Problem 58
Question
Find the indicated term of each arithmetic sequence. \(a_{21}\) for \(121,118,115, \ldots\)
Step-by-Step Solution
Verified Answer
The 21st term, \(a_{21}\), is 61.
1Step 1: Identify the First Term and Common Difference
The first term of the sequence is \(a_1 = 121\). The common difference \(d\) is found by subtracting the second term from the first term: \(118 - 121 = -3\). Thus, \(d = -3\).
2Step 2: Use the Formula for the n-th Term of an Arithmetic Sequence
The formula to find the n-th term of an arithmetic sequence is given by \(a_n = a_1 + (n-1) \cdot d\). Here, we need to find \(a_{21}\), so we will substitute the known values into this formula.
3Step 3: Substitute Values into the Formula
We need to find \(a_{21}\). Using the formula \(a_n = a_1 + (n-1) \cdot d\), substitute \(a_1 = 121\), \(d = -3\), and \(n = 21\). This gives us: \[ a_{21} = 121 + (21-1) \cdot (-3) \]
4Step 4: Simplify the Expression
First, calculate \(21-1\) which is \(20\). Then multiply \(20\) by the common difference \(-3\), resulting in \(20 \cdot (-3) = -60\). Substitute this back into the expression: \[ a_{21} = 121 - 60 \]
5Step 5: Calculate the Final Result
Perform the subtraction \(121 - 60\) to find the 21st term. Thus, \(a_{21} = 61\).
Key Concepts
Common DifferenceFirst Termn-th Term Formula
Common Difference
In an arithmetic sequence, the common difference represents the consistent interval that separates consecutive terms in the sequence. To determine this value, subtract any term from the subsequent term in the sequence.
For example, in sequence 121, 118, 115, and so forth, the common difference is calculated as 118 - 121, resulting in -3.
Key points about the common difference include:
For example, in sequence 121, 118, 115, and so forth, the common difference is calculated as 118 - 121, resulting in -3.
Key points about the common difference include:
- If the difference is positive, the sequence will increase with each term.
- If negative, as in our example -3, the sequence will decrease.
- A common difference of 0 results in a sequence where all terms are identical.
First Term
The first term of an arithmetic sequence is the point from which all calculations start. It's the initial member of the sequence, frequently denoted as \(a_1\).
In our sequence of 121, 118, 115, etc., the first term \(a_1\) is 121.
Understanding the first term is crucial because it acts like the anchor for the rest of the sequence. Without it, determining other terms using the formula is impossible.
In arithmetic sequences:
In our sequence of 121, 118, 115, etc., the first term \(a_1\) is 121.
Understanding the first term is crucial because it acts like the anchor for the rest of the sequence. Without it, determining other terms using the formula is impossible.
In arithmetic sequences:
- This term is necessary to identify the entire sequence.
- It provides the starting value from which all subsequent terms are derived using the common difference.
n-th Term Formula
The n-th term formula in an arithmetic sequence allows you to find any specified term without listing all preceding terms. It's given by \(a_n = a_1 + (n-1) \cdot d\), where:
Overall, this formula is a powerful tool in arithmetic sequences, minimizing manual effort and swiftly obtaining outcomes.
- \(a_n\) is the term you aim to find.
- \(a_1\) is the first term.
- \(n\) represents the term number.
- \(d\) is the common difference between terms.
Overall, this formula is a powerful tool in arithmetic sequences, minimizing manual effort and swiftly obtaining outcomes.
Other exercises in this chapter
Problem 58
Find \(S_{n}\) for each geometric series described. \(a_{1}=72, r=\frac{1}{3}, n=7\)
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Use a graphing calculator to find the sum of each geometric series. $$ \sum_{n=1}^{13} 6\left(\frac{1}{3}\right)^{n-1} $$
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State whether each statement is true or false when \(n=1\). Explain. $$ 1=\frac{n^{2}(n+1)^{2}}{4} $$
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A vacuum pump removes 20% of the air from a container with each stroke of its piston. What percent of the original air remains after five strokes?
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