\cos \theta + i \sin \theta) \) is \( r \). Therefore, the modulus for \( z_1 \) is \( \sqrt{2} \) and for \( z_2 \) is \( 3\sqrt{2} \).
2Step 2: Determine the Argument of Product
To find the argument of the product \( z_1 z_2 \), add the angles (arguments) of each complex number: \( 75^\circ + 60^\circ = 135^\circ \).
3Step 3: Compute the Modulus of the Product
Multiply the moduli of \( z_1 \) and \( z_2 \). The modulus of the product is \( \sqrt{2} \times 3\sqrt{2} = 3 \times 2 = 6 \).
4Step 4: Formulate the Product in Polar Form
Combine the modulus and argument of the product to express it in polar form: \( 6 (\cos 135^\circ + i \sin 135^\circ) \).
5Step 5: Determine the Argument of the Quotient
For the argument of the quotient \( z_1 / z_2 \), subtract the arguments: \( 75^\circ - 60^\circ = 15^\circ \).
6Step 6: Compute the Modulus of the Quotient
Divide the moduli to find the modulus of the quotient: \( \frac{\sqrt{2}}{3\sqrt{2}} = \frac{1}{3} \).
7Step 7: Formulate the Quotient in Polar Form
Combine the modulus and argument of the quotient to get \( \frac{1}{3} (\cos 15^\circ + i \sin 15^\circ) \).
Key Concepts
Polar FormModulusArgumentProduct and Quotient of Complex Numbers
Polar Form
The polar form of a complex number is a way to express the number in terms of its magnitude (modulus) and direction (argument). To transform a complex number from its rectangular form \( a + bi \) into polar form, we use the expression \( z = r(\cos \theta + i \sin \theta) \). Here, \( r \) is the modulus of the complex number, and \( \theta \) is the argument. This form is particularly useful for multiplying and dividing complex numbers, as it simplifies the operations to simple arithmetic with the modulus and the addition or subtraction of angles.
- Magnitude is represented as the modulus \( r \).
- Direction is shown using the argument \( \theta \).
- Expresses complex numbers as \( r(\cos \theta + i \sin \theta) \), also written as \( r \text{cis} \theta \) for short.
Modulus
The modulus of a complex number is essentially its distance from the origin on the complex plane. For a complex number written as \( z = a + bi \), the modulus \( r \) is the square root of the sum of the squares of its real part \( a \) and imaginary part \( b \). In mathematical terms, this is represented as \( r = \sqrt{a^2 + b^2} \).
- The modulus is always a non-negative real number.
- It represents the magnitude of the complex number.
- In polar form, it is the value \( r \) in \( r(\cos \theta + i \sin \theta) \).
Argument
The argument of a complex number is the angle the complex number makes with the positive real axis on the complex plane. For a complex number \( z = a + bi \), the argument \( \theta \) is found using the inverse tangent function: \( \theta = \tan^{-1} \left( \frac{b}{a} \right) \).
- Angles are often measured in degrees or radians.
- It shows the direction of the complex number in the complex plane.
- In polar form, it is written as \( \theta \) in \( r(\cos \theta + i \sin \theta) \).
Product and Quotient of Complex Numbers
Working with complex numbers in polar form simplifies finding their product and quotient. The rules are quite straightforward thanks to the nature of polar coordinates. Let's break it down:
- Product: To find the product of two complex numbers, multiply the moduli and add the arguments: \( r_1 \times r_2 \) and \( \theta_1 + \theta_2 \).
- Quotient: For the quotient, divide the moduli and subtract the arguments: \( \frac{r_1}{r_2} \) and \( \theta_1 - \theta_2 \).
- The operation results are expressed back in polar form, which is \( r(\cos \theta + i \sin \theta) \).
Other exercises in this chapter
Problem 57
Show that the graph of \(r=a \cos \theta+b \sin \theta\) is a circle, and find its center and radius.
View solution Problem 57
Convert the polar equation to rectangular coordinates. $$r=1+\cos \theta$$
View solution Problem 58
(a) Graph the polar equation \(r=\tan \theta \sec \theta\) in the viewing rectangle \([-3,3]\) by \([-1,9]\) (b) Note that your graph in part (a) looks like a p
View solution Problem 58
Convert the polar equation to rectangular coordinates. $$r=3(1-\sin \theta)$$
View solution